C# Discussion Boards - CodeProject

SQl

r.kh2-Mar-09 18:41

r.kh

2-Mar-09 18:41

how do i enter a record to database(table) by datagrid/.

Re: SQl

Naveed7272-Mar-09 18:43

Naveed727

2-Mar-09 18:43

http://www.google.com.pk/search?q=enter+a+record+to+database(table)+by+datagrid&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a[^]

have fun

My Regular expression stop at $ sign

Naveed7272-Mar-09 18:34

Naveed727

2-Mar-09 18:34

I am using following string..
Searching text er's community and total budget is $16/page.

The regular expression I am using is "[^$]*"
but it only get "Searching text er's community and total budget is " not getting the whole string.
it means it stop at $ sign what changes I should made to get the whole string.

Thanks in advance Smile | :)

Re: My Regular expression stop at $ sign

PIEBALDconsult2-Mar-09 18:45

PIEBALDconsult

2-Mar-09 18:45

You told it to take everything up to the first $ and stop there, what did you expect?

You want a RegEx to take the whole string you already have? Why?

Re: My Regular expression stop at $ sign

Naveed7272-Mar-09 18:48

Naveed727

2-Mar-09 18:48

Actually this is a part of a big string in which I am searching for something but it stop at $ sign if you resolve this issue then it will helpful for me.
Thanks

Re: My Regular expression stop at $ sign

PIEBALDconsult2-Mar-09 18:51

PIEBALDconsult

2-Mar-09 18:51

Then more information is required. What is the string, and what part do you want? Are there many strings?

Re: My Regular expression stop at $ sign

Shyam K Pananghat2-Mar-09 20:56

Shyam K Pananghat

2-Mar-09 20:56

This will just pick up the whole string and stops.. as per your command .. So why do you need this expression then. Please try to undestand some basics of RegeX here.

http://www.codeproject.com/KB/dotnet/regextutorial.aspx[^]

Smile | :)

Shyam..

My Blog dotnetscoups.blogspot.com

Repost : WMI query doesnot return record for user having less previleges!!

Cracked-Down2-Mar-09 18:28

Cracked-Down

2-Mar-09 18:28

This is re posted question

Hi all,
I am trying to retrieve the Disk partitions using the following code lines

foreach (ManagementObject mgmObj in gmtObjo.GetRelated("Win32_DiskPartition"))
{
//get the logical partitions and add to collection

}

This code snippet works well for user having administrative privileges on the machine.However,user having less privileges it does not retrieve any record.

I have searched through net and got the solution where we have to give the permission to the WMI itself using WMITool.However,this solution seems like not feasible as I can not give the permission to client machine.

I am looking for solution using which I would able to fetch the records irrespective of what user privileges are.Either through script or setting the privileges through code(setting through code might again require admin rights...).

Anybody here had faced this problem before or have solution to this??

Help will be appreciated!!!

Thanks in advance

Blocking TCP/IP Client Server

astrovirgin2-Mar-09 17:48

astrovirgin

2-Mar-09 17:48

Hi,
I am working on a blocking client/server architecture.I have a client which sends XML files to the server. It sends many XML files continuously (5 to 10 files per second) to the server using blocking communication method through TCP/IP. What I have to do is to read the XML file and store it in a queue and if the XML file is valid or invalid, give the response back to the client that the file is valid or invalid from the same communication path from where it come. Can anyone help me in this regard that how to acheive that. I am comfortable with queue, just want to know how to send the response back to the client using the same communication path from where the XML file comes.

Thanks in advance.

Re: Blocking TCP/IP Client Server

Jimmanuel3-Mar-09 3:48

Jimmanuel

3-Mar-09 3:48

If you can already send files over a TCP socket from one computer to another then what's the problem you're having sending a message back over the same channel?

Re: Blocking TCP/IP Client Server

mcldev10-Mar-09 10:57

mcldev

10-Mar-09 10:57

There pleny of good code examples, look for TCP Queue IO or QIO.

Client Server Comm

mrithula82-Mar-09 17:45

mrithula8

2-Mar-09 17:45

//This is the server code im using

using System;
using System.Net;
using System.Net.Sockets;
using System.Text;
public class UdpServer
{
    public static void Main()
    {try
        {
            int recv;
            byte[] data = new byte[1024];
            IPEndPoint ipep = new IPEndPoint(IPAddress.Parse("127.0.0.1"), 9050);
Socket newsock = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, ProtocolType.Udp);
            newsock.Bind(ipep);
            Console.WriteLine("Waiting for a client...");            
            IPEndPoint sender = new IPEndPoint(IPAddress.Parse("127.0.0.1"), 9050);
            EndPoint tmpRemote = (EndPoint)(sender);
            recv = newsock.ReceiveFrom(data, ref tmpRemote);
            Console.WriteLine("Message received from {0}:", tmpRemote.ToString());
            Console.WriteLine(Encoding.ASCII.GetString(data, 0, recv));
            data = new byte[1024];
            string ss = "Welcome to the Server";
            data = Encoding.ASCII.GetBytes(ss);
            newsock.SendTo(data, data.Length, SocketFlags.None, tmpRemote);
            Console.WriteLine("\nSent Acknowledgement");
           // newsock.Close();           
        }
        catch (Exception e)
        {
            Console.WriteLine("Error..... " + e.StackTrace);
        }
       // Console.ReadLine();      
    }
}

//This is the client code which im calling inside a button click event

private void Send_Click(object sender, EventArgs e)
       {
           Callback();}
       private void Callback()
       {try
           {
               byte[] data = new byte[1024];
               listBox3.Items.Add("Connecting....");
               IPEndPoint ipep = new IPEndPoint(IPAddress.Parse("127.0.0.1"), 9050);
      Socket server = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, ProtocolType.Udp);
               listBox3.Items.Add("Connected");
               data = Encoding.ASCII.GetBytes("hello");
               listBox3.Items.Add("Transmitting...");
               server.SendTo(data, data.Length, SocketFlags.None, ipep);//sent hello
               listBox3.Items.Add("Sent...");
     IPEndPoint sender = new IPEndPoint(IPAddress.Parse("127.0.0.1"), 9050);
               EndPoint tmpRemote = (EndPoint)sender;
               listBox3.Items.Add("Message received from {0}:");
               listBox3.Items.Add(tmpRemote.ToString());
               data = new byte[1024];
               int recv = server.ReceiveFrom(data, ref tmpRemote);
               listBox3.Items.Add(Encoding.ASCII.GetString(data,0,recv));
               //listBox3.Items.Add("Stopping client");
               //server.Close();}
           catch (Exception e)
           {
               Console.WriteLine("Error..... " + e.StackTrace);
           }
           Console.ReadLine();}

When i run this code:
My form design is as follows:
With a button click i list the drives in the system,then with another button click i list the folders in each drive,and then listing the exe files in the folder..I have set a default path say C:\projects\ports.The ports folders in turn contains many folders like 10000,10001 etc..I have copied the exe file obtained when compiling the Server Application to 10000...So with a button click event i will get the exe of the server application which should act as server and i have defined the client in the Form1.cs..Now when i have another button click the message(which i have defined inside the code)should be sent to the exe(i.e.server) opened...Please check my code and tell me whether i should make any changes.
Right now when i run this application the exe(server)window closes when i click "Send" button to send the message to the exe...Please help me with this

PathGradientBrush - blending multiple colors in an ellipse shape

Richard Blythe2-Mar-09 17:15

Richard Blythe

2-Mar-09 17:15

I'm trying to use the PathGradientBrush to create a gradient blend on an elliptical path. I have been able to partialy achieve that by setting the Interpolation property. However, I'm wanting to control how each color blends into the other as with the LinearGradientBrush's Blend property.

For example, say I want two colors to transition from solid blue to solid red instead of gradually fading into one another. Again, this can be achieved with the LinearGradientBrush.

How can this be done with the PathGradientBrush?

There cannot be a crisis today; my schedule is already full.

Re: PathGradientBrush - blending multiple colors in an ellipse shape

Xmen Real 2-Mar-09 20:23

Xmen Real

2-Mar-09 20:23

Gradient != Solid

TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L
%^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2
W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN%
Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-iTV.C\y<pjxsg-b$f4ia>
--------------------------------------------------------
128 bit encrypted signature, crack if you can

Re: PathGradientBrush - blending multiple colors in an ellipse shape

Richard Blythe3-Mar-09 5:00

Richard Blythe

3-Mar-09 5:00

I'm guessing by your reply that you don't know that answer.

This is a feature that's implemented in many graphics programs, including PhotoShop. It allows the user to control how soft/hard the blend is between two colors.

Can someone who does know the answer please clue me in?

There cannot be a crisis today; my schedule is already full.

Re: PathGradientBrush - blending multiple colors in an ellipse shape

Xmen Real 3-Mar-09 5:04

Xmen Real

3-Mar-09 5:04

well dude, the answer is simple, you cant have solid colors with GradientBrush.

Re: PathGradientBrush - blending multiple colors in an ellipse shape

Richard Blythe3-Mar-09 5:15

Richard Blythe

3-Mar-09 5:15

I'm afraid your probably right. It stinks that the LinearGradientBrush gives you so much more control over blending than the PGB.

If anyone has any further info, please let me know. (that includes you Xmen) Lol

There cannot be a crisis today; my schedule is already full.

server

mrithula82-Mar-09 17:08

mrithula8

2-Mar-09 17:08

Hi,
I have a doubt.If i am using Process.Start() the exe file gets opened.
//Method1
Actually if i am going to run the server from the console,I will use csc /t:exe Server.cs //compile
Server//run
Method2
Previously i defined Server separately and run that file using the console,i defined client in the Form1.cs (which i run using the Start Debugging option).It worked well
Now i have defined client in Form1.cs and try to send message to the server (i.e.exe file).This exe is just opened.Is this exe same as the one obtained by Method1(i.e.exe obtained by using "run" command)?

Re: server

JoseMenendez2-Mar-09 17:13

JoseMenendez

2-Mar-09 17:13

Use ProcessStartInfo, and set UseShellExecute to true
Then you can run the process as you where using the console.

Jm
www.menendezpoo.com

Client-Server

mrithula82-Mar-09 17:07

mrithula8

2-Mar-09 17:07

Hi,
I am working with WindowsApplication in VS.NET 2005
I have listed the folders in a drive...for eg:
C:\projects\ports.ports folder in turn contains 10 other folders namely 10000,10001 etc...
I have created a separate application for the client and server to communicate...I have compiled the server application and copied the exe file into folder 10000 and i have included the client as a function in Form1.cs.
In my tool i.e. VS.NET 2005, i have written code to list exe files in a folder.So it gives me Server.exe with a button click.I wanted to run this exe file...I used Start() to do so. The exe file opens when i click start button.
Now i want to send a message from the client to the server(i.e .exe file opened with a button click).Is it possible to do this?
I had a try with this...When i click send button to send message from the client to the exe ,the exe closes...I have not closed the socket in side th code...I dont know why that happens...
Please help me out with this...Thanks for any help in advance.

Finiding the name of Opened windows which is on task bar

Lijo Rajan2-Mar-09 16:50

Lijo Rajan

2-Mar-09 16:50

Hi all,

I want to find out the name and path if all opened windows which is on task bar. Can anyone help me to get that???

Regards
Lijo

Re: Finiding the name of Opened windows which is on task bar

ABitSmart2-Mar-09 17:13

ABitSmart

2-Mar-09 17:13

See here[^]

Re: Finiding the name of Opened windows which is on task bar

Lijo Rajan2-Mar-09 17:24

Lijo Rajan

2-Mar-09 17:24

Thanks a lot for ur reply. but from that link i will get only process name.i want all application names which is on task bar.can u plse give me little more clear idea on this???
Regards
Lijo

Re: Finiding the name of Opened windows which is on task bar

ABitSmart2-Mar-09 17:41

ABitSmart

2-Mar-09 17:41

Lijo Rajan wrote:
i want all application names which is on task bar

Can you explain a bit more ?

Your orignal question was to get all name of opened windows on task bar. The link provides alternate ways to achieve that. The simplest being,

if (p.MainWindowHandle != 0)<br />
       { // This is a GUI process<br />
       }<br />
       else<br />
       { // this is a non-GUI / invisible process<br />
       }

You get all processes using Process.GetProcesses and then loop to check as above. But there are other better means using Window's API which is also mentioned in the post.

Custom Label OnPaint Override Issue

Member 3966782-Mar-09 16:44

Member 396678

2-Mar-09 16:44

Hi everyone,

I have made a very simple custom control based on the label control.

public class CustomLabel : Label
{
	protected override void OnPaint(PaintEventArgs e)
	{
		//base.OnPaint(e);
		SolidBrush sb = new SolidBrush(ForeColor);
		e.Graphics.DrawString(Text, Font, sb, Margin.Left, Margin.Top, StringFormat.GenericTypographic);
	}
}

Now I have made a form which has one 'CustomLabel' and one 'Label' with exactly the same font.
When the form loads they paint in identical sizes.

If I changed the fonts of both controls like this (scale them by 110%)

label1.Font = new Font(label1.Font.FontFamily,label1.Font.Size * 1.1F,label1.Font.Style);
label2.Font = new Font(label2.Font.FontFamily,label2.Font.Size * 1.1F,label2.Font.Style);

then they begin painting differently. Can anyone help me figure out why even though the two labels
have identical font sizes they draw differently?

Matt

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