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I'm trying to make a login form in a web application in C# and I was wondering if there was an easier way to make the login button disabled if one or both text boxes are empty. I want it to disable if both or one are empty and enable if they are both populated. Is there a kind of 'and or' operator that I can use instead of doing one if loop for the username and one for the password in the textchanged event of both.
Like:
C#
if (username.Text == "" 'and or' password.Password == "")
{
    login.IsEnabled = false;
}

Is there any way of doing this? Thank you
Posted
Comments
Sergey Alexandrovich Kryukov 18-Oct-13 15:30pm    
Please explain the exact logic behind "and or" you would need.
There is no such operator, but any logic can easily be expressed using the available ones.
—SA
Emre Ataseven 18-Oct-13 15:38pm    
Just OR is enough
Alireza C 18-Oct-13 17:02pm    
Hi Henry, I agree with Emre Ataseven, you don't need check both of them. Just check any of them with OR operator.

This is OR. Or END. Besides, using
C#
if (someBooleanExpression)
   someBooleanProperty = true;
else
   someBooleanProperty = false;

would be plain silly, as it is strictly equivalent to
C#
someBooleanProperty = someBooleanExpression;


Also, you should not use "" and avoid using any immediate constants except most fundamental ones line 0, 1 or null. Use string.Empty instead.

So, you would need
C#
login.IsEnabled = username.Text != string.Empty && password.Password != string.Empty;

Note using '&&' instead of '&'. This eliminates redundant checks, as well as '||'. Note that it can also eliminate side effect of the check if a call is involved, that's why '&' and '||' are not removed from the operator set.

In practice, it's advised to make some stricter check:
C#
login.IsEnabled = username.Text.Trim() != string.Empty && password.Password.Trim() != string.Empty;


—SA
 
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v2
Comments
Sergey Alexandrovich Kryukov 18-Oct-13 17:08pm    
Are you serious?! I simplified OP's sillies down to just one line, and you, who, if I'm not much mistaken, put the same kind of sillies in your own answer, managed to make a conclusion that it's "complex"?
Congratulations! Perhaps you need to improve your post reading skills. Sorry.
—SA
Sergey Alexandrovich Kryukov 18-Oct-13 17:23pm    
Offend?! You are offending with some of your posts, but I'm not the one who would play the "offended card". I'm just telling you the truth. If someone points me out the mistake like the one you did, I always only say "thank you", and everyone knows about that.

Teaching? I totally agree. Consider I'm helping you too learn, and it's up to you to accept it and learn, or pretend to be offended and keep to ignorance. We all do mistakes, but some learn from them, others remain stubborn and don't. I hope it's not later for you to review your plans on that. :-)

Best wishes,

—SA
Philippe Mori 18-Oct-13 17:19pm    
As a side note, with latest versions of .NET, you can also uses string.IsNullOrWhiteSpace(username.Text).
lewax00 18-Oct-13 17:29pm    
I agree, that is a much cleaner option.
Sergey Alexandrovich Kryukov 18-Oct-13 17:32pm    
Yes, a good point, but see also my comment above. Compatibility with previous .NET versions is more important, especially on this site, and when we don't know exact version OP uses.
—SA
There's no such thing as "and or". In your case, this would just be an OR expression. I think you better have a look at the boolean logic truth tables.
 
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v2
It's very simple, just you need to check one of them and you don't need to use two if expression so your code can be:

C#
if (string.IsNullOrEmpty(username.Text) || string.IsNullOrEmpty(password.Text))
{
    login.IsEnabled = false;
}


[edit]unnecesary code block deleted[/edit]
 
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v2
First: string.IsNullOrEmpty was implemented starting in .NET 2.0, but, since, as SAK observes, the 'Text property of a TextBox is never 'null, there is no point using either string.IsNullOrEmpty, or string.IsNullOrWhiteSpace: but using them won't "hurt you" :) Using string.Empty, in combination with the string.Trim() method, makes more sense.

The person who implements a LogIn form has some choices to make:

1. to allow white-space entry in UserName or Password fields, or not, is one choice: [^], [^].

If you want to block the user from entering white-space: write an EventHandler for a Control KeyPress Event, and wire-up both UserName and Password TextBoxes to that EventHandler:
C#
private void LogInTextBoxes_KeyPress(object sender, KeyPressEventArgs e)
{
    // uncomment this to block all white-space entry
    // if (char.IsWhiteSpace(e.KeyChar)) e.Handled = true;
}
2. most modern LogIn dialogs show password characters masked out: in Windows Forms you can use a MaskedTextBox to achieve this; I am not familiar with what C# Web applcations provide, but would certainly use one.

3. Deciding when to enable the "attempt login" Button: I like the idea that the UserName and Password TextBoxes start off showing "UserName" and "Password" in their respective TextBoxes, and I like the idea that when the user clicks in either one, their initial display goes away.

In the following example the names of the UserName and Password TextBoxes are 'tbUserName, and 'tbPassword; the name of the Button used to perform the LogIn is 'btnLogIn.
C#
// WinForms 
// set some flags
private bool tbPasswordFirstClick = true;
private bool tbUserNameFirstClick = true;

// both TextBoxes use this Click EventHandler
private void LogInTextBoxes_Click(object sender, EventArgs e)
{
    if (ActiveControl == tbUserName && tbUserNameFirstClick)
    {
        tbUserName.Clear();
        tbUserNameFirstClick = false;
    }
    else if (ActiveControl == tbPassword && tbPasswordFirstClick)
    {
        tbPassword.Clear();
        tbPasswordFirstClick = false;
    }
}
//
// both TextBoxes use this Textchanged EventHandler
private void LogInTextBoxes_TextChanged(object sender, EventArgs e)
{
    btnLogIn.Enabled = !
    (tbUserName.Text.Trim == string.Empty
    || tbPassword.Text.Trim == string.Empty);
}
4. In case you are curious what I actually do in WinForms when the LogIn button is enabled, and it gets a Click:
C#
// the LogIn Form defines two Public Properties

public string UName { get; set; }
public string PWord { get; set; }

// the LogIn Form's DialogResult property is used to communicate
// whether the user cancelled, or made a valid attempt to log in back
// to the point in the application that launched
// the log in form. See final paragraph below for details.

private void btnLogIn_Click(object sender, EventArgs e)
{
    UName = tbUserName.Text;
    PWord = tbPassword.Text;
    this.DialogResult = DialogResult.OK;
    Close();
}
Yes, there is a 'Cancel Button on the LogIn Form, and if it is clicked, the DialogResult property of the Form is set to 'false, and the Form is closed, which passes control back to the point where the Form was shown modally.

If you are really curious, read on: in the Windows Form application I modify the Program.cs file so the log in form is shown first: if the log in attempt fails. the Application never runs. Here's a simple example:
C#
[STAThread]
static void Main()
{
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);
    LogInForm lg = new LogInForm();
    
    // note this is equivalent to using 'ShowDialog() !
    Application.Run(lg);
    if (lg.DialogResult == DialogResult.OK)
    {
        if(lg.PWord == "secret" && lg.UName == "user") Application.Run(new MainForm());
    }
}
 
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Hi,
I agree with Dave, there is no option or condition .
like this type.
C#
private void textBox1_Validated(object sender, EventArgs e)
      {
          if (textBox1.Text != string.Empty || textBox2.Text != string.Empty)
          { button2.Enabled = true; }
          else { button2.Enabled = false; }
      }

      private void textBox2_Validated(object sender, EventArgs e)
      {
          if (textBox2.Text != string.Empty || textBox1.Text != string.Empty)
          { button2.Enabled = true; }
          else { button2.Enabled = false; }
      }



I hope that it is helpful for you.

Thanks
Mohit
 
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Comments
Sergey Alexandrovich Kryukov 18-Oct-13 16:30pm    
Amazingly, you are writing the same silly think as OP did, only improved. :-)
—SA

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