Images from current directory are not being shown

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I am trying to show all images from my current directory using php script. the php file which is showing image also is in the same directory. here is the script

PHP

<?php 
$dir =basename(__DIR__);
if (file_exists($dir) == false) 
{  
echo 'Directory \''. $dir. '\' not found!'; 
}
else{
$dir_contents = scandir($dir);  
foreach ($dir_contents as $file) 
 {     
 $file_type = strtolower(end(explode('.', $file)));    


if ($file !== '.' && $file !== '..' && in_array($file_type, $file_display) == true)
 {          
echo '<img src="'.$dir. '/'.$file. '" alt="'.$file. '" />';     }    }  }   
 ?>

the output says the no directory exists. but i have seen the directory exists. please tell me whats wrong with my code Thanks

Posted 19-Aug-15 7:30am

saifullahiit

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Comments

Zoltán Zörgő 19-Aug-15 13:56pm

What is your PHP version?
Are you sure you need basename there?

__DIR__ should equal to dirname(__FILE__) and that is your scripts folder. But whí don't you print it to debug?

saifullahiit 19-Aug-15 14:24pm

i have optimized my code:
$files = glob(__DIR__.DIRECTORY_SEPARATOR.'*.jpg');
echo $files;
foreach ($files as $file) {
if (!is_file($file)) { // if isn't file, skip it

continue;

}

$info = pathinfo($file);
// check if allowed extensions
if (in_array(strtolower($info['extension']), array('jpg', 'png', 'gif'))) {
echo '<img src="'.$file. '" alt="'.$file. '" />'; // your image echo
}
}
but here images are broken. you can check the link.

Zoltán Zörgő 19-Aug-15 14:31pm

Are you running this script from command line or over a web server? If you are using a web server you have to consider that the web url will be different from the OS level path.

saifullahiit 19-Aug-15 14:39pm

can you please tell me how to show images from the current directory

2 solutions

Solution 2

Here you have it:

PHP

<?php

$urlbase = dirname($_SERVER["SCRIPT_NAME"]);
$ext = array("jpg", "gif", "png");

if ($handle = opendir(__DIR__)) {

    while (false !== ($entry = readdir($handle))) {
        $path_parts = pathinfo($entry);
        if(in_array($path_parts["extension"], $ext)){
            echo "<img src='$urlbase/{$path_parts["basename"]}' alt='$entry' /><br/>";
        }
    }
}

Posted 19-Aug-15 10:16am

Zoltán Zörgő

Updated 19-Aug-15 10:18am

v2

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saifullahiit · Accepted Answer · 2015-08-19T08:40:00

Solution 1

PHP

<?php
$format = '<img src="[FILE]"> [FILE]<br>';

chdir(dirname(__FILE__));

$files = glob("*.{jpeg,jpg,png,gif}", GLOB_BRACE);

foreach ($files as $file) {
    if (is_file($file)) {
        echo str_replace('[FILE]', htmlspecialchars($file), $format);
    }
}
?>

Posted 19-Aug-15 8:40am

saifullahiit