Android

Re: Access MySql using php script from Android app..

19-Sep-17 9:47

Member 13416547 wrote:
Strangely debug (IOException) value is blank.

Where are you catching this at? I do not see any reference to it in the code snippet you've shown.

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Member 1341654720-Sep-17 16:03

Member 13416547

20-Sep-17 16:03

Sorry David, below is the full function. When I run the app on the phone it just closes down. (I reworked code and it doen't go to CATCH now.) If I comment out the

connection.connect();

line, it runs thru with no error. If I paste the url (http://xxx.xxx.xxx/myscript.php) into a browser it works and inserts a record into my table.

private void  Testphp2() {
    try {

        URL url;
        HttpURLConnection connection = null;
        url = new URL("http://xxx.xxx.xxx/myscript.php");
        connection = (HttpURLConnection) url.openConnection();
        connection.setReadTimeout(3000);
        connection.setConnectTimeout(3000);
        connection.setRequestMethod("POST");
        connection.setDoInput(true);
        Toast.makeText(getApplicationContext(), "About to try", Toast.LENGTH_LONG).show();
        connection.connect();
        Toast.makeText(getApplicationContext(), "Success", Toast.LENGTH_LONG).show();

    } catch (IOException e) {
        e.printStackTrace();
        Toast.makeText(getApplicationContext(), "error" , Toast.LENGTH_LONG).show();
    }
}

Re: Access MySql using php script from Android app..

Member 1341654720-Sep-17 19:24

Member 13416547

20-Sep-17 19:24

I just saw this video which indicated I need to use an AsyncTask. if that is required then that is my issue I think.
How to Connect Android with PHP, MySQL - Best Android Studio Tutorial 2017 - YouTube[^]

Re: Access MySql using php script from Android app..

David Crow20-Sep-17 16:52

Re: Access MySql using php script from Android app..

20-Sep-17 16:52

Member 13416547 wrote:
(I reworked code and it doen't go to CATCH now.)

Because you are trying to catch a specific exception. Try using Exception instead. Have you considered the exception's getMessage() method?

Also, I suggest using Log.d() calls instead of popping up Toast messages when debugging.

Member 1341654723-Sep-17 15:03

Member 13416547

23-Sep-17 15:03

Thanks David, I will look at using Exception & getMessage as well as log.d (I am new to android dev as you can probably tell.)

FCM notification

Malashree Halade9-Sep-17 3:26

Malashree Halade

9-Sep-17 3:26

if any one know then tell me.
when application is in background, then how to read notification?

David Crow9-Sep-17 4:55

9-Sep-17 4:55

Notification messages are only received in onMessageReceived() when the app is in the foreground. When the app is in the background, an automatically generated notification is displayed. When the user taps on the notification they are returned to the app.

Malashree Halade9-Sep-17 5:38

Malashree Halade

9-Sep-17 5:38

Thanks for reply.
But actually I want to update one value in sqlite after getting a notification. I had done code with this in message received method but problem is that, when app is in background, then I will get notification but can't update value in sqlite.
So tell me any solution.

Malashree Halade9-Sep-17 5:41

Malashree Halade

9-Sep-17 5:41

Otherwise tell me how to get text or title from notification.
Or notification on click listener.

David Crow9-Sep-17 14:31

for googple map serach location

9-Sep-17 14:31

Malashree Halade wrote:
Otherwise tell me how to get text or title from notification.

The RemoteMessage parameter that is passed to onMessageReceived().

See here for more.

Member 133938216-Sep-17 2:23

Member 13393821

6-Sep-17 2:23

i wnt some link which i got android app develoment .

Re: for googple map serach location

David Crow6-Sep-17 3:14

Re: for googple map serach location

6-Sep-17 3:14

Richard MacCutchan6-Sep-17 3:55

Richard MacCutchan

6-Sep-17 3:55

Have you tried Google? Have you tried the CodeProject articles section?

Re: for googple map serach location

thatraja6-Sep-17 4:33

thatraja

6-Sep-17 4:33

huh?

thatraja

Coming soon1 | Coming soon2 | Coming soon3^New

Issue navigating to a Fragment

Vimalsoft(Pty) Ltd3-Sep-17 10:56

(View) in a parent or ancestor Context for android:onClick attribute defined on view class Button

3-Sep-17 10:56

Good Day All

i have a Navigation Drawer which is defined like this

<FrameLayout
                android:id="@+id/content_frame"
                android:layout_width="match_parent"
                android:background="#0099ff"
                android:layout_height="fill_parent" />

and when one of my drawer item is selected i have this code

// Create a new fragment and a transaction.
                        FragmentTransaction fragmentTx = this.FragmentManager.BeginTransaction();
                        Fragment1 aDifferentDetailsFrag = new Fragment1(); 
                        // The fragment will have the ID of Resource.Id.fragment_container.
                        fragmentTx.Add(Resource.Id.content_frame, aDifferentDetailsFrag);

<pre>
                    // Commit the transaction.
                    fragmentTx.Commit();
                    Toast.MakeText(this, "Home:", ToastLength.Long).Show();</pre>

and Fragment1 is defined like this

<?xml version="1.0" encoding="utf-8"?>
<ScrollView xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:local="http://schemas.android.com/apk/res-auto"
    android:layout_width="match_parent"
    android:layout_height="match_parent"

<pre>
android:paddingLeft="12dp"
        android:paddingRight="12dp">

    <Button
        android:textSize="24dp"
        android:textColor="#FFF"
        android:id="@+id/btn_details_file_save"
        android:layout_width="match_parent" 
        android:layout_height="wrap_content"
        android:text="HOME" />

and the cs is defined like this

public class Fragment1 :  Fragment
    {

<pre>
    public override void OnCreate(Bundle savedInstanceState)
    {
        base.OnCreate(savedInstanceState);

        // Create your fragment here
    }
    public override View OnCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState)
    {
        return inflater.Inflate(Resource.Layout.Fragment1, null, false); 
    }
}</pre>

when i run this , i only get a toast message, the Fragment1 does not show which has a button that is having text "home"

Thanks

Vuyiswa Maseko,

Spoted in Daniweb-- Sorry to rant. I hate websites. They are just wierd. They don't behave like normal code.

C#/VB.NET/ASP.NET/SQL7/2000/2005/2008
http://www.vimalsoft.com
vuyiswa[at]vimalsoft.com

Vimalsoft(Pty) Ltd30-Aug-17 7:22

Re: (View) in a parent or ancestor Context for android:onClick attribute defined on view class Button

30-Aug-17 7:22

Good Day Everyone

I have an activity class defined like this

[Activity(Label = "Activity_Home", MainLauncher = false, Icon = "@drawable/lenderlogo", Theme = "@style/MyTheme")]
    public class Activity_Home : ActionBarActivity //AppCompatActivity
    {

and the activity is hosting a Tab that display its content from a fragment. A fragment is defined separately and it has a button that is defined like this

 <Button
android:textSize="10sp"
android:textColor="#FFF"
android:id="@+id/btn_details_save"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:onClick="btn_details_saveClick"
android:text="Continue" />

as you can see i have a click event that is triggered when the button is clicked. The code to handle the event of the button is defined in the fragment class file like this

//Find Controls to hook 
                Button btn_details_save = FindViewById<Button>(Resource.Id.btn_details_save);

                // set onclick listener here, by deleting some process
                btn_details_save.Click += delegate
                {
                    btn_details_saveClick();
                };

and he function itself is defined like this

public void btn_details_saveClick()
        {
             //Do stuff
        }

Now when i run the application, the button is click the button the following error occurs

AndroidRuntime(19059): java.lang.IllegalStateException: Could not find method btn_details_saveClick(View) in a parent or ancestor Context for android:onClick attribute defined on view class Button with id 'btn_details_save'

Please note that this is C# code , which means i am using xamarin ,but the error is Android related not Xamarin.

Thanks

David Crow30-Aug-17 10:35

Re: (View) in a parent or ancestor Context for android:onClick attribute defined on view class Button

30-Aug-17 10:35

My first concern is that you are declaring the click handler twice: once in the layout file, and again in code. Use one or the other, but not both.

Second, you need to change btn_details_saveClick() to accept a View parameter. This is what the error message is actually telling you.

Vimalsoft(Pty) Ltd30-Aug-17 11:08

Re: (View) in a parent or ancestor Context for android:onClick attribute defined on view class Button

30-Aug-17 11:08

Thanks for your reply David

"My first concern is that you are declaring the click handler twice: once in the layout file, and again in code. Use one or the other, but not both."

I thought we have to add the click event on the layout file and add hookup the event to the button also in the initialization of the Activity. i learned, thanks. i am coming from asp.net background

i have changed my function in my frament page to be like this

public void btn_details_saveClick(View  view)
        {

had

 //// set onclick listener here, by deleting some process
//btn_details_save.Click += delegate
//{
//    btn_details_saveClick();
//};

and i ran it and i got the Error

java.lang.IllegalStateException: Could not find a method btn_details_saveClick(View) in the activity class android.support.v7.widget.TintContextWrapper for onClick handler on view class android.support.v7.widget.AppCompatButton with id 'btn_details_save'

i have also have a example project( 9mb) on this link Example Project

To Reproduce the Error
1) Open the drawer

2) Click on loan application and click the button "Continue" and you will get an Error

Thanks

modified 30-Aug-17 18:00pm.

David Crow31-Aug-17 3:56

Re: (View) in a parent or ancestor Context for android:onClick attribute defined on view class Button

31-Aug-17 3:56

Does the btn_details_saveClick() method belong to the same class that 'owns' the layout?

Vimalsoft(Pty) Ltd31-Aug-17 4:00

Re: (View) in a parent or ancestor Context for android:onClick attribute defined on view class Button

31-Aug-17 4:00

Hi David

Yes it does , i have an example Project (9mb) http://www.3cx.vimalsoft.com/Example_Android_Exception/App10.zip

David Crow31-Aug-17 4:23

Re: (View) in a parent or ancestor Context for android:onClick attribute defined on view class Button

31-Aug-17 4:23

If you are defining the click-handler in the .xml file, the click-handler must be implemented in the activity not the fragment. If you are defining the click-handler in the .cs file, the click-handler can be implemented in the fragment.

You'll notice in that example that the btn_details_saveClick() method is contained within the activity PersonalDetailsView rather than the fragment PageFragment.

Vimalsoft(Pty) Ltd3-Sep-17 10:49

Android Notification by App

3-Sep-17 10:49

Thank you David i fixed the issue

after making the PersonalDetailsView inherit from Fragment, all started to work.

Andy_Bell27-Aug-17 6:58

Andy_Bell

27-Aug-17 6:58

Good evening
I need to insert notifications in my Android application. This is something similar to RSS service.
Therefore I have inserted NotificationCompat.Builder, and Pendig Intent to this purpose. When user selects corresponding item the application is restarted and updated.
But I have a problem, I don't have idea how to fire the notification. I'm thinking to start something like a Timer, every 15-30 minutes connect to server and look for new event released. If there is one, I'll fire Notification through the corresponded object.

Is this a best prtacice? Is there any better way to do?

I would appreciate any sugestions.
Thanks a lot.

Re: Android Notification by App

David Crow27-Aug-17 13:00