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Actually according to my application it is so easy to use as char *, as a buffer. Is it easy for my requirement?
I appreciate your help all the time...
Eranga 
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Take a look at the Mid function[^] (and similar functions like Right and Left
EDIT: BTW, in the documentation there's always the list of all available methods. And in general, the name of the functions are quite explicit.
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Hmm, thats seems to me easy. I'll try it now. Let see. Thanks pal.
I appreciate your help all the time...
Eranga
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Hello all,
I want to count perticular character in String.
I had made it by for loop but it takes to much time. Is there any in built function availale?
Thanks in advance.
Manish Patel.
B.E. - Information Technology.
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If you want to get length of a string you can use of CString::GetLength().Is this your question?
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No,
I am using BYTE * and i want to know how many times perticular char is repeated in that buffer.
Any idea?
Manish Patel.
B.E. - Information Technology.
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Why are you using a BYTE array to store characters ? Do you need to store characters or unsigned characters ?
Can you post the code of your loop, because it shouldn't take too much time to check each character of your string (except if it is exceptionally long).
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I am storing bytes in buffer. And its too long. Thats why i need for in built function.
Any idea?
i had done like this:
int countByte(BYTE *src, BYTE b)<br />
{<br />
int count = 0;<br />
for(int i = 0; i < strlen((char *)src); i++)<br />
if(src[i] == b)<br />
count++;<br />
return count;<br />
}
Any Suggestion..
Manish Patel.
B.E. - Information Technology.
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Is your buffer NULL-terminated ? If no, then there is a big problem because strlen calculates the lenght of the string by counting the number of characters until it finds a 0.
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Ya, My string is NULL terminated.
My function working properly but it takes to much time for string length greater than 10000.
Please provide me any idea to decrease this time.
Manish Patel.
B.E. - Information Technology.
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//this one should run faster
int countByte(BYTE *src, BYTE b)
{
int count = 0;
int i = 0;
while( src[i] )
{
if(src[i] == b)
count++;
i++;
}
return count;
}
Greetings from Germany
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Wow its working fine.
Thanks a lot.
Manish Patel.
B.E. - Information Technology.
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It was taking so much time because at each iteration of your for loop, you call strlen. And strlen is basically just a loop that counts the number of characters until a 0 is encountered. So, redoing that at each iteration is quite costly.
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<br />
typedef unsigned char BYTE;<br />
<br />
int countByte(BYTE *src, BYTE b)<br />
{<br />
int count = 0;<br />
BYTE *s;<br />
for (s=src;*s; s++)<br />
if (*s == b)<br />
count++;<br />
return count;<br />
} <br />
<br />
int _tmain(int argc, _TCHAR* argv[])<br />
{<br />
char s[20] = "111222333";<br />
printf("%d",countByte((BYTE*)s,'1'));<br />
return 0;<br />
}<br />
This version eliminates the strlen call and it eliminates the use of the square brackets []. Each time you use the square bracket array index, an offset into your array has to be calculated.
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Hi Friends
I anybody have an idea to create a window, that is appeared in top of other windows. ie timeline slider in Windows Movie Maker
thanx in advance
-RisKhan-
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You can use of SetWindowPos for set it to top.
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thanks hamid. One more question, how to create a shapeless window. Do u have idea
thanks
-RisKhan-
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when create a dialog based MFC project defaultly, we have the OK, cancel buttons in the topright corner, I want to create a CListBox dynamicly and place it in the position relative to the IDOK button( the top cordination of CListBox is the same as IDOK), so I write my code like below:
first, construct a CListBox in the .h file
CListBox m_ctlBox;
then, within the OnInitDialog
BOOL CMyDialog::OnInitDialog()
{
CDialog::OnInitDialog();
m_ctlBox.Create(STYLE, CRect(0, 0, 0, 0), rightcode);
m_ctlBox.ShowWindow(SW_HIDE);
CRect rcOK;
GetDlgItem(IDOK)->GetWindowRect(&rcOK);
int nBoxWidth = 30;
int nBoxHeight = 40;
int nxMargin = 10;
int nBoxTop = rcOK.top;
int nBoxLeft = rcOK.left - nxMargin - nBoxWidth;
m_ctlBox.SetWindowPos(&CWnd::wndTop, nBoxLeft, nBoxTop, nBoxWidth, nBoxHeight, SWP_SHOWWINDOW);
m_ctlBox.ShowWindow(SW_SHOW);
return TRUE;
}
but the m_ctlBox's top is not as IDOK's. Really confused with how to use GetClientRect 、GetWindowRect、ScreenToClient and ClientToScreen correctly to set window position correctly.
So I can't write my code to deal with WM_SIZE correctly.
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GetWindowRect() gets coords relative to the screen.
SetWindowPos() is expecting coords relative to the parents client area.
BOOL CMyDialog::OnInitDialog()
{
CDialog::OnInitDialog();
m_ctlBox.Create(STYLE, CRect(0, 0, 0, 0), <font color="Red">this</font>);
m_ctlBox.ShowWindow(SW_HIDE); <font color="Green">
CRect rcOK;
GetDlgItem(IDOK)->GetWindowRect(&rcOK);
int nBoxWidth = 30;
int nBoxHeight = 40;
int nxMargin = 10;
<font color="Red"> CPoint BoxUpperLeft;
BoxUpperLeft.y = rcOK.top;
BoxUpperLeft.x = rcOK.left - nxMargin - nBoxWidth;
ScreenToClient(&BoxUpperLeft); <font color="Green">
</font> m_ctlBox.SetWindowPos(&CWnd::wndTop, <font color="Red">BoxUpperLeft.x</font>, <font color="Red">BoxUpperLeft.y</font>, nBoxWidth, nBoxHeight, SWP_SHOWWINDOW);
m_ctlBox.ShowWindow(SW_SHOW);
return TRUE;
}Mark
Mark Salsbery
Microsoft MVP - Visual C++
![Java | [Coffee]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/coffee.gif)
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Question NO.1
BOOL CMyDialog::OnInitDialog()
{
CDialog::OnInitDialog();
m_ctlBox.Create(STYLE, CRect(0, 0, 0, 0),this);
m_ctlBox.ShowWindow(SW_HIDE);
CRect rcOK;
GetDlgItem(IDOK)-><big><font color="red">GetWindowRect</font></big>(&rcOK);
int nBoxWidth = 30;
int nBoxHeight = 40;
int nxMargin = 10;
CPoint BoxUpperLeft;
BoxUpperLeft.y = rcOK.top;
BoxUpperLeft.x = rcOK.left - nxMargin - nBoxWidth;
<big>this->ScreenToClient(&BoxUpperLeft)</big>
<font color=blue>
</font>
m_ctlBox.SetWindowPos(&CWnd::wndTop, BoxUpperLeft.x, BoxUpperLeft.y, nBoxWidth, nBoxHeight, SWP_SHOWWINDOW);
m_ctlBox.ShowWindow(SW_SHOW);
return TRUE;
}
Question NO.2
and how to do it with GetClientRect()?
BOOL CMyDialog::OnInitDialog()
{
CDialog::OnInitDialog();
m_ctlBox.Create(STYLE, CRect(0, 0, 0, 0),this);
m_ctlBox.ShowWindow(SW_HIDE);
CRect rcOK;
GetDlgItem(IDOK)-><big><font color="red">GetClientRect</font></big>(&rcOK);
int nBoxWidth = 30;
int nBoxHeight = 40;
int nxMargin = 10;
CPoint BoxUpperLeft;
BoxUpperLeft.y = rcOK.top;
BoxUpperLeft.x = rcOK.left - nxMargin - nBoxWidth;
m_ctlBox.SetWindowPos(&CWnd::wndTop, BoxUpperLeft.x, BoxUpperLeft.y, nBoxWidth, nBoxHeight, SWP_SHOWWINDOW);
m_ctlBox.ShowWindow(SW_SHOW);
return TRUE;
}
-- modified at 2:40 Wednesday 21st November, 2007
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Before going into your question,
GetWindowRect(..) will return the window rect with respect to screen cooridates.
GetClientRect(..) will return the client area of the window, that is regardless of its position the top left point is 0, 0 and right, bottom point is its width and height respectivly
Now for Question 1:
You got the screen coordinate of OK button, now you have to find its coordinate with respect to the dialog and not with the listbox.
For Question 2:
As i said earlier, if you use GetClientRect(..), simply it will return width and height. By knowing only the width and height you can't find its starting (top,left) coordinate.
Do your Duty and Don't expect the Result
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When I see the explaination of the API ::ScreenToClient(), I understand clearly.
GetDlgItem(IDOK)->GetWindowRect(&rcOK);
First, rcOK's coordinates are relative to the upper left of the display screen.
Then compulate the position of the CListBox to the coordinates relative to display screen.
Next we need convert the screen coordinates of the CListBox to the coordinates in the main Dialog's client coordinates.
<br />
BOOL ScreenToClient(<br />
HWND hWnd,
LPPOINT lpPoint
);<br />
hWnd <br />
[in] Handle to the window <big><font color="red">whose client area will be used </font></big> for the conversion.
so we should pass the dialog's hWnd.
BOOL CMyDialog::OnInitDialog()
{
CDialog::OnInitDialog();
m_ctlBox.Create(STYLE, CRect(0, 0, 0, 0),this);
m_ctlBox.ShowWindow(SW_HIDE);
CRect rcOK;
GetDlgItem(IDOK)->GetWindowRect(&rcOK);
int nBoxWidth = 30;
int nBoxHeight = 40;
int nxMargin = 10;
CPoint BoxUpperLeft;
BoxUpperLeft.y = rcOK.top;
BoxUpperLeft.x = rcOK.left - nxMargin - nBoxWidth;
::ScreenToClient(this->m_hWnd, &BoxUpperLeft);
<font color="red">
m_ctlBox.SetWindowPos(&CWnd::wndTop, BoxUpperLeft.x, BoxUpperLeft.y, nBoxWidth, nBoxHeight, SWP_SHOWWINDOW);
m_ctlBox.ShowWindow(SW_SHOW);
return TRUE;
}
If somewhere is wrong, please correct me! thx.
-- modified at 0:17 Thursday 22nd November, 2007
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There's not an API (or CWnd method) I know of to get the rect of a window relative
to its parent, so your GetClientRect() method isn't going to give you the info you need.
Remember, the window rect is the outer bounding rect of the window. The client rect
is the interior of the window, excluding borders, title bar, menu, and other "decorations".
As Parthi mentioned, the client rect's upper left coord is always 0,0.
Controls are windows, so the same rules apply.
About Windows[^]
MapWindowPoints()[^]
Mark
Mark Salsbery
Microsoft MVP - Visual C++
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<br />
class CMyEdit:public CEdit<br />
<br />
void CMyEdit::OnKeyDown(UINT nChar, UINT nRepCnt, UINT nFlags)<br />
{<br />
CEdit::OnKeyDown(nChar, nRepCnt, nFlags);
CString s;<br />
GetWindowText(s);
}<br />
I want to use the WindowText as soon as the text is changed, any way?
Thanks.
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