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You know what guys. I seriously take everything back. I don't want your help anymore Thank you for everything though.
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nee-kow wrote: please reply to my e-mail
this is not how this site works. Besides, it may not be very smart to publish your e-mail address like that, any bot can grab it.
One normally researches the problem area using search engines, books, and the like. And then, when stuck, ask specific questions here, including some small code snippet if that would help, and then people will be glad to help you out.
BTW: if the entire class fails to understand the assignment, then I'd say something is wrong with the way the teacher operates. Talk to him.
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Luc Pattyn wrote: if the entire class fails to understand the assignment, then I'd say something is wrong with the way the teacher operates
...too right! But hey, what can you expect from one of the top engineering schools in the country!
return 5;
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Hi, i have successfully added validation for my textboxes. i have 2 buttons, the add and the delete. When the user click on the add button without any input to the textboxes, a message will display telling the user to input value, however when the delete button is clicked instead of the add button, the validation would appear and it wont allow me to delete. why is this so?
Needing help!
modified on Tuesday, January 4, 2011 10:27 PM
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pancakeleh wrote: why is this so?
it is very difficult to predict why it is so. please mention you code
modified on Tuesday, January 4, 2011 11:16 PM
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my delete button code as follows:
public String button1_action() {
try{
RowKey rk = tableRowGroup1.getRowKey();
if(rk != null){
incidentdataDataProvider.removeRow(rk);
incidentdataDataProvider.commitChanges();
incidentdataDataProvider.refresh();
}
}catch(Exception ex){
log("ErrorDescription", ex);
error(ex.getMessage());
}
return null;
}
my add button as follows:
public String add_btn_action(){
String myString = (String) getIncidentidtxt().getValue();
Integer incidentIDName = Integer.parseInt(myString);
String incidentNameName = (String)getncidentnametxt().getValue();
getSessionBean1().updateIncident(incidentIDName, incidentNameName);
incidentdataDataProvider.refresh();
return null;
}
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before starting validation, check which button was pressed. should be somewhere available in a Event-object or you extract that information to some variable, which you can access when and where needed. a boolean value should do the trick.
regards
Torsten
I never finish anyth...
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thanks i manage to solve it
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please pancakeleh, how did u do it?show as the code please...thanks alot..
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hi,
pls tell me.
which keyword used for differentiating local and global variable in java.
************ S G KORE *******************
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There is no such thing as global variables in java.
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All variables are defined by their scope, that is to say the block that contains them. Since no variable can exist outside a class there are no globals in Java. Take a look at the Java Tutorials[^] for more information.
Just say 'NO' to evaluated arguments for diadic functions! Ash
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I agree to what the others wrote.
There are some keywords in java you may not use as variable name:
Java Language Keywords @ Oracle.com[^]
But usually those words are highlighted in a special way as you use an IDE like Eclipse or Netbeans.
regards
Torsten
I never finish anyth...
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Static can be used as a key word to differentiate instance variable and Class variable. But according to the place where its declared can determine whether its local variables or instance variables. But there is no global variables in java.
public class DemoVariable {
private static int a=0; //Class Variable
private int b=0; // Instance Variable
public void print() {
int c =0; // local variable
}
}
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I'm developing a small game using the Swing Application Framework and I have stored a sound file (to be played when the user clicks something) in the application.resources folder:
resourceMap.getClassLoader().getResource(resourceMap.getResourcesDir()+"Beep.au").getPath();
(Then I use the path text returned to create a new File object which I pass into the AudioInputStream 's constructor).
I'm using NetBeans and it works fine when I run it in NetBeans. But when I run it outside NetBeans (by executing the jar file that NetBeans creates) I can't play the sound because a null pointer exception gets generated in the AudioInputStream 's constructor.
Can anyone help me out here to figure out what's going wrong?
modified on Monday, January 3, 2011 8:47 AM
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Pamodh wrote: Then I use the path text returned to create a new File
A File is basically a metadata representation of a file on the file system.
As described it cannot contain data because it isn't in fact a file (because it is in the jar.)
Thus what you are actually doing in your code is creating a reference to the actual file.
And that is why it doesn't work outside of netbeans.
You need to extract the file from the jar as a byte stream and enclose it in a Stream.
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Thanks for the answer. I tried it but it still didn't work. But then I saw that I had made a small mistake in capitalization of the actual file name. After fixing that and adding in your method, it worked great! Thank you very much!!
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Pamodh wrote: But then I saw that I had made a small mistake in capitalization of the actual file name
Per your explanation of your code that doesn't fix the problem that I was describing.
To guarantee correctnesss you should test your jar by doing the following.
1. Build the jar
2. Rename the sound file
3. Verify the sound file doesn't exist anywhere.
4. Run your jar
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I did and it works OK. Thanks!
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Needing help in validating textboxes to check if the textbox is null. I am netbeans and doing web application.
Anyone knows where to find tutorial on this?
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Well, there is always the obvious place[^].
Just say 'NO' to evaluated arguments for diadic functions! Ash
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i am now able to validation textboxes when the textboxes is null a error message will appear.
Right now if the user enter the number 20 and he or she wants to add the number 20 again, an error will occour.
how do i achieve tt?
i tried google however have no clue on how to strt.
Needing help..
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Assuming you've split your code into MVC (Model, View and Controller) - and of course you did so
You will store the data somewhere in a object. For this you're using a set-methode.
This is a typical moment for checking integrity of the value:
public void setIValue(final int iValue){
if(null != iValue && 0 < iValue && 100 > iValue){
this.iValue = iValue;
}
else{
}
}
or you do delegate this validation to another class(when pushing some "OK"-button) or even your textbox itself (write an extension and trigger on lost of focus or keystroke(can become strange if validation takes to long)).
regards,
Torsten
I never finish anyth...
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pancakeleh wrote: i tried google however have no clue on how to strt.
I already gave you a link to the Java tutorials. I suggest you spend some more time going through them, especially the areas that you are having difficulty with.
Just say 'NO' to evaluated arguments for diadic functions! Ash
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Hi, i am trying to connect to MySQL database mysql using JAVA .. using code given below,
import java.sql.*;
public class dbExample{
public static void main(String[] args) {
System.out.println("Listing all table name in Database!");
Connection con = null;
String url = "jdbc:mysql://localhost:3306/";
String db = "mydb";
String driver = "com.mysql.jdbc.Driver";
String user = "root";
String pass = "root";
try{
Class.forName(driver);
con = DriverManager.getConnection(url+db, user, pass);
}
catch (Exception e){
e.printStackTrace();
}
}
}
I've picked this example from internet .. and there lot more example i tried using this same driver String driver = "com.mysql.jdbc.Driver"; But this code all other i tried gives me error Driver Class not found ... at this statment Class.forName(driver); ..... and similarly on trying this driver sun.jdbc.odbc.JdbcOdbcDriver the above mentioned statment Class.fonName ... executes but then it gives error on statment con = DriverManager.getConnection(url+db, user, pass); error is No suitable drive found for jdbc:mysql://localhost:3306/mydb
I'm very much confused and tried it toooooo many time in diffrents ways that i could but still unable to create successfull database connection.
I've tried this using notepad / Netbeans both and both on WINDOWS7 and XP ... and both give same error to me ....
Please Please PLease give me any solution .... I shell be very very Thanksfull to you.
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