My object is not showing when show() method call

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hi everyone
i am using a piece of code as under

the object of the form1 class/form doesn't appears please help to display it within the time_elapsed body

What I have tried:

void MainWindow_Loaded(object sender, RoutedEventArgs e)
{

timer = new Timer();
timer.Interval = 1000;
timer.Elapsed += timer_Elapsed;

timer.Start();
}
void timer_Elapsed(object sender, ElapsedEventArgs e)
{
form1 object = new form1();
object.Show()

}

Posted 15-Sep-16 2:43am

Faiiziii Awan

Updated 15-Sep-16 3:11am

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BillWoodruff 15-Sep-16 9:37am

Create the instance of the Form outside the call to Timer_Elapsed.

johannesnestler 15-Sep-16 10:13am

post your real code - then we see further -this doesn't compile. With that kind of accuracy at work you do better something else then programming...

Philippe Mori 15-Sep-16 12:17pm

Obviously, if the form is not shown (multiple times), then something else must be wrong in your code...

2 solutions

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OriginalGriff · Answer 1 · 2016-09-15T02:55:00

That's a silly thing to do, even if your code compiled - which it won't. It's missing a semicolon, and you can't call a variable object for the same reasons you can't call it float or string.
So the chances are that if you fix them, it'll work - it does for me - and it doesn't seem to work for you because it doesn't compile so the "running version" doesn't have that code in it.

    System.Timers.Timer timer = new System.Timers.Timer();
    timer.Interval = 1000;
    timer.Elapsed += timer_Elapsed;
    timer.Start();
    }
void timer_Elapsed(object sender, System.Timers.ElapsedEventArgs e)
    {
    Form1 f1 = new Form1();
    f1.Show();
    }

But that's not nice - it'll open a new form every second ... which will fill the screen pretty quickly.

buffedcheesy · Answer 2 · 2016-09-15T03:11:00

Solution 2

try this:

C#

void MainWindow_Loaded(object sender, RoutedEventArgs e)
{

timer = new Timer();
timer.Interval = 1000;
timer.Elapsed += timer_Elapsed;

timer.Start();
}
void timer_Elapsed(object sender, ElapsedEventArgs e)
{
form1 f1 = new form1();
f1.Show();
timer.Stop();
}

You shouldn't use "object" as a name for an object, because object is a reserved type and of course you'd better stop the timer after created the new instance of form1.

You further should know that this is not the "professional" way of doing anything.

Posted 15-Sep-16 3:11am

buffedcheesy

Comments

Faiiziii Awan 15-Sep-16 9:30am

thanks buffedcheesy
but i have already try this nut now work.
as form1 obj = new form(); creates the object suddenly object goes kill.i already tired stop timer first then creates object etc etc but all does nothing

buffedcheesy 15-Sep-16 9:44am

Which environment are you working with?
Usually the standard name is "Form1" (upper case) not "form1", this is confusing me a bit. The order of commands in the event handler doesn't matter in this case.

I Try to follow you but i don't know how far you are.