Jet SQL - Syntax Query

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Hi all,

I'm struggling due to the lack of a count(distinct) function in Jet SQL. My code so far is as follows:

SQL

select
    [FailureModels].[Id],
    [FailureModels].[Description],
    [FailureModels].[FailureRate],
    [FailureModels].[FailureRateDistribution],
   [FailureModels].[ModelType],
    iif([FailureModels].[ModelType] = 'Rate&', [FailureModels].[RepairRate], [FailureModels].[MTTR]) as RepairRateMTTR,
   [GateGroupImportance].[FVImp],
   [GateGroupImportance].[BBImp],
   [GateGroupImportance].[Project],
   count(*) where [FailureModels].[Id] = [PrimaryEvents].[FailureModels]
   from ([FailureModels] INNER JOIN [GateGroupImportance]
   ON [GateGroupImportance].[EventGroup] = [FailureModels].[Id])
   INNER JOIN [PrimaryEvents] ON [PrimaryEvents].[FailureModel] = [FailureModel].[Id]

It all compiles, except the line beginning count(*) which is throwing a syntax missing exception. Has anyone any ideas?

Very grateful for any advice,
Thanks,
Stephen.
[edit]code block added[/edit]

Posted 12-Nov-12 6:38am

Steve 2712

Updated 12-Nov-12 8:30am

Nelek

v2

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Comments

snorkie 12-Nov-12 15:25pm

Have you tried counting a column instead? Try COUNT([FailureModels].[Id])

Herman<T>.Instance 13-Nov-12 3:59am

nope when using functions like count,sum etc you have to define the GROUP BY so the query tells the server what to count exactly

chaau 12-Nov-12 16:37pm

I do not believe count(*) where [FailureModels].[Id] = [PrimaryEvents].[FailureModels] is a valid SQL syntax. As the snorkie suggested, use COUNT([FailureModels].[Id]). Do not forget to add GROUP BY statement at the end of your query.

Herman<T>.Instance 13-Nov-12 3:57am

indeed it is the group by that is missing

Kschuler 13-Nov-12 10:58am

I agree. You should post this as a solution, not just a comment.

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Steve 2712 · Accepted Answer · 2012-11-22T05:45:00

Solution 1

Thanks for all the comments, they were invaluable. The group by statement was the solution. I had to group by all of the columns mentioned to solve the problem.

Thanks again,
Stephen.

Posted 22-Nov-12 5:45am

Steve 2712