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by default, the datagrid add a pending new row after i have add my own row, the pending row has a * in front of the first column, is there anyway i can disable this pending new row? or is there anyway i could disable the user to add a new row on the datagrid itself?since the dataentry is done by another routine
Below is the screenshot
http://img.photobucket.com/albums/v608/mjay83/datagrid.jpg[^]
-- modified at 3:07 Thursday 2nd November, 2006
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hi
you can simply set the allowUserToAddRow property of the data grid to false.
this will eliminate the row of the * that u don't like and will allow the user of that interface to only view the table and the data in it.
hope it hleps
if you need more help plz contact me on MSN: jamilaboukhalil@hotmail.com
Jamil Abou Khalil
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Hi Jamil, thanks for reply
but i cant find the property u mentioned
i am using VS 2003, please advise
Thanks a again
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hi
sorry i don't know about vs2003 but i am sure that this property is one of the properties of the datagrid of vs2005. I am sorry about that.
p.s: u should upgrade to vs2005 it is more relaiable and more friendly and have more functionalities.
best regards
jamil abou khalil
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Thanks for reply again
It is ok, i dun think my company gonna purchase license for VS 2005 though
Thanks anyway;)
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hi again,
i think i have the solution for you. in the columns property of the datagarid you can navigate throught the columns that appear in the datagrid view. and for each column there is some properties on the right hand side of the window that appear when you click on the columns property. there u can set the column to be frozen. this means that the column is read only.
tell me if this works
best regards
jamil abou khalil
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try to use the read only property of the grid
When you get mad...THINK twice that the only advice
Tamimi - Code
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Hi Tamimi,
The Read only mode wont work for me becoz there is some column i would like the user can edit it on the fly..
thanks for reply anyway
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trust me, there is no way to do this...........
i tried to do this several times with no luck
When you get mad...THINK twice that the only advice
Tamimi - Code
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i am using a treeView control in which i want to display image against its every node. the images are placed in project directiory's \bin\release folder. now the tree is popupulated when the form is loaded i.e the statements of populating the tree are after calling
InitializeComponent();
in the constructor of new form. at first time when i come 2 this form (calling it against the NEXT button of a prevous form) then no problems occur and the images are loaded without any complication but when i go back to a previous form and come back to this form through same path and using same NEXT button then fileNotFound exeception occurs at this line
Image img = Image.FromFile("pic1.jpg");
but previously images were displayed successfully...!
i am facing same problem when i rightclick and create a contextMenu against a node. images are displayed against each optin of contextMenu successfully at first but when i click some option of contextMenu then work n then rightclick same node then the same exeception fileNotFound occurs(while populating ContextMenu) at same sort of lines...
further more if i am debugging the project then these fileNotFoundException occurs even for the first time when i populate the tree.but when i run the project no error comes for the first time and the images are loaded successfully....but only for first time..!
i canot understand where the problem lies??
May God help u solv ur problems as well,thx in advance!!
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I program a programing which can enforce another program. How can I do? Please help me ,thank so much!
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you can use the system.diagnostic.process.start(fullpath) and put the full path of the second program as an argument.
this will start the second program
Jamil Abou Khalil
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thank for your help.But I don't understand clearly, can you give me source code for reference.Thank you!
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For example, I design a button which when I push it, a program (eg : sound recorder)run but run background not display.
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if you want to run any system recognized Program then proceed as
Process.Start("wordpad.exe");
else if you want to run your Program then proceed as
Process.Start(ExePath+"\\wordpad.exe");
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Use : System.Diagnostic.Process.Start(@"C:\My Temp\MyApplication.exe");
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there is no DESC Keyword present in Sql server
sameer
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well what query can i use to get structure and information of a table??
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SELECT Column_Name,Ordinal_position,Data_Type,IS_Nullable,Column_Default ,Character_Maximum_Length FROM INFORMATION_SCHEMA.Columns WHERE TABLE_Name ='TableName'
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Hi
I want to know when and where a data access layer (dal) should be used and when we must avoid using a dal. Also why should we use a dal?
regards
sAqIb
"Our scientific power has outrun our spiritual power. We have guided missiles and misguided men."
Dr. Martin Luther King Jr.
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you can split your project into 3 layers
1) Visual Layer
2) Working (Logic) Layer
3) DAL
this kind of utilisation opens for you a hugh number of variety.
F.ex your logic Layer calls a function from the DAL "LoadCustomer"
The Logic calls all the time "LoadCustomer" no matter how the customers are loaded.
The loading is maded by the DAL. The specific DAL Class, for example SQL_DAL knows that a loading is "SELECT * FROM CUSTOMER" ... if you would change after 5 years the DB, you must only change your
DAL or derive a new class from a DAL Base-Interface ( that definites all functions that the logic layer can call ) So you re-programmate only the OBJ-DAL ( for example a object-rel DB )
The logic layer still calls LoadCustomer, but there, the loading is different
I hope you understand my poor english
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i uderstood what u were trying to say, but there must be some more benefits of using dal. can you tell me what r those?
sAqIb
"Our scientific power has outrun our spiritual power. We have guided missiles and misguided men."
Dr. Martin Luther King Jr.
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I only know the benefit that you can make a universal use of classes.
You can change in runtime your DB for example.
Or if you change your Application into a Web Application, you only change the Visual Layer and the rest of all layers aren't changed
Thats all that i know;)
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