SQL Query selecting the oldest member

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SELECT membFNme, memberIdNum, MAX(DATEDIFF (YY,substring(memberIdNum, 1,6), GETDATE()))
FROM member
GROUP BY membFNme
HAVING  = MAX (DATEDIFF (YY,substring(memberIdNum, 1,6), GETDATE

I need to select the oldest member in the member table

Posted 19-Aug-10 1:30am

allaparaclatus

Updated 19-Aug-10 7:50am

Abhinav S

v2

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shivaprasadk 19-Aug-10 8:22am

Please mention clearly the requirement.
The DateDiff function gives difference between two date values. I don't think the MemberIdNum is the DateValue. Is it?

LittleYellowBird 19-Aug-10 8:25am

Hi, there is no need to shout. I have removed the all capitals from your title as it appears to be shouting and is very rude. :)

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shivaprasadk · Answer 1 · 2010-08-19T02:27:00

Solution 1

Hi,

You have two options:

1. If the MemberIdNum column contains identity or continuous number, you can take first member as the Oldest member. B'coz, the first member will be the oldest member

2. If the MemberIdnum is containing the datevalue, then also the lowest MemberIDnum value is the oldest member

so, you can use:

select top 1 membFNme, MemberIdNum from member order by MemberIdNum

Posted 19-Aug-10 2:27am

shivaprasadk

Comments

allaparaclatus 19-Aug-10 9:19am

Thank you but i also need it to sho the age as well

shivaprasadk 19-Aug-10 12:09pm

For getting the Age, you should have the member joining date (if age of work) or birth date (if age of employee)

shivaprasadk · Answer 2 · 2010-08-19T20:54:00

Solution 2

Hi,

for getting the oldest member with Age, the query is:

select top 1 memnFNme, memberidNum, dateDiff(yy,membDOBirth,getdate()) as Age from Member
order by membDOBirth

Posted 19-Aug-10 20:54pm

shivaprasadk