date difference problem in sql server 2008

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SQL-Server-2008

Hello everyone,

I just used DateDiff in sql, i.e Datediff(Day,fromdate,todate) and i got a nice result.

I used ..

SQL

Declare @fromdt date
Declare @todt date
set @fromdt=CONVERT(datetime,2012-05-30 ,105)
set @todt =CONVERT(datetime,2012-05-29  ,105)
SELECT datediff(DAY,@fromdt ,@todt )as 'DaysDifference'

it gave me output as : 1

but when i used..

SQL

Declare @fromdt date
Declare @todt date
set @fromdt=CONVERT(datetime,2012-05-30 ,105)
set @todt =CONVERT(datetime,2012-05-31  ,105)
SELECT datediff(DAY,@fromdt ,@todt )as 'DaysDifference'

it gave me output as : -1

now what i need is irrespective of whether the date is greater then from date or lesser then from date i want output as 1 only ...please suggest what should i do??

Thanks & Regards,
Krunal Panchal

Posted 29-May-12 21:56pm

krunal25

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Dylan Morley · Answer 1 · 2012-05-29T22:00:00

Solution 1

You could use the ABS [^]function to convert...e.g

SQL

SELECT ABS(datediff(DAY,@fromdt ,@todt )) AS 'DaysDifference'

Posted 29-May-12 22:00pm

Dylan Morley

Updated 29-May-12 22:01pm

v2

Comments

Maciej Los 30-May-12 5:22am

Good answer, my 5!

[no name] 31-May-12 2:38am

Hi losmac,

I used your solution and it worked but again i am facing one problem i.e.

when i used

Declare @fromdt date
Declare @todt date
set @fromdt=CONVERT(datetime,2012-05-30 ,105)
set @todt =CONVERT(datetime,2012-06-01 ,105)
SELECT datediff(DAY,@fromdt ,@todt )as 'DaysDifference'
it gave me output as : 28 days instead it should give 2 days....

please help...

Regards,
Krunal Panchal

Dylan Morley 31-May-12 4:08am

It's the way you're converting, try this...

Declare @fromdt date
Declare @todt date

set @fromdt=CONVERT(datetime,2012-05-30 ,105)
set @todt =CONVERT(datetime,2012-06-01 ,105)

PRINT @fromdt
PRINT @todt

Notice the date values? They are incorrect! Try changing the values used in the CONVERT function, see if you can fix it

Prosan · Answer 2 · 2012-05-29T22:41:00

use this query i think it will solve your problem

SQL

Declare @fromdt datetime
Declare @todt datetime
set @fromdt=CONVERT(datetime,2012-05-30 ,105)
set @todt =CONVERT(datetime,2012-05-31  ,105)
SELECT
(case when datediff(DAY,@fromdt ,@todt ) >0 then datediff(DAY,@fromdt ,@todt ) else abs(datediff(DAY,@fromdt ,@todt )) end)as 'DaysDifference'

if you don't want to check datediffernce is >0 or <=0 then you can use direct abs() method as per describe in solution 1.