See here:
Preprocessor directives - C++ Tutorials[
^] = search for "##" and you get:
Function macro definitions accept two special operators (# and ##) in the replacement sequence:
The operator #, followed by a parameter name, is replaced by a string literal that contains the argument passed (as if enclosed between double quotes):
#define str(x) #x
cout << str(test);
This would be translated into:
cout << "test";
The operator ## concatenates two arguments leaving no blank spaces between them:
#define glue(a,b) a ## b
glue(c,out) << "test";
This would also be translated into:
cout << "test";
I like the honesty though! :laugh:
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