How To Use 'Like' Operator In Reverse?

Question

1.00/5 (1 vote)

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SQL-Server-2008R2

My situation is:

col1     col2  
*************
732      abc
732      xyz
732      rrt
6784     rre
6784     oop
56       u7h
56       wwt

I want to list all of col2 which have a part of 732887.

Posted 13-Mar-15 0:21am

utm

Updated 13-Mar-15 0:32am

Leo Chapiro

v2

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Comments

Shivangi_K 13-Mar-15 6:28am

do you mean to say that if u give 732887 as input, any value in col1 which has any similarity with the input should be selected? like in this case, abc, xyz, rrt should be selected?

utm 13-Mar-15 6:31am

yes.

2 solutions

Solution 3

Try this:

SQL

SELECT * FROM tablename WHERE
CONVERT(VARCHAR, 732887) LIKE '%'+ CONVERT(VARCHAR, col1) +'%'

Posted 13-Mar-15 0:56am

Peter Leow

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Saral S Stalin · Accepted Answer · 2015-03-13T00:29:00

Solution 1

Try below

SQL

declare @t table (col1 varchar(20), col2 varchar(20))
INSERT INTO @t VALUES
('732', 'abc')
,('732', 'xyz')
,('732', 'rrt')
,('6784', 'rre')
,('6784', 'oop')
,('56', 'u7h')
,('56', 'wwt')

SELECT * FROM @t WHERE '732887' LIKE '%' + col1 + '%'

Posted 13-Mar-15 0:29am

Saral S Stalin

Comments

utm 13-Mar-15 6:49am

THANKS ..IT SOLVE MY PROBLEM :)