Arithmetic overflow error converting expression to data type smalldatetime.

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hello friends please help me...here is my code .....
private void dateTimePicker1_Leave(object sender, EventArgs e)
{
SqlConnection con = Conn.getopenedconnection();

SqlCommand cmd = con.CreateCommand();
cmd.CommandType = CommandType.Text;
cmd.Connection = con;
DateTime date1 = Convert.ToDateTime(dateTimePicker1.Text);
string date11 = date1.ToShortDateString();
//cmd.CommandText = ("SELECT itemcode,maturity FROM SAUDAMAST WHERE COMPCODE='" + Compcls.Gcomp_cd + "'and itemcode='"+comboBox1.SelectedValue+"' and maturity='"+date11+"'");
cmd.CommandText = ("SELECT itemcode,maturity FROM SAUDAMAST WHERE COMPCODE=@COMPCODE and itemcode=@itemcode and maturity=@maturity");
cmd.Parameters.AddWithValue("@COMPCODE", Compcls.Gcomp_cd);
cmd.Parameters.AddWithValue("@itemcode", comboBox1.SelectedValue);
cmd.Parameters.AddWithValue("@maturity", date11);
SqlDataReader sdr = cmd.ExecuteReader();
int count = 0;
while (sdr.Read())//HERE I GET ERROR=Arithmetic overflow error converting expression to data type smalldatetime.
{
count = 1;
}

if (count > 0)
{

MessageBox.Show("Sauda already exists this comodity and this date");
dateTimePicker1.Focus();
// textBox3.Text = "";
}
}
ERROR=Arithmetic overflow error converting expression to data type smalldatetime.

Posted 24-Dec-11 0:04am

Lakhan Aanjana

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Sridhar Patnayak · Answer 1 · 2011-12-24T00:08:00

Solution 1

DateTime date1 = Convert.ToDateTime(dateTimePicker1.Text)

statement is getting error

Declare like this

DateTime date1=new datetime();

date1=dateTimePicker1.value

This will solve your problem

Posted 24-Dec-11 0:08am

Sridhar Patnayak

Comments

[no name] 24-Dec-11 6:13am

thank you very much.....if u don't mind can u tell me reason behind problem

Sridhar Patnayak 24-Dec-11 6:21am

Datetime is a constructor, so first you have to create object it and pass parameters .
2nd one datetimepicker1.value return date