Path of XML file in Windows application

I assume you are using a OpenFileDialog control in a Windows Forms application and perhaps you are trying to retrieve the File's full path in the Form_Load() event. That is:

private void Form1_Load(object sender, EventArgs e)
{
       string filePath = Path.GetFullPath(openFileDialog1.FileName);
       //This will return the path of the exe or dll of the application
}

If you try to retrieve the full path in the Form_Load event, system will provide you the current directory Path, that is, the dll or exe from where the application is running. May be that's what is happening in your case.

What you need to do is, you should try to retrieve the File's full path after selecting the file using the OpenFileDialog control. Here are the steps:

private void Form1_Load(object sender, EventArgs e)
{
       //No code here
}
        
private void button1_Click(object sender, EventArgs e)
{
       // Show the file browser control in the Button click event (A button on the windows form)
       // You need to add a Button Click event handler
       openFileDialog1.ShowDialog();
}

private void openFileDialog1_FileOk(object sender, CancelEventArgs e)
{
       //Retrieve the file's path when user selects the file. You need to add a FileOk click handler 
       //for the OpenFileDialog control
       string filePath = Path.GetFullPath(openFileDialog1.FileName);
       //Here you will get the full path of the selected file
}

Hopefully, this will resolve your issue.