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It would be best to check the length before trying to substring that... I don't think anyone likes argument out of range exceptions....
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thanks for the hints. i guess the best solution will be
if (mystring.length > maximumlength)
{
mystring = mystring.Substring(0, maximumlength);
}
so if the string is already smaller than the maximum length, then it is easy to insert it, but if it is longer, then just the first characters (up to maximumlength) should be insert.
thanks again for the hints. i didn't know it was this easy 
stephan.
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good morning from montreal,
i am working with a TURBO C 2.01 compiler -
with which i am still very satified - but i can't find anywhere a good
article how to incorperate ASSEMBLY language with this compiler. that's
really all for now. of course if someone could show me a SIMPLE code
fragment, from way back when, that's really all i,d like. So thanks
beforhand. allan.
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you asked in the wrong forum.
this forum is about C#, a rather recent language, quite different from good old C.
I suggest you ask again in the C/C++ forum (unmanaged, no CLI), but even then don't
hold your breath...
Luc Pattyn [Forum Guidelines] [My Articles]
This month's tips:
- before you ask a question here, search CodeProject, then Google;
- the quality and detail of your question reflects on the effectiveness of the help you are likely to get;
- use PRE tags to preserve formatting when showing multi-line code snippets.
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It's been a really long time, but I think Borland used the following:
single line:
asm mov ah, 9
or a block:
asm
{
mov ax, 1234h
mov bx, ax
}
Hope that works. I think you can also link in your ASM files but that part of my brain has been overwritten.
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I get an InvalidCastException in the bold part of the code (the "" and /object are not part of the code)
public void AthugaStafset()
{
SortedList SL = new SortedList();
SortedList SL2 = new SortedList();
SL.Add(0, "V1");
SL.Add(1, "V2");
SL.Add(2, "V3");
SL.Add(3, "V4");
SL.Add(4, "V5");
SL2.Add(0, richTextBox1.Text);
SL2.Add(1, richTextBox1.Text);
SL2.Add(2, richTextBox1.Text);
SL2.Add(3, richTextBox1.Text);
SL2.Add(4, richTextBox1.Text);
bool equal = Compare(SL, SL2);
if (equal)
{
richTextBox2.Text = "Right";
}
else
{
richTextBox2.Text = "They differ";
}
}
static bool Compare(SortedList SL, SortedList SL2)
{
if (SL.Count != SL2.Count)
{
return false;
}
foreach (KeyValuePair<object, string=""> item in SL)
{
if (!SL.Contains(item.Key))
{
// Return the moment we find a difference
return false;
}
}
// Must be the same
return true;
}
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Change KeyValuePair<> to DictionaryEntry.
Remember to use the "code" and "pre" tags when posting code.
Scott P
"Run for your life from any man who tells you that money is evil. That sentence is the leper's bell of an approaching looter." --Ayn Rand
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That worked, but now everything is equal or correct, even if I type in a wrong string.
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I was waiting for you to get to that. You are comparing the Keys to both lists, not the Values. And the Keys in both lists are identical. Your compare function needs work.
Scott P
"Run for your life from any man who tells you that money is evil. That sentence is the leper's bell of an approaching looter." --Ayn Rand
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Firstly, take more than a minute and consider the problem. Give it like ten.
"Run for your life from any man who tells you that money is evil. That sentence is the leper's bell of an approaching looter." --Ayn Rand
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Which I have.
This is the Compare code. I suspect it has something to do with the bold text. BUt I can´t put my finger on it.
static bool Compare(SortedList SL, SortedList SL2)
{
if (SL.Count != SL2.Count)
{
return false;
}
foreach (DictionaryEntry item in SL)
{
if (!SL.ContainsKey(item.Key))
{
return false;
}
}
return true;
}
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Is this homework?
"Run for your life from any man who tells you that money is evil. That sentence is the leper's bell of an approaching looter." --Ayn Rand
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Not really, I am taking a course in C# but this is more of a side project I´d like to finish.
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Here's a hint - you're reading from the SL sorted list, and then checking to see if the same sorted list contains the key. Change it to point to the right list:
foreach (DictionaryEntry item in SL)
{
if (!SL2.ContainsKey(item.Key))
{
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Hmmmm....
This seems like an Equality problem...
"Run for your life from any man who tells you that money is evil. That sentence is the leper's bell of an approaching looter." --Ayn Rand
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Equality... Equality... Equality...
A is equal to B if A = B and B = A
"Run for your life from any man who tells you that money is evil. That sentence is the leper's bell of an approaching looter." --Ayn Rand
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But it's a list. That'll bugger things up.
A.items == B.items & B.items = A.items
Duplicates could mess you up.
pseudocode:
foreach thingy in A{
make sure thingy is in B.Thingies
}
foreach thingy in B {
make sure thingy is in A.Thingies
}
Help any?
"Run for your life from any man who tells you that money is evil. That sentence is the leper's bell of an approaching looter." --Ayn Rand
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not really, if you could incorporate it into the Compare code I posted it may shed some light.
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I'm not going to write code for you, call it tough love.
Again, I'll write pseudo code for you, you're supposed to be writing it to learn.
using SortedList, in this case you can go through by INDEX and check to see if the elements that life in the INDEXES match.
for(0 to elements){
if a[index] != b[index], return false.
}
return true.
Hope this helps.
"Run for your life from any man who tells you that money is evil. That sentence is the leper's bell of an approaching looter." --Ayn Rand
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what do you mean by 0 to elements?
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Alright.. you have two lists of KeyValuePairs.
Say they're identical.
List1 = [1,A],[2,B],[3,C],[4,D]
List2 = [1,A],[2,B],[3,C],[4,D]
When you have 2 sorted lists, you can use the index to do the check and not the foreach loop.
if(List1.Count != List2.Count) return false;
for(int i = 0 ; i < List1.Count ; i++){
if(List1[i] != List2[i]) return false;
}
return true;
And you can see when you write the problem out exactly how it happens.
Example 2 Inequal list lengths.
List1 = [1,A],[2,B],[3,C],[4,D]
List2 = [1,A],[2,B],[3,C],[4,D],[5,E]
the comparison of lengths returns false. OK.
Example 3 Inequal lists
List1 = [1,A],[2,B],[3,C],[4,D]
List2 = [1,A],[2,B],[3,C],[5,E]
remember that these are sorted, so we're COUNTING on the order.
List lengths, ok, continue.
List1[0] == List2[0] TRUE
List1[1] == List2[1] TRUE
List1[2] == List2[2] TRUE
List1[3] == List2[3] FALSE
Lists inequal, ok.
Remember that the contents of the list are important, so you have to check both the key and the value in your KeyValuePair.
B.Key == A.Key && B.Value == A.Value
Hope this helps some more.
"Run for your life from any man who tells you that money is evil. That sentence is the leper's bell of an approaching looter." --Ayn Rand
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static bool Compare(SortedList SL, SortedList SL2)
{
if(SL.Count != SL2.Count) return false;
for(int i = 0 ; i < SL.Count ; i++)
{
if(SL[i] != SL2[i]) return false;
}
return true;
Is that right?
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Hi all
I would like to use C# serialization classes to serialize the following, but I am quite crazy about how to do that!
I tried a lot of combination of Xml attributes, but notone was good!
Data types in variable are not the same..once they are string, then are float..etc..
Have you any idea?
Kind Regards
Emanuele
<Variable>
<Parameter>
<variable name="FirstVar"> 10.20</variable>
<variable name="SecondVar"> 10.22</variable>
<variable name="ThirdVar"> 10.23</variable>
<variable name="FourthVar"> false</variable>
<variable name="SixthVar"> 10.32</variable>
</Parameter>
</Variable>
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