Output Is Not As Expected When I Try Calling Shell Script From C Code

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I have a shell script it gets the files from another server

C++

int main()
    {
     char y[18];
    // copying the value into y
    strcpy(y,"123456789.111"); 
    
    // calling the shell script
    system("/home/sandy/sftp2.sh y"); 
    return 0;
    
    } //end of main

Here i need to get all the files that starts 123456789.111 . I am new to this please help to resolve this.

Posted 1-Oct-15 0:01am

Member 11900955

Updated 1-Oct-15 0:21am

Naveen.Sanagasetti

v3

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chandanadhikari 1-Oct-15 6:13am

what output do you get ... please elaborate more about what error message you are getting.

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CPallini · Answer 1 · 2015-10-01T00:14:00

Quote:
system("/home/sandy/sftp2.sh y");

The above line passes the letter 'y' as argument to the script while you probably want to pass the y variable value, namely the "123456789.111" string.

However, I wonder why don't you write directly

C

system("/home/sandy/sftp2.sh 123456789.111");

?