Comments by Andriken - CodeProject

Andriken 18-Sep-17 7:43am View

maybe , lastly im giving it a try by re-creating virtual env and installing right compatible version as best as i can according to django offical guide on compatible django and python version.

Andriken 8-Jul-16 10:51am View

ohh ! so rude you are' im sorry stranger ...... i even should'nt called anyone for help as they are strangers for me on here ' but that does'nt mean i could not ask for help ! you sound's like iv'e doing major sin's by calling you bruh or bro !

Andriken 30-Jun-16 14:48pm View

bro that's what conclusion im dumping here ................codeacademy say it's a syntax error and codeacademy is a learning site it doest show up the exact error line although the code does well and console correctly ! and sorry if you are even learning ... understand me bruh ! by d way thanks ' already before heard from douglas crockford referred about that site but just noticed what it is !

Andriken 30-Jun-16 14:46pm View

i did the same as here he claims and proven at the same place where im doing this ! but my did'nt work ... see here http://stackoverflow.com/questions/31032001/codeacademy-contact-list-building-7-8-not-returning-contact-info/31032212

Andriken 30-Jun-16 14:41pm View

i dont know how much more clarification you guys need even same as you i think it's right code but the codeacademy say's it's not, throwing an error saying "syntax error !"

Andriken 17-Jun-16 9:14am View

bro it's make sense that i only replying you're consideration ! i already agree with solution 1 i just said cause you asked , by d way i already understand , thanks for effort dude !

Andriken 15-Jun-16 14:03pm View

actually i just created a program which is a search text program which find's a whole word ' by just an starting letter of it ' see this !

var text ="Andriken is trying to be nice !";
var myName ="Andriken";
var hits=[];
for(var i = 0;i < text.length; i++){
if(text[i] === "A" ){
for(var j= i; j <(myName.length + i); j++){
hits.push(text[j]);
}
}
}
if(hits === 0){
alert("your name was'nt found");
}
else{
alert(hits);
}

and then thought about finding a string using same function ! but came to know that's cant compare a letter from for loop with string.

Andriken 15-Jun-16 13:58pm View

you mean when for loop start running and it's check's letter's instead of string's ? and so that's why i was comparing an text[i] which has letter's and was comparing it to a string ! am i right ? and sir please tell me how much experience you have in javascript , you are fabulous in solving and figuring !

Comments by Andriken (Top 8 by date)