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Hi,
I already have Platform SDK installed in win2k in the path c:\psdk.
I want to update the SDK.Do i need to specify the same directory c:\psdk while installing the latest one. Or specify a different path ?
Pls help
Thanks in advance
Ram
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My personal preference would be to remove the old version and install the new version to whatever path I prefered.
Ant.
I'm hard, yet soft.
I'm coloured, yet clear.
I'm fruity and sweet.
I'm jelly, what am I? Muse on it further, I shall return! - David Walliams (Little Britain)
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I agree. Very few items benefit from overwriting.
"Opinions are neither right nor wrong. I cannot change your opinion of me. I can, however, change what influences your opinion." - David Crow
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DWORD __stdcall MEditStreamOutCallback(DWORD dwCookie, LPBYTE pbBuff, LONG cb, LONG *pcb)
{
CString sThisWrite;
sThisWrite.GetBufferSetLength(cb);
CString *psBuffer = (CString *)dwCookie;
for (int i=0;i<cb;i++) {
="" sthiswrite.setat(i,*(pbbuff+i));
="" }
="" *psbuffer="" +="sThisWrite;
" *pcb="sThisWrite.GetLength();
" sthiswrite.releasebuffer();
="" return="" 0;
}
<u="">I use above function to get string form buffer but i have problem.
Assume the string on editor is "##123456789##" and i test MEditStreamOutCallback function with below function
void CRichEgView::OnReadout()
{
CString sReadText; to
EDITSTREAM es;
es.dwCookie = (DWORD)&sReadText; es.pfnCallback = MEditStreamOutCallback;
GetRichEditCtrl().StreamOut(SF_RTF,es); MessageBox(sReadText.Mid(0,500));
}
The string below is the result but i need noly "##123456789## string,please suggest
"{\rtf1\ansi\ansicpg874\deff0\deflang1054{\fonttbl{\f0\fswiss\fprq2\fcharset222 System;}}
\viewkind4\uc1\pard\lang1033\b\f0\fs20 ##123456789##\lang1054\par
}
"}
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Have you tried GetWindowText()?
Ryan "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"
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GetWindowText() so work!!!
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hi,
is there anyway of accessing data in a win Ce other then thought the RAPI function??
i would like to download the database to my PC and access it with an application written in VC++.
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You cannot access directly the database (on the PocketPC) from your desktop computer. But what you can do is first copy it on the desktop computer and then access it. But you will need to convert it during the copy. Take a look at this article to see how to do this ADOCE Filtering[^].
Hope this helps
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thanks... that was helpful.
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Howdy All-
I am just looking for some good words about these 3 topics (together)....
I've been asked to add SNMP support to an application. That is, my application should be able to provide SNMP data to those that ask for it.
Does that make me an SNMP Agent?
or a provider?
Does WMI "just do this" for me? (assuming I hook into WMI appropriately)?
It's a messy world...
Thanks
-p
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br />
Peter Weyzen<br />
Staff Engineer<br />
<A HREF="http://www.santacruznetworks.com">Santa Cruz Networks</A>
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Search MSDN for "SNMP Extension Agent" and "Writing Your Own SNMP Management Information Base for Microsoft Windows CE 3.0". The sample for Windows CE works in Windows NT too. You must install the Windows SNMP agent before try the sample.
TIP. Your extension DLL must depends ONLY from DLLs into the system folder. Even if the DLL that your extension DLL depends are into the same folder (and the folder is not the system folder, p.ex. c:\program files\yourapp  ), the Windows SNMP agent will fail to load your dll ! Only Windows Server 2003's SNMP agent can load the DLL.
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hai..
I have to send a packet to a port..i'm using writefile() to do this..
My packet is 4 bytes 01 43 52 0D all hex values...
how should i do this..
thanks a lot.
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I assume your real question is:
How do I represent this hex data in C++?
unsigned char Data[] = { 0x01, 0x43, 0x52, 0x0D };
const int DataSize = (sizeof(Data)/sizeof(unsigned char));
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<br />
Peter Weyzen<br />
Staff Engineer<br />
<A HREF="http://www.santacruznetworks.com">Santa Cruz Networks</A>
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Hello,
I've added my own hook procedure to an Explorer-Type Open File Dialog and I'm trying to override the lst2 listbox ON_LBN_DBLCLK call to prevent the dialog from taking the one file double clicked on and dismissing the dialog.
What I want to do is re route the ON_LBN_DBLCLK call to a different function.
I have not been able to re route the call using the message map nor with the callback functions, any ideas? Is it even possible to do so?
Thanks,
--Joseph
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I can't find any information how I can
- add my custom template to the OPENFILENAME dialog
- have the "new style" (with the places bar to the left) enabled
I'm adding OFN_ENABLETEMPLATE | OFN_EXPLORER | OFN_ENABLESIZING to the flags, but I get the "old" look (with my child dialog added OK)
we are here to help each other get through this thing, whatever it is Vonnegut jr.
boost your code || Fold With Us! || sighist | doxygen
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Does your definition of OPENFILENAME have the pvReserved, dwReserved and FlagsEx fields? And are you using sizeof(OPENFILENAME) rather than OPENFILENAME_SIZE_VERSION_400 for the lStructSize field? Both of these are necessary to enable the places bar. That's the only thing I can remember about using the places bar 
Ryan "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"
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peterchen wrote:
- have the "new style" (with the places bar to the left) enabled
First you'll need to set _WIN32_WINNT to 0x0500 so that you'll have access to the FlagsEx member of OPENFILENAME. Second, you'll not be able to do this using CFileDialog. You'll need to use GetOpenFileName() without a hook procedure.
"Opinions are neither right nor wrong. I cannot change your opinion of me. I can, however, change what influences your opinion." - David Crow
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I don't understand the following code. Could someone please explain it to me?
struct SomeStruct
{
union
{
unsigned int field;
struct
{
unsigned x: 1;
unsigned y: 1;
unsigned z: 1;
unsigned space: 3;
};
};
};
I am guessing that this is making use of Anonymous Unions.
There is a struct containing a union containing a struct... confusing.
Also I don't understand this notation "unsigned x: 1;", what is this saying?
My best guess that field would tell you which variable to use and then you would access it like:
SomeStruct mystruct;
For example if field donoted using x you would access by mystruct.x ??
Finally, is this C/C++ or just for C++?
Thanks
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smesser wrote:
I am guessing that this is making use of Anonymous Unions.
You are correct.
smesser wrote:
Also I don't understand this notation "unsigned x: 1;", what is this saying?
That the variable only occupies 1 bit.
smesser wrote:
For example if field donoted using x you would access by mystruct.x ??
Correct. In this particular example, accessing member x would also be accesssing one bit of member field. That's the whole premise of a union. All members start at the same address because a union variable can contain only one of its members at a time.
smesser wrote:
Finally, is this C/C++ or just for C++?
Unions are used in both languages. The difference comes in how you declare union variables. With C, you must use the union keyword. In C++, the union keyword is unnecessary.
"Opinions are neither right nor wrong. I cannot change your opinion of me. I can, however, change what influences your opinion." - David Crow
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Thanks for your answer.
So your saying that each item in the union occupies 1 bit so then space is the total number of bits or it is the total number of choices?
So if I want to create a variable to store this data I would just do this?
bool my_x = mystruct.x;
Sorry, for the dumb questions. I have never used unions before much less anonymous ones.
Thanks
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Not quite. Read the other replys.
Each item in the union STARTS at the same place. They are used either when you know that of two different variables only one is needed (but which one is not known in advance), or when you want to use the same data in different ways. In your case, field takes 32 bits, on a 32 bit system. x represents bit 1 of field, y represents bit 2, and space represents 4-6.
if you do:
struct somestruct mystruct;
mystruct.field = 0xa8000000;
than field (dropping the last 24 bits which are all 0) contains the following in binary:
10101000
Therefore
mystruct.x == 1
mystruct.y == 0
mystruct.z == 1
mystrict.space = 2
(Note, double check this, I might have the layout backwards. I cannot remember this unless I'm deep into such code)
Bitfields almost always make your program larger and slower than just using an int. Therefore the only time you normally see them is in networking and hardware. Both are cases where limits in transfer speed or length are far more important that CPU time or memory. It is generally not worth your time to use them elsewhere.
Warning, whenever you see data structures like this, the author knew something about the exact hardware in question! There are dragons lurking for anyone who trys to run this on anything else without a lot of care. If you do not understand what I'm getting at, stick to less advanced programs. Many programers get by without ever needing to deal with bitfiels.
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Your question poses a number of interesting points 
I am guessing that this is making use of Anonymous Unions.
Yes. An anonymous union is just a way to tell the compiler that the enclosed members share the same storage. For instance:
union{
int x;
int y;
}
x=100;
cout<<y; Here, we've used an anonymous union to locally declare two variables sharing the same position in memory. Most of the time, anonymous unions are used for type definition inside a struct:
struct foo{
union{
int x;
int y;
};
};
foo f;
f.x=100;
cout<<f.y; Also I don't understand this notation "unsigned x: 1;", what is this saying?
This is an orthogonal feature called bitfields. By adding a bitfield specification to a member, we instruct the compiler to use the indicated bits for storage instead of what it normally would take to store the member. For instance:
struct foo{
unsigned x:2;
unsigned y:2;
unsigned z:2;
unsigned w:2;
};Here, member variables x, y, z and w will take only two bits each, and the resulting foo will only occupy one byte (alignment issues aside.) Of course, these variables will not be able to hold a value greater than what can be expressed with two bits (3) --the compiler cannot do miracles.
What do we have if we combine these two features?
struct SomeStruct{
union{
unsigned int field;
struct{
unsigned x: 1;
unsigned y: 1;
unsigned z: 1;
unsigned space: 3;
};
};
};By virtue of the anonymous union, field will share the same storage as x, y, y and space. And because we are using bitfields on those, the overall effect is that SomeStruct.x will refer to the first bit of SomeStruct.field, SomeStruct.y to the second bit, etc. Got it? This kind of constructs (which are very low-level and depend on non-portable issues like type alignment, size of primitive types, big- or little-endiannness, etc.) are commonly used to reproduce bit-specified data structures like those you can find in some data protocols (for instance, TCP data units), and allow the programmer to handle the data at the sub-byte level.
Finally, is this C/C++ or just for C++?
Neither This construct relies on what we could call an "anonymous struct":
struct{
unsigned x: 1;
unsigned y: 1;
unsigned z: 1;
unsigned space: 3;
};Alas, anonymous structs are not standard C or C++, though MSVC admits them. Apart from this, the rest is C/C++ (though its usage would differ in minor syntactic issues.)
Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo
Want a Boost forum in Code Project? Vote here[^]!
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Thanks for another very good explanation.
Then, Why would one put at the end of the union:
unsigned space : 3
Which just seems to be the total bits in the union is this the case and why would you do it?
So, then to access anything from:
So, to access x,y, or z you would:
SomeStuct mystruct;
int my_x = mystruct.x;
int my_y = mystruct.y;
int my_z = mystruct.z;
How would you get the values from field ?
Thanks
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At a guess the unsigned space:3 is a mistake. I expect what space is meaning to contain is the other bits that an unsigned int occupies. On 32-bit machines space would be 29, i.e. 32 - 1 - 1 - 1 = 29.
smesser wrote:
How would you get the values from field ?
unsigned int my_field = mystruct.field;
Or do you mean how do you get x, y and z from mystruct.field?
Ant.
I'm hard, yet soft.
I'm coloured, yet clear.
I'm fruity and sweet.
I'm jelly, what am I? Muse on it further, I shall return! - David Walliams (Little Britain)
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Actually here is the actual struct
typedef struct
{
union
{
unsigned int field;
struct
{
unsigned xyz_offset: 1;
unsigned collision_fwd_fuselage: 1;
unsigned collision_aft_fuselage: 1;
unsigned collision_lt_wing: 1;
unsigned collision_rt_wing: 1;
unsigned collision_lt_tail: 1;
unsigned collision_rt_tail: 1;
unsigned collision_vt_tail: 1;
unsigned collision_lt_gear: 1;
unsigned collision_rt_gear: 1;
unsigned collision_nose_gear: 1;
unsigned collision_prop1: 1;
unsigned collision_prop2: 1;
unsigned collision_prop3: 1;
unsigned collision_prop4: 1;
unsigned weapon_strike: 1;
unsigned space: 16;
};
};
}CollisionType;
Yes, I wanted to get x,y, and z.
I think you would do it like this:
For example:
if( mystruct.x )
{
do_x_stuff();
}
if( mystruct.y )
{
do_y_stuff();
}
if( mystruct.z )
{
do_z_stuff();
}
Since each bit is either on or off I believe this would work.
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