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Hello everyone:
I have a tree window, before scroll to the last line, I want to delete the tree and re-install it, and then scroll. For to do it, I want to get WM_VCSROLL before OnVScroll() is called.
1.I tryed to get the msg in PreTranslateMessage, but WM_VSCROLL is not sent into the function.
2.I tryed to get the msg in WinProc, but I cannot.
How to get it? Thank you.
-Freehawk
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WinProc? You program in WIN32? 
Did you mean DefWindowProc()?
Anyway, that's not important.
I guess this problem is because your message is sent to another window. Under the MFC framework, all messages would be sent to DefWindowProc( ) if their message handler are not defined (Ex: user defiend messages ). So your problem sounds quite strange...;P
( In Win32, you need to define all message handlers if you want to do something when these messages are sent. Otherwise, DefWindowProc( ) would be called. )
In addition, in Visual Studio you can use a tool Spy++ to "SPY" any message in your window.
I hope that will help. Good luck!;)
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hi all,
I have created a exe using MFC. Now I want to execute it when starting the Windows...
If any one know that please reply me ..
Thanks in advance..
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Just make a shortcut in the start>programs>startup
<italic>Work hard and a bit of luck is the key to success. You don`t need to be genius, to be rich.
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Add path (string value) of your exe to following location in registry:
HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Run
ARSALAN MALIK
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Add path of your exe to following location in registry:
HKEY_LOCAL_MACHINE\Software\Microsoft\Windows\CurrentVersion\Run
Regards,
Vishal
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Looking for code to create / control a color palette similar to Corel's color toolbar controls.
Thanks in advance
Tony Teveris
Gerber Scientific Products
Senior Software Engineer
Phone: 860 648 8151
Fax: 860 648 8214
83 Gerber Road West
South Windsor, CT 06074
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How do I do exponents in C++? If ^ is XOR...
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Use the pow() function.
Ryan "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"
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2^3= pow(2,3)
<italic>Work hard and a bit of luck is the key to success. You don`t need to be genius, to be rich.
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I wrote this string parser. It compiles without errors. But when I launch the program, it doesn't seem to quit the loop.... What's wrong?
#include <string.h>
int Parse(char *String)
{
int Temp = 0;
int Result = 0;
int Length = int(strlen(String));
bool Negative = false;
for (int i = 0; i < Length; i++)
{
if (i = 0)
{
if (String[i] == 45)
{
Negative = true;
}
}
else
{
if (String[i] < 48)
{
return 0;
}
else if (String[i] > 57)
{
return 0;
}
else
{
switch (String[i])
{
case 48:
Temp = 1;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
case 49:
Temp = 1;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
case 50:
Temp = 2;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
case 51:
Temp = 3;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
case 52:
Temp = 4;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
case 53:
Temp = 5;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
case 54:
Temp = 6;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
case 55:
Temp = 7;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
case 56:
Temp = 8;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
case 57:
Temp = 9;
for (int j = 0; j < (Length - i); j++)
{
Temp *= 10;
}
Result += Temp;
Temp = 0;
break;
}
}
}
}
if (Negative == true)
{
Result = Result - (Result * 2);
}
return Result;
}
Any help would be appreciated...
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just debug it, trace the variable value.
<italic>Work hard and a bit of luck is the key to success. You don`t need to be genius, to be rich.
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[DFS] Zero wrote:
if (i = 0)
{
if(i == 0) 
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You may want to start and write defensively.
Instead of
if (i == 0)
Write
if (0 == i)
In this case you can not change the value of i by accident. It is so easy to leave out an equal sign.
Ant.
I'm hard, yet soft.
I'm coloured, yet clear.
I'm fruity and sweet.
I'm jelly, what am I? Muse on it further, I shall return! - David Walliams (Little Britain)
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why not edit you message and put your code into a <pre></pre> block for helping us to see the indentation ?!
TOXCCT >>> GEII power
[toxcct][VisualCalc]
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Thanks everyone. And I modified the message a little...
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oh, that's better now  but the #include still don't appear. be carful to type & l t ; to see a < and a & g t ; for a >.
ok, now, you parser seem to be parser a little than one i wrote before. I cannot say to you what is wrong in your code, but I can give you an advice. see the source of my VisualCalc to perform your code...
If you need any question about your source, ask it to me here ; if it is about my code, post your request at the bottom of the VisualCalc article.
See you,
TOXCCT >>> GEII power
[toxcct][VisualCalc]
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I used the swab function to swap the data in a struct and then write it to a file. If I have two data structs that writes to one file, can I swap the bytes individually before writing them separately to the file or would I need to store them in a third struct (combo of the two), swap the bytes and then write to a file?
Scenario 1: read struct a, swap bytes, write to file
read struct b, swap bytes, write to file
Scenario 2: struct c is a combination of struct a and b
store struct a in struct c
store struct b in struct c
swap bytes in struct c
write to file
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I don't know if this is the right forum, so bear with me. I'm pretty new, and I just need some help stopping the infinite loop that is occuring in my programming. The bit that is causing problems is pretty simple, but I can't figure out the problem! Here it is:
void Error_day()<br />
{<br />
int enter1;<br />
<br />
cout << "That is not a day!\n";<br />
cout << "Type 'C' then press 'enter' to continue...\n";<br />
cin >> enter1;<br />
<br />
get_info();<br />
}
Any help would be appreciated. Thanks
Only Neo is me, no Cleo can see, my future, if she did I'd shoot her!
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You have to type in an integer to get rid off cin, or change enter1 from int to char to accept any character.
ARSALAN MALIK
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 if u want the ascii value.....go ahead and declare enter1 as int type but get it with functionz like getch() or getche(),or some function other than cin
if u want to use cin ,then declare the enter1 as char type
hope that helpz.....
happy programmin.....
cheerz.....
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This might be obvious, but in many cases you must hit return before input is accepted. That is if you type the number but don't hit the enter key input will not be returned, even though you typed it!
Beginners mistake, but you did say you were a beginner.
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Hello all,
Would anyone tell me that how C++ prevent the static variable been created more than one? Eg, if I have a function that contains a static variable:
<br />
void f() {<br />
static classA a;<br />
a.print();<br />
}<br />
<br />
void main() {<br />
f();<br />
f();<br />
}<br />
How C++ prevents the static variable "a" inside the function to be constructed twice rather than once? If I inline the function f(), will it still works?
Thanks!!!
Nacho
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Hi Nacho,
The static variable will get created only once (exactly, the first time f is invoked.) Are you observing something different?
Joaquín M López Muñoz
Telefónica, Investigación y Desarrollo
Want a Boost forum in Code Project? Vote here[^]!
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