select from open file dialog path

Yes, you can ust it OpenFileDialog[^], but in different way, using string variable instead OpenFileDialog properties.

Please, create new WindowsApplication project and put one button on the form, then double-click on it. Copy and paste below code:

Public Class Form1

    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        Dim ofd As OpenFileDialog = Nothing
        Dim sFullFileName As String = String.Empty
        Try
            ofd = New OpenFileDialog()
            With ofd
                .InitialDirectory = Environment.SpecialFolder.MyDocuments
                .Multiselect = False
                .DefaultExt = "txt"
                .Filter = "txt files (*.txt)|*.txt"
                If .ShowDialog = Windows.Forms.DialogResult.Cancel Then Exit Try
                sFullFileName = .FileName
            End With

            MsgBox("Directory name: '" & System.IO.Path.GetDirectoryName(sFullFileName) & "'" & vbCr & _
                "Short file name: '" & System.IO.Path.GetFileName(sFullFileName) & "'", MsgBoxStyle.Information, "Information...")

        Catch ex As Exception
            MsgBox(ex.Message, MsgBoxStyle.Exclamation, "Error...")
        Finally
            ofd = Nothing
        End Try
    End Sub
End Class