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Ok.
Per the OP table looks like the following
Table T
id char(22)
RefId1 char(22)
RefId2 char(22)
I need to do the following
1. Verify that RefId1 and RefId2 are in a different table either in that order (1,2) or (2,1)
2. Report if neither or only one id is found.
3. Report if more than one match is found
4. If found report if a different column (not documented above) is same as in the second table.
The second table also has a billion rows.
Both tables have indexes on the id, and the two other columns documented above.
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oh that is ugly - the 1,2 - 2,1 is going to cost you.
Can you do it in a couple of steps, inner join on the 2 layouts and eliminate them from the process, possibly even move the non matching records into another table for your reporting analysis (one assumes the majority have valid matching records).
Never underestimate the power of human stupidity
RAH
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Mycroft Holmes wrote: oh that is ugly - the 1,2 - 2,1 is going to cost you.
Yep - not my design.
Mycroft Holmes wrote: Can you do it in a couple of steps, inner join on the 2 layouts and eliminate them from the process,
I suspect that join between the two tables will return on the order of a billion rows. Either because there are very few rows that are not matched or there are zero. I am only expecting the first because with legacy data orphans might occur.
Mycroft Holmes wrote: possibly even move the non matching records
I have to find them first. Once I find them I don't consider the analysis to be a problem. Actually for those that do not match I consider it likely they are orphans.
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Split it into groups by taking the first 1 or 2 characters, process each set independently.
Getting desperate here as I'm running out of ideas.
Never underestimate the power of human stupidity
RAH
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Also an interesting idea.
For base 64 encoding that would give approximately 244000 per query(2 characters0 and, per the other comment, it should be fast enough to use that a page.
The only limitation there would be if the values were not uniformly distributed.
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jschell wrote: if the values were not uniformly distributed
Uhm I would presume the fields are indexed and physical location would be irrelevant.
Never underestimate the power of human stupidity
RAH
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It's not uniformly distributed per definition, but the first half of a guid is the time part, and it's stored in reverse order of significance, so for this purpose it could probably be considered as uniformly distributed.
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For clarification on that the value is actually based on the UUID from java. And that UUID would seem to have a uniform distribution because the layout is not strictly ordered by time - the UUID uses the minor time (probably seconds/millis) as the most significant part.
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Another question.
Do you need to keep track on what page you are analysing or is sequential paging good enough?
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Paging was not part of the solution. Paging was necessary only because I could not read the entire collection into memory. However I did need to insure that all of the data was read and that the same row was not read twice.
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Then I believe I have enough info to recommend you to not use pagination the way you do.
SELECT * FROM tbl LIMIT 2000,10; is an extraordinary inefficient query.
It's internally functioning like this pseudocode:
SELECT BOTTOM 10 *
FROM (
SELECT TOP (2000+10) *
FROM T
)In short it selects the 2010 first rows to just throw away the first 2000 rows.
If you can store the max(ID) from the previous page I'd recommend trying this instead
SELECT id
,RefId1
,RefId2
,...
FROM T
WHERE id > @PreviousMaxID
ORDER BY id
LIMIT @PageSizeYou obviously need to have an index on the id column for this to be fast.
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Jörgen Andersson wrote: If you can store the max(ID) from the previous page I'd recommend trying this instead
I like the idea. Unfortunately the id is not sequential (again not my idea.)
So to do the paged query based on that it would require sorting the primary id then paging on that. So perhaps exactly the same or even less efficient.
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That's why you need to have an index on the id. (or any unique column or combination of columns)
The index is already sorted per definition.
So the WHERE id > @PreviousMaxID just walks down the b-tree to the right id and starts counting leafnodes until it reaches @PageSize.
I don't know how AWS Aurora is organized, but if your table is clustered, you don't even need to lookup the pages and Bob's your uncle.
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I do not believe that is how that works.
The primary key is indexed. However indexing is a btree and based on a hash. I presume natural ordering on the index would be to walk the btree. But, again, that would be based on the hash.
In contrast "id > previous" is based on the value.
I do not have access to the hashing algorithm and even if I used "hash(id) > hash(previous)" then it would end up doing a table scan (or at least an index scan) which would not help at all.
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B-tree is not hash based.
MySQL DOES support[^] hash-based indexing, but that is not supported on neither MyISAM nor InnoDb. Only for Memory storage engine and NDB-clusters.
And then you still need to choose between b-tree OR hash-based index.
Hash-based indexes are obviously NOT ordered.
I don't know anything about Amazons databases, so whether your index is hash-based or not is something you need to check.
In my very personal opinion, the only reason to use a hash-based index instead of b-tree is if your data doesn't have any kind of ordering to it, like GUIDs for example.
<edit>Curiosity took over, I wondered why your RefID was char(22), and it seems like a base64 encoding of GUIDs use exactly 22 characters.</edit>
modified 24-Mar-18 14:44pm.
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Jörgen Andersson wrote: B-tree is not hash based.
Ok. I stand corrected.
So that should work.
Jörgen Andersson wrote: I don't know anything about Amazons databases
They do not expose the underlying implementation. But it should be a binary equivalent so your point should hold.
Jörgen Andersson wrote: and it seems like a base64 encoding of GUIDs use exactly 22 characters
Yes I believe that is correct. Not my design but I believe something I have looked at in just the last day would support that.
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If it's a btree index it should work.
But if it is a hash index, I really don't have a solution.
Except adding a btree index on the table.
Hash indexes are faster for lookups, but totally useless for ranges.
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Hi - We migrated from sql server 2008 to 2012. We have a stored proc which inserts dates into a table. We insert an initial value wherein the identity key value is -1, with an insert statement. For the rest of the dates, we have a while loop. within the while loop, the next identity key value is resulting as 0 in sql server 2012 and as a 1 in sql server 2008. Both server have the table's field name defined with identity_seed as 0, and increment as 1.
Why does sql server 2008 have 1 as the next value after -1, and sql server 2012 have 0 as the next value after -1?
Thank you.
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The fact you have a while-loop is filling me horror. However, without being able to see the SP code we can't possibly comment on what might be going wrong.
You have contradicted yourself however, you stated Quote: We insert an initial value wherein the identity key value is -1,
but you state Quote: Both server have the table's field name defined with identity_seed as 0, and increment as 1.
Without checking I can't confirm, but perhaps there was a hole in 2008 that allowed you to trample all over the IDENTITY column.
You should use IDENTITY (-1,1) if you want the first key to be -1 (but I suspect you don't).
Try posting the code so we can suggest ways of improving it ... like getting rid of the WHILE loop 
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Sounds like you're RESEEDing the table:
If rows are present in the table, the next row is inserted with the new_reseed_value value.
In version SQL Server 2008 R2 and earlier, the next row inserted uses new_reseed_value + the current increment value.
So if you reseed to 0, and your increment is 1, the next value in SQL 2008 R2 or earlier will be 1, whereas the next value in SQL 2012 or later will be 0.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Thank you, that is helpful!
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VK19 wrote: Why does sql server 2008 have 1 as the next value after -1, and sql server 2012 have 0 as the next value after -1?
The answer was above, but I am curious why it matters.
Certainly existing data would long be past zero or one. And if this is new data, always, then why does it matter?
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This is part of our datawarehouse project.
We have some reports set up for data extract, and using some <> 0 conditions.
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So then adjust your index to start at 100 just to be sure.
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