How to add text in a textfile to a string using C#

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3.00/5 (2 votes)

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I have selected a file using open file dialog.

Then I need to add all the text contents in the file to a string variable.

How to do so.

Posted 25-Mar-14 22:48pm

KUMAR619

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OriginalGriff · Accepted Answer · 2014-03-25T23:03:00

You could just do this:

C#

string s = "my original content";
s += File.ReadAllText(path);

But that is pretty inefficient:

C#

string s = "my original content";
string fileData = File.ReadAllText(path);
StringBuilder sb = new StringBuilder(s.Length + fileData.Length);
sb.Append(s);
sb.Append(fileData);
s = sb.ToString();

Might be better, particularly if you are doing this a lot and can re-use the StringBuilder

"I am using open file dialog to select 5 files at runtime.

How to create five strings at runtime to store all text files in appropriate strings"

Try this:

C#

OpenFileDialog ofd = new OpenFileDialog();
ofd.Multiselect = true;
if (ofd.ShowDialog() == DialogResult.OK)
    {
    List<string> data = new List<string>();
    foreach (string file in ofd.FileNames)
        {
        data.Add(File.ReadAllText(file));
        }
    }

Or this if you prefer Linq:

C#

OpenFileDialog ofd = new OpenFileDialog();
ofd.Multiselect = true;
if (ofd.ShowDialog() == DialogResult.OK)
    {
    string[] data = ofd.FileNames.Select(f => File.ReadAllText(f)).ToArray();
    }

norbitrial · Accepted Answer · 2014-03-25T23:03:00

Solution 4

You can read the content from a text file as the follows:

C#

String yourFileFromDialog = "file location and file name";
String textFromFile = string.Empty;

try
{
   using (StreamReader sr = new StreamReader(yourFileFromDialog))
   {
       textFromFile = sr.ReadToEnd();
   }
}
catch (Exception e)
{
   //exception handling
}

Here[^] you can read more.

If you have a string array for your file names, do the follow:

C#

string[] fileNames = //fill up from your dialog

String yourFileFromDialog = string.Empty,
       textFromFile = string.Empty;

try
{
   for(int i = 0; i < fileNames.length; i++)
   {
      yourFileFromDialog = fileNames[i];
    
      using (StreamReader sr = new StreamReader(yourFileFromDialog))
      {
         textFromFile += sr.ReadToEnd();
      }     
   }

}
catch (Exception e)
{
   //exception handling
}

For the later usage of the text from the files you can make a private property to your class and append this instead of textFromFile variable:

C#

private string textFromFiles = string.Empty;

Posted 25-Mar-14 23:03pm

norbitrial

Updated 25-Mar-14 23:52pm

v4

Comments

KUMAR619 26-Mar-14 5:14am

@Norbitrial

I am using open file dialog to select 5 files at runtime.

How to create five strings at runtime to store all text files in appropriate strings

norbitrial 26-Mar-14 5:17am

If you store your file names for example in a string array then you can iterate through that array and use the code what I've added as a solution. In each running of your iteration you can change the yourFileFromDialog variable value to the actual file name.

KUMAR619 26-Mar-14 5:18am

Can you get me a code snippet for that please

norbitrial 26-Mar-14 5:25am

I've improved my solution.

KUMAR619 26-Mar-14 5:48am

Thanks
How to create individual string for all files so that I can use it for further purposes

norbitrial 26-Mar-14 5:50am

Maybe you can make to your class a private property or a global variable.

KUMAR619 26-Mar-14 6:20am

I have to store all files in different string such as
textFromFile[0],textFromFile[1],textFromFile[2],textFromFile[3]textFromFile[4]

How to do this

KUMAR619 26-Mar-14 6:38am

I have to store all files in different string such as
textFromFile[0],textFromFile[1],textFromFile[2],textFromFile[3]textFromFile[4]

How to do this

Please help me

norbitrial 26-Mar-14 8:09am

You have to iterate through the textFromFile array and that should be it.

syed shanu · Accepted Answer · 2014-03-25T23:01:00

Solution 1

Chk this code :

C#

 System.IO.StreamReader file = new System.IO.StreamReader(@"D:\test.txt");
String Line="";
String txtLine = "";
while ((Line = file.ReadLine()) != null)
{
    txtLine = txtLine + Line;
  
}
file.Close();
            textBox4.Text=txtLine;

Posted 25-Mar-14 23:01pm

syed shanu

Comments

KUMAR619 26-Mar-14 5:13am

@Syed

I am using open file dialog to select 5 files at runtime.

How to create five strings at runtime to store all text files in appropriate strings

nandakishoreroyal · Accepted Answer · 2014-03-25T23:01:00

Solution 2

C#

StringBuilder sb = new StringBuilder();
using (StreamReader sr = new StreamReader("TestFile.txt"))
{
    String line;
    // Read and display lines from the file until the end of
    // the file is reached.
    while ((line = sr.ReadLine()) != null)
    {
        sb.AppendLine(line);
    }
}
string allines = sb.ToString();

Try Also this Link

Posted 25-Mar-14 23:01pm

nandakishoreroyal

Updated 25-Mar-14 23:02pm

v2

Comments

KUMAR619 26-Mar-14 5:13am

@NandaKishore

I am using open file dialog to select 5 files at runtime.

How to create five strings at runtime to store all text files in appropriate strings

nandakishoreroyal 26-Mar-14 5:26am

create string array, and using for loop assign text in to that..

paste your code, i will write the condition...

How to add text in a textfile to a string using C#

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