C#

DaveyM69 wrote:

float b = float.Parse(decimal.Parse(a).ToString("N4"));

DaveyM69 wrote:

This seems a little clumsy but it works
float b = (float)Math.Round(decimal.Parse(a), 4);

DaveyM69 wrote:

The Math.Round method uses 'Bankers Rounding' which may not acheive the result you require. If not you may need to use this which is even clumsier
float b = float.Parse(decimal.Parse(a).ToString("N4"));

Guffa wrote:

Why is there no base64 and serializing to xml in there?

float b = Convert.ToSingle(a);
int b4= (int)(10000.0*b+0.5);
b=0.0001*b4;

public static double GetValue(string what)
      {
          return multiplierDivider * (int)(multiplier * Convert.ToSingle(what) + 0.5);
      }

Luc Pattyn wrote:

The bankers rounding, is that what you want?? (you do realize it produces even numbers only?)

Luc Pattyn wrote:

And I never understood the advantage, if any, of the banker's rounding.