Comments by Sourabh Jambale (Top 23 by date)

Yes, added. Thank you!

I did for an example string:


String s1 = "250,10@100,3@50,7";
String hello[] = s1.split("@", 3);
String s2[] = null;
for (String a : hello) {
s2 = a.split(",");
for (String b : s2) {
int z = Integer.parseInt(b);
System.out.println(z);
}
}

All the integer values are stored in z but how can individually assign them to their respective variables, for example 250 to Rate1,100 to Rate 2 and so on?

Actually, the compiler adds input of its own when I submit the solution(when I run the program, I don't get any errors because I initialised the objects to their correct values) it shows Null Pointer Exception at the equals() method. This is my main method:

public class Source {
	public static void main(String[] args) {
		Customer c1 = new Customer(1, "Sourabh", "Pune", "89", "Hello");
		Customer c2 = new Customer(1, "Sourabh", "Pune", "89", "hello");
		c1.setEmail("vinod@gmail.com");
		c2.setEmail("vinod@gmail.com");
		c2.equals(c1);
		Customer c3 = new Customer();
		c3.setCustomerId(10);
		int k = c3.getCustomerId();
		System.out.println(k);
		Customer c4 = new Customer();
		c3.equals(c4);
	}

}

Thank you!

Thank you so much for the answer. But how can we avoid the negativesArraysize exception error in this code? We want to return "Invalid input" when we enter a negative value for "n" which is the array size. Here's my code:

String designation = "Sales";
        int counter = 0, n;
        Scanner sc = new Scanner(System.in);
        n = sc.nextInt();
        String[] result = new String[n];
        if (n > 0) {
            for (int i = 0; i < n; i++) {
                result[i] = sc.next();
            }
            for (int j = 0; j < result.length; j++) {
                if (result[j].startsWith(designation)) {
                    result[counter] = result[j];
                    counter++;
                }
                
            }
            if(counter>0){
                System.out.println("Designations in Sales Department " + counter );
                
            }
            else if(counter==0){
                System.out.println("No designations in Sales department ");
            }
           
            for (int i = 0; i < counter; i++) {
                System.out.println(result[i]);
            }
        }
        else{
            System.out.println("INVALID INPUT");
        }

What is the "answer" variable here?

I did

if (Arrays.stream(arr).anyMatch("sales"::equals)) {
                    System.out.println(arr[i]);
                }

but it doesn't show any output.

But we don't want to compare strings here, we want to input some strings and then check if those strings contain the word "Sales" and print those values.

But I get the wrong output...

Input:

100 rajan chennai

20 rakesh hyderabad

30 pradeep delhi

10 akanksha pune

101 atharva xyz

My wrong Output:

20 rajan chennai

30 rakesh hyderabad

100 pradeep delhi

101 akanksha pune

10 atharva xyz

But that works only for primitive data types but String is not a primitive data type.

Yes, but how can we apply bubble sort on 2d array? I mean this only swaps the customer id but keeps the other details meaning 10 sam london and 5 joe paris will become 5 sam london and 10 joe paris. How to match the correct output?

Ok, so I did this but I think it is wrong too? Can you please help in the correction?

for (int i = 0; i < 2; i++) {
            for (int j = 0; j < 3; j++) {
                info[i][j] = sc.nextLine();
            }

        }
        for (int i = 0; i < 1; i++) {
            if (info[i][0].compareTo(info[i + 1][0]) > 0) {
                temp = info[i][0];
                info[i][0] = info[i + 1][0];
                info[i + 1][0] = temp;
            }
        }
        for (int i = 0; i < 2; i++) {
            for (int j = 0; j < 3; j++) {

                System.out.println(info[i][j]);
            }
        }

I did

for (int i = 0; i < 1; i++) {

but when I display the array, it only shows the first part of the array(only details of 1 customer and not the second one). Can you please help with the sorting part? I'm new to Java.

but doesn't i<2 means that it would skip 2? the only values will be 0 and 1 and when i=2, it will come out of the loop?

What should be done so it accesses the next element? It is recommended to have a 2d array in the question.

Actually the question asks to have a 2d array.