How to write in javascript for 20-character random generator

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(Program in Javascript)

Write a 20-character random generator that uses the least resource (file size, memory, CPU). The valid characters
allowed in the key string are a-z, A-Z and 0-9.
e.g. 83FEdmhjKla4WiYd6uem

Posted 16-Dec-11 1:38am

ttds

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koolprasad2003 · Answer 1 · 2011-12-16T01:42:00

Solution 1

http://vitaln.com/ehalos/js/RANGen.html[^]

http://www.frihost.com/forums/vt-40859.html[^]

Posted 16-Dec-11 1:42am

koolprasad2003

#realJSOP · Answer 2 · 2011-12-16T01:43:00

if you can create GUIDs in javascript, just do that, and remove the hypens and curly braces if necessary. I found this with google:

JavaScript

function createUUID() 
{ 
    // http://www.ietf.org/rfc/rfc4122.txt     
    var s = []; 
    var hexDigits = "0123456789abcdef"; 
    for (var i = 0; i < 36; i++) 
    {    
        s[i] = hexDigits.substr(Math.floor(Math.random() * 0x10), 1);     
    } 
    s[14] = "4";  
    // bits 12-15 of the time_hi_and_version field to 0010     
    s[19] = hexDigits.substr((s[19] & 0x3) | 0x8, 1);  
    // bits 6-7 of the clock_seq_hi_and_reserved to 01     
    s[8] = s[13] = s[18] = s[23] = "-";      
    var uuid = s.join("");     
    return uuid; 
}

You can change the contents of hexDigits to include more alphabetic characters, adjust the for loop to only generate 20 characters, and remove the code at the bottom of the function that adds the hyphens.

sravani.v · Answer 3 · 2011-12-16T01:44:00

Solution 3

Refer this link
May help you

http://codegolf.stackexchange.com/questions/1360/how-to-write-a-single-line-password-generator[^]

Posted 16-Dec-11 1:44am

sravani.v

Sara Dark · Answer 4 · 2011-12-16T01:47:00

Java

 <script type="text/javascript">
        function generateRandomString() {
            chars = new Array("0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "a", "b", "c", "d", "e", "f", "g", "h", "i", "g", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z");
            var x = "";
            for (i = 0; i < 20; i++) {
                x += chars[randomnumber = Math.floor(Math.random() * 36)];
            }
            return x;
        }
//test it with this line
        //window.alert(generateRandomString());</script>
//to add capital letters just add them to the array and put 62 instead of 36

Santosh K. Tripathi · Answer 5 · 2015-02-09T18:58:00

Solution 5

C#

function GetRandomString() {
var text = "";
var possible = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";

   for (var i = 0; i < 20; i++) {

    text += possible.charAt(Math.floor(Math.random() * possible.length));
   
   }

  return text;
}

Posted 9-Feb-15 18:58pm

Santosh K. Tripathi

Comments

CHill60 12-Feb-15 5:26am

Question was answered over 3 years ago!

Deepu S Nair 12-Feb-15 6:03am

Ans he is reposting it

CHill60 12-Feb-15 6:24am

And there is very little difference between this and solution 4 :)

Deepu S Nair 12-Feb-15 6:27am

smart :)

Santosh K. Tripathi · Answer 6 · 2015-02-09T19:02:00

Solution 6

C#

function GetRandomString() {
var text = "";
var possible = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";

   for (var i = 0; i < 20; i++) {

    text += possible.charAt(Math.floor(Math.random() * possible.length));

   }

  return text;
}

Posted 9-Feb-15 19:02pm

Santosh K. Tripathi

Comments

Deepu S Nair 10-Feb-15 1:12am

Question is nearly 4 years old and also you are reposting your answer

Santosh K. Tripathi 10-Feb-15 5:49am

Is this answer wrong?
or 'ttds' has accepted any solution and hence question is closed?
or a person can't answer a question if question is old?

I was searching for some this and found this question. I answered it because some time earlier i was facing same issue.

Deepu S Nair 12-Feb-15 6:03am

but why are you reposting your answer?

CHill60 12-Feb-15 6:26am

No the answer is not wrong. However there is little difference between what you have posted and what Sara Dark posted in Solution 4 years ago.

Santosh K. Tripathi 12-Feb-15 23:27pm

thanks for response. My solution is showing here two time, really i don't know how it happen.

we can discourse little bit more. i want to put my few points.

1. in my answer i did use 'new Array' keyword because

http://stackoverflow.com/questions/931872/what-s-the-difference-between-array-and-while-declaring-a-javascript-ar

http://stackoverflow.com/questions/7375120/why-is-arr-faster-than-arr-new-array

2. I used '*possible.length' instead of '*36 (no need to calculate array length manually, easy for maintenance if you add/remove few characters in array).

CHill60 17-Feb-15 11:34am

good points - but you should have included them in your solution in the first place and possibly you would not have got all those down-votes

Santosh K. Tripathi 18-Feb-15 4:03am

i will keep it in mind next time :)

suthar parth · Answer 7 · 2015-02-11T23:23:00

You can use below code for the same.

<html>
<body>

Click the button to display a random number.

<button onclick="myFunction()">Try it</button>

<p id="demo"></p>

<script>
function myFunction() {

var Output = "";
var characters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
 
   for (var i = 0; i < 20; i++) {
 
    Output += characters.charAt(Math.floor(Math.random() * characters.length));
   
   }
 
    document.getElementById("demo").innerHTML = Output;
}
</script>

</body>
</html>