Comments by Member 15784866

Member 15784866 6-Oct-22 8:20am View

Hi Richard! yes, I took into account that the number can be greater than 9, it is the part called "doppia"/"doppia1" but it doesn't work properly anyway...when the number consists of 2 digits..something is missing to me. I'm using emu8086 indeed.

Member 15784866 5-Oct-22 17:01pm View

I understand it and I thank you for your reply. I promise that I'm going to stop posting about this problem. I really don't want to monopolize the site.

Member 15784866 2-Oct-22 11:28am View

beh as I said, the ASCII value for '0' is always 00h, and Null as code, , and 9 becomes 09h and HT as code. This program is supposed to add two one digit numbers, and the risult should be kept until 9. This is my first goal, then I will improve it. Unfortunately I didn't catch the last question

Member 15784866 2-Oct-22 11:13am View

to be honest, I barely understand the question.. the first ten numbers should be the same, in ex and in the binary form...well, I have to read the assembly's basics again...thank you anyway.

Member 15784866 2-Oct-22 9:04am View

this code should convert the chars into binary numbers, as I was supposed to it. I found it online but I must adapt it to my program..is it reasonable or am I out of line? by the way, I'm using emu8086..so this is an emulator and nothing else

Member 15784866 2-Oct-22 8:00am View

Ah I forgot to tell you that "somma" would be"sum" in English..but you already got it.

Member 15784866 2-Oct-22 7:59am View

wonderful! I understand more or less the point...I need something like this: .model small
.data
a db 0AH
.code
mov ax, @data ; Initialize data section
mov ds, ax
mov al, a ; Load number1 in al
mov cl , 08H
mov ah, 00h ; ah=00
up : shl al, 01h ; divide the number by 2
and SHL gives the same result
mov bl, al
mov al, 00H
adc al, 30h
mov dl, al
mov ah, 02h
int 21h
mov al,bl
dec cl
jnz up
mov ah, 4cH ; Terminate Program
int 21H
end

Member 15784866 2-Oct-22 4:19am View

Content moved to the question.

Member 15784866 2-Oct-22 3:48am View

hI Richard" many thanks! I'm having another problem, I just corrected the code but the debugger says that there operands don't match in the "MOV NUM1, AX" instruction..it's a 8 bit address and a 16 bit register..can we correct this point? I must excuse me, I should have brush up the basics but I was in hurry and I started with the practice immediately..;,

Member 15784866 1-Oct-22 14:05pm View

there is an "FB" instead of "DB", this is an error, but not the main one

Member 15784866 1-Oct-22 14:04pm View

hello, thanks for answering! you are right, I beg your pardon. The emulator shows "the emulator is halted." before giving the final result

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