Php if link is clicked replaces a form with another

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Hi there im trying to replace my login form with forgor password if link is clicked with out changing the page to another just replace form. it just will not change, here is my link

HTML

<a href="<?php echo URL; ?>Includes/Login/requestpasswordreset">Forgot my Password</a>

and here is my if statement

C#

<?php
            if(isset($_GET['requestpasswordreset'])){
                include ('./Includes/Login/requestpasswordreset.php');
            }
            else {
                include ('./Includes/Login/login.php');
            }
        ?>

Posted 21-Dec-13 13:43pm

Nico_Travassos

Updated 21-Dec-13 13:44pm

v2

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Peter Leow · Accepted Answer · 2013-12-22T00:51:00

You can achieve your objective all in one page using javascript, php code is not needed here. See example code below:

XML

<!DOCTYPE html>
<html>
<body>
<form id="loginForm" style="display:block">
<p>this is login form</p>
<input type="button" id='reset' value="Reset password" onclick='changeForm(this)' />
</form>
<form id="resetForm" style="display:none">
<p>this is reset form</p>
<input type="button" id='login' value="Goto login" onclick='changeForm(this)' />

</form>

<script>
function changeForm(e){

   var whichButton = e.id;

   if (whichButton == 'reset'){
       document.getElementById('loginForm').style.display="none";
document.getElementById('resetForm').style.display="block";

   } else {

document.getElementById('loginForm').style.display="block";
document.getElementById('resetForm').style.display="none";       }

}
</script>

</body>
</html>