XML / XSL

Re: XML to JSON using XSLT

3-Mar-09 23:34

Hey Lee
ya i googled it from ur earlier reply and was able to find the VB code and i just tested it for transformation. It worked. wow, i have these so called senior developers on my side and it dint strike them when i asked them for this transformation tool. K thanks a million.

Regards
Teja

XML to JSON using XSLT

Nishanthkumar26-Feb-09 19:29

Nishanthkumar

26-Feb-09 19:29

How do i convert an XML file to JSON(Java Script Object Notation) file using XSLT.
Help me......(new to XSLT).

Thanks in Advance

Curtis Schlak.27-Feb-09 1:33

Reading XML Schema and schemas located in Includes

27-Feb-09 1:33

I'd recommend first learning some XSLT. You can do that at W3 Schools XSLT Tutorial[^].

Then, I'd recommend learning about JSON, if you don't know it already. You can do that at JSON.org[^].

Finally, map the elements from your XML file to serialized objects in the JSON file.

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

ValAkkapeddi26-Feb-09 12:23

ValAkkapeddi

26-Feb-09 12:23

I'm writing a C# app to document the types of XmlSchemaComplex types...

I have a schema file containing complexTypes, and those complexTypes have elements which are of other complexTypes, located in another file that I'm including into my outer schema file. I'm reading the schema file, going into the complexTypes, and trying to read the types of the sub-elements that are of the sub-types.

However, the type attributes of the elements inside my main complexTypes are set to nulls, although the SchemaTypeText is filled out with the current type name and namespace.

The code that I'm using looks a little something like this (please pardon the horrendous noobishness):

XmlTextReader schemaReader = new XmlTextReader(schemaPath);
XmlSchema schema = XmlSchema.Read(schemaReader, null);

foreach (XmlSchemaObject xso in schema.Items)
{
if (xso is XmlSchemaComplexType)
{
XmlSchemaComplexType rootType = xso as XmlSchemaComplexType;
if (rootType.Particle is XmlSchemaSequence)
{
XmlSchemaSequence rootseq = (XmlSchemaSequence)rootType.Particle;
foreach(XmlSchemaObject ixso in rootseq.Items)
{
if (ixso is XmlSchemaElement)
{
XmlSchemaElement ele = ixso as XmlSchemaElement;
XmlSchemaType eleType = ele.SchemaType; // this is null
string typTxt = ele.SchemaTypeText; // this right, but strings.
}
}
}
}

If I can get the part about accessing the element types of the nested elements in my complexTypes right, I want to pass those complexTypes into a recursive method that'll enumerate all the members of the inner complexTypes for me, etc.

XML Read and Write in Java

TJS4u25-Feb-09 18:43

TJS4u

25-Feb-09 18:43

hello all

Can any one help me with the xml read and write operations using java

some sample codes......
which is used in java DOM ,SAX,,,,,

thanks

tJS

Re: XML Read and Write in Java

led mike26-Feb-09 4:42

led mike

26-Feb-09 4:42

TJS4u wrote:
Can any one help me

Sure, I always enjoy helping the google impaired.

Here you go[^]

Have a nice day.

XSLT nested list problem [modified]

PeOpLesChAmP25-Feb-09 5:02

PeOpLesChAmP

25-Feb-09 5:02

Hi, I'm new to XSLT and i was hoping someone could point me in the right direction with the problem below...

I have the following XML:

<list level="1">
    <item>1</item>
           <list level="2">
                 <item>1</item>
                 <item>2</item>
                 <item>3</item>
           </list>
     <item>2</item>
</list>

I would like to extract the nested list and insert it between item 1 and 2 of the parent list:

<list level="1">
     <item>1</item>
</list>
<list level="1">
     <item>1</item>
     <item>2</item>
     <item>3</item>
</list>
<list level="1">
     <item>2</item>
</list>

Any suggestions?

modified on Wednesday, February 25, 2009 11:14 AM

Re: XSLT nested list problem

led mike26-Feb-09 4:44

led mike

26-Feb-09 4:44

PeOpLesChAmP wrote:
Any suggestions?

Check out www.w3schools.com. They have tutorials tailored for beginners as well as a complete reference.

XML

Bedke24-Feb-09 16:26

Bedke

24-Feb-09 16:26

How do i create an entry for an control in xml if the name contains "< >" characters. for Ex: name="[9] <mm>somename"

Re: XML

Calin Tatar26-Feb-09 5:50

Calin Tatar

26-Feb-09 5:50

You need to replace those special chars. Use this:

xml encode/decode[^]

Calin

How to convert from html to xml

Tejabhiram22-Feb-09 18:51

22-Feb-09 18:51

Hey all,

I have been writing a tool which will allow u to convert xml files into .docx files (Word 2007). For this one needs to have the xml and a related xsl file for it.

Now i also need to convert the word document to the basic xml file that was used earlier. I couldn'nt figure out a way to do that and so have converted that word document to a basic html file. Now i am in a fix as to how to convert that file in to the original xml file.

Is the technique which i am following(Word > html > xml) correct? Or is there a better way to do this?
If there is an easier or better way to do this, Please help me out.

Thanks in Advance
Teja

Curtis Schlak.26-Feb-09 15:59

26-Feb-09 15:59

I guess the question is if your transformation from XML to DOCX represents a lossy or lossless transformation.

If the transformation causes loss in understanding the content or structure of the original XML file, then you cannot reconstitute the exact original XML file regardless of intermediary transformations, such as to XML.

Otherwise, if your transformation is lossless, then you should have enough information to write an XSLT document that provides the inverse of the original XSLT. In this case, your intermediary step of HTML is not needed.

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

Tejabhiram26-Feb-09 17:49

26-Feb-09 17:49

Hey Currtis,

Thanks for the reply. Mine is a loseless transformation.
I need a clarification. What do you mean by a reverse XSLT? Once i get my reverse XSLT, Do i need to use it on the Wordml document in order to transform it into a original xml?>

Please help,
Thanks in Advance
Teja

Curtis Schlak.27-Feb-09 1:31

27-Feb-09 1:31

Hi, Teja.

You need to craft another XSLT document that is the inverse of your original XSLT document. You have XML -> WordML, now you need a WordML -> XML transformation, as well. Then, you just run the new XSLT on the WordML document to make it XML.

Do you want to do this because you don't retain the original XML? Or, you transform it from XML so that users can edit it in Word? Then, after their edits, you want to replace it in your document management/repository system?

You're welcome, in hindsight,
Curtis.

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

Tejabhiram27-Feb-09 2:05

27-Feb-09 2:05

Hey Curtis,

Wow, i dint know that there existed an inverse xslt that will help me convert the WordML to a the original xml. I guess now i need to figure out as to how to write the inverse XSLT. Yes the kind of interpretation u gave about wat am i trying to do is correct. I am trying to allow a user to open an xml as word document and when he edits it and saves it, i an trying to save it in the original xml format.

Could u send me any sites in which i could get a glance of the word to xml, xslt. if i get an example, i could start writing my own xslt for the document.

Thanks for the great help,
Thanks in advance,
Teja

Curtis Schlak.27-Feb-09 3:43

27-Feb-09 3:43

Teja,

I regret that I have to write that I know of no Web sites or books that talk about how to create an inverse XSLT. However, since you have the original one, I would recommend going through the transformation command by command, figure out the mappings XML -> WordML, and then try to capture that in another XSLT.

I don't use it myself (because it costs money and I'm cheap : ), but Altova XmlSpy can help you with understanding the transformations with its XSLT editor and debugger. I think that Altova used to allow you to download a free edition, or you could ask your company to purchase a license for the Standard, Professional, or Enterprise edition. (Note: I do not work for or with Altova.)

Hope that helps and happy hacking!

You're welcome in hindsight,
Curtis.

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

Tejabhiram1-Mar-09 17:56