A Visual Studio regex to remove someone's overzealous use of regions in VS. Find and replace: (^.*\#region.*$)|(^.*\#endregion.*$) Remember to enable regular expressions in the Visual Studio find and replace dialog.
A Visual Studio regex to remove someone's overzealous use of regions in VS. Find and replace: (^.*\#region.*$)|(^.*\#endregion.*$) Remember to enable regular expressions in the Visual Studio find and replace dialog.
I agree it would be nice to be able to use the group name in the switch; unfortunately the Group object doesn't have a Name property (and neither does its base class Capture) so the best you'll be able to do is the following:string ReplaceMatch(Match m) { if...
I am using a Regex with a MatchEvaluator delegate to process a format string, e.g. "Time: %t, bytes: %b" would replace the "%t" with a time stamp, and the "%b" with a bytes count. Needless to say, there are loads of other options!To do this, I use: Regex regex = new...
I think the matching with prefix and suffix options of Regex can be used to extract only the required value from the parentheses as shown below:string text = @"STRING[261] Directory(\FTP\OSP_003\)\nSTRING[9] FileName(SysParaI)\nSTRING[4] FileExtension(002)";Match match = Regex.Match(text,...
The Regex method uses comma, full stop, hyphen, and apostrophe as word separators. The problem with this is that these characters are not universally used as separators. The hyphen is used to join two words. Could I suggest the following?string input = "Mr O'Brien-Smith arrived at 8.30 and...
OK - this is a bit of algorithmic fun and I'll tell you how I'd go about it, but you'll have to figure the code out yourself.You need to combine a forward reading parser with a recursive object or functional call. On every open tag you need to go one level further of recursion, storing the...
Essentially you are attempting to parse the grammar in the string.See this CP article Parsing Expression Grammar Support for C# 3.0 Part 1 - PEG Lib and Parser Generator[^] which is also referenced from this post[^] that includes some alternative ideas.Here's an academic paper[^] on the...
You can try thishttp:(?:(?!http:).)*It will match from http: up to the next occurence, but not including it.The result of your sample string will be 3 separate matches.[UPDATE]Forgot the https variant:http(?:s)?:(?:(?!http(?:s)?:).)*
Consider using the open source HTML Agility Pack library (htmlagilitypack.codeplex.com).It lets you use XPATH queries to access very specific parts of an HMTL document, and the HTML does not have to be valid, well-formed XML. In addition to accessing the raw inner text of an element you can...
One option is to split the original string at the location of ? and reconstruct using @param as shown belowSub Main Dim statement As String = "INSERT INTO X (a,b,c) values (?,?,?)" Dim statements As String() = statement.Split("?"C) 'Construct a stringbuilder Dim sb As New...
You can go simple and justRegex r = new Regex(@"\(.*\)");var e = r.Matches(s);e is a collection of matches, and will include the "()"Will not requerRegex r = new Regex(@"\((.*)\)");var e = r.Match(s);e.Groups will contain all matches, the second item will your result
Regular expression, or often known as regex, is a pattern that consist of rules used to match a certain set of strings. They are extremely powerful, and you’ll need them in most programming languages you come across, especially when there’s a need to scan and match context for further...
sample code:var splitwords =new string[] {"egg","eggs", "have a receipt"}; string input ="I have a receipt with eggs but others with just one egg";foreach (string word in splitwords){ var regex = new Regex(@"(?
It is returning a length of 350 because the string contains 350 characters.To verify this, select the text and paste it into an Unicode editor (e.g. with Notepad++ choose File - New, Encoding - UCS-2 Little Endian, and paste the text). Within Notepad++, it will look like (shortened, there...
You either have an extra backslash: "[(.*?;)([(if)(while)(for)]\s*?\(.*?\){({.*?})*?})]"becomes"[(.*?;)([(if)(while)(for)]\s*?(.*?\){({.*?})*?})]"or one too few:"[(.*?;)([(if)(while)(for)]\s*?\(.*?\){({.*?}\)*?})]"
It's certainly the fastest way to type it.If you want to try to find faster ways, be a programmer and try different ways to approach the problem.Performance for such a task would greatly depend on the length of the string involved.
Unfortunately, AFAIK there is no way top make a regex which replaces "one of these" with "one of those".You can clean it up a bit, by using a MatchEvaluator to remove the need for a String builder. Make the regex just a list of known invalid characters and: result =...
This is a so called 'regular expression' (RegEx).Just have a look at this :http://en.wikipedia.org/wiki/Regular_expression[^]Your RegEx will match when:0 or more whitespaces (\s*)are followed byexactly two digits (\d{2})followed by ':'followed by 0 or more whitespaces...
The first thing to do is to write down exactly what you want to match. From your examples, it looks to me like this is a good start:a non-letterfaceoptional apostropheoptional sa non-letterTranslated into a regex, this turns into[^a-zA-Z]face\'?s?[^a-zA-Z]You then need to...
Note: These suggestions aren't Regex specifically, which I know you asked for. I'll work on a RegEx for you as well, but these solutions seem simpler and lighter than full RegEx:Pass the file names into the GetExtension method like so:string extension =...
You want a negative lookahead or a negative lookbehind. Suppose you want to validate so that a phrase starts with "string" and ends with "bee", but does not contain "like". You could use this regular expression (which uses a negative lookahead):(?!.*like)^sting.*bee$The negative look ahead...
Basically you can replace the keyword @city with \s+(?[\S\s]+?)\s+Example:string template1 = @"^Tell me the forcast of\s+(?[\S\s]+?)\s+for\s+(?[\S\s]+)$";In C# you useMatch m = Regex.Match("Tell me the forcast of Las Vegas for tomorrow", template1);if...
I have been unable to determine what the meaning of \Q is in Java, but in Perl, it's:\Q quote (disable) pattern metacharacters until \E\E end either case modification or quoted section,This doesn't appear in the .net implementation and seems needless in your...
See this regex:/^(?=[^a]*a)(?=[^n]*n)(?=[^u]*u)/iRegex explanation:^ Asserts position at start of string.(?=[^a]*a) Asserts that "a" is present after all the non-"a"s.(?=[^n]*n) Asserts that "n" is present after all the non-"n"s.(?=[^u]*u Asserts that "u" is present after all...
The same you can achieve using Linq[^] query:string[] words = new string[]{"Anitha", "Nandu","anushka","jayasree"};var qry = from w in words where w.ToLower().Contains('a') && w.ToLower().Contains('n') && w.ToLower().Contains('u') select w;foreach(string word in...
Two problems with your code:You've used Regex.Match instead of Regex.IsMatch;You've missed the @ prefix on the second "\b" string;I'd also be inclined to add a Regex.Escape around the word to find, in case it contains any special characters.var listTobeDeleted =...
Your parameters are the wrong way round - the first parameter is the string to test, and the second parameter is the regular expression to use:Regex.IsMatch(myString, ".* My name is XYZ")To retrieve the details of the match, use the Match method[^], which returns a Match object[^]....
Your pattern currently consumes the leading and trailing commas, so every other value is skipped.You need to use zero-width positive lookahead/lookbehind assertions instead:Regular Expression Language - Quick Reference[^]Also, it would be better to use [^\,]* rather than .*?, since you...
See solution 1 for a working solution.This site can help to see if a regex is doing what you expect.Debuggex: Online visual regex tester. JavaScript, Python, and PCRE.[^]I guess you will have to read regex documentation to understand advanced usages.perlre - perldoc.perl.org[^]By...
String.Split isn't a Regex - it's just a basic string method that can't do anything too complex.Try:("[^"]*")|([^\s]+)as a regex - it should give you what you want as separate Group values.
It's not a valid regex for a telephone number: what it matches is literally a single numeric digit followed by the text "{5-15}" and nothing else.What they probably meant to say was:^[0-9]{5,15}$Which matches "any string of numeric digits between 5 and 15 characters long,...
Using RegEx for Credit Cards is at best rudimentary; you are better off validating what you are actually working with Credit Card numbers themselves are generally at least 16 digits long; the primary exception being American Express which uses 15 digits. CVV numbers are 3 digits long for most;...
[EDIT] If you would like optionally to get first occurance of 99,00... For lines: My super data plan 10gb mobile 99,00 1 jul - 31 jul 2020 99,00 My super data plan 10gb mobile 1 jul - 31 jul 2020 99,00 Try this: ...
Please check the following modified code:Private Sub TextBox1_KeyPress(ByVal sender As Object, ByVal e As System.Windows.Forms.KeyPressEventArgs) Handles TextBox1.KeyPress Dim allowedChars As String = "0123456789" If e.KeyChar ControlChars.Back Then If...
NOTE: If you're really wanting plain text, then you should also be sure to decode the HTML entities (System.Web.HttpUtility.HtmlDecode()) on the resulting text, or you'll wind up with HTML/XML character entity text in your output, such as & and [ If you're going to immediately output the...
In case you have never heard of it, this is an excellent site. Contains cheat sheet and testers. As well as a list of predefined expressions.regexlib[^]That is a suggestion, i will see if i can come up with a solution!Edit: See you posted your question on that site also :doh: I will...
I wouldn't use a regex: you could but it would be quite complex and difficult to maintain.Instead, I would sort the characters in my input string, and then check it.If two adjacent characters are the same, fail.If any character is not in the set 'B', 'L', 'R', 'T', failOtherwise, pass.
Save yourself the pain and use XPath expressions[^] to dissect your XML.Regular expression are really no good for parsing nested structures.Best Regards,-MRB
1. You can use \d{10} instead of @"\d\d\d\d\d\d\d\d\d\d"2. What is this : expvalidator.IsValid.IsValid?Edit ----Because the default value of this property is true, it will return true if you query this property before validation is performed. For example, this might occur if you attempt...
And I think you will continue looking: that is not something I would want to do with a regex, particularly since you do not know the length of the sequence to be checked for.Instead - since I assume this is for checking password strength - why not use existing code: Password Advisor[^] has...
Hello, I cannot find a valid regular expression pattern for my needs.I have a sample string like this:I have four child of seven years each, [seven] years ago I had no child, because I was fourteennow, I want match and then substitute the words "four" and "[seven]".So I have...
That actually quite difficult, and probably not suited for a regex at all. The problem is that you want to accept the "Peter" from "Peter's" but discard "5th". What you really want to do is probably use a dictionary (a proper one, rather than an .NET Dictionary class) and check for actual words....
You can use the Regex.Split Method[^].Use these links to find out how regular expressions work:.NET Framework Regular Expressions[^]Regular Expression Language Elements[^]
I also use a Regex expression to count words, which returns the same number of words as MS Word. I wrap the Regular Expression in a String extension method to make it easy to use.public static class StringExtensions{ /// /// WordCounts Regular Expression /// ...
In this case, try:ClosedAccountFile_(\d+)_(\d+)_(\d+)_(\d+).txtThis matches your example, and separates each of the numeric values out into it's own group within the match.You have top realize that Regexes are much, much more complex than SQL LIKE statements - the simplest form of "%" in a...
how to change this regular expession to must have two decimal place((0)+(\.[1-9](\d)?))|((0)+(\.(\d)[1-9]+))|(([1-9]+(0)?)+(\.\d+)?)|(([1-9]+(0)?)+(\.\d+)?) cause i try 0.0123 it work but if i try 1.123 it don't wok, if i try 0.1 is don't worki have try this...
Try:Regex regex = new Regex("[a-zA-Z]");string result = regex.Replace(InputText,"#");Get a copy of Expresso [^] - it's free, and it examines and generates Regular expressions.
If you want to remove the whole select element with it's content, then you can do it with regex only if some constraints are met: no nested element of the same name (select in this case).Try this:string pattern = @"";CheersAndi
I think the following Regex and HtmlDecode would do:string html = ...;string textonly = HttpUtility.HtmlDecode( Regex.Replace(html, @"|", ""));Any HTML construct that would not be stripped off properly by this?
This is a bit rough, because you don't describe it well:[1-9][0-9,]{0,5}Get a copy of Expresso [^] - it's free, and it examines and generates Regular expressions.
I guess it should be like this:bool result1 = Regex.IsMatch("ABCDEF", @"^[A-Z]{2}$");bool result2 = Regex.IsMatch("ABCDEF", @"^[A-Z]{2,2}$");bool result3 = Regex.IsMatch("AB", @"^[A-Z]{,2}$");bool result4 = Regex.IsMatch("AB", @"^[A-Z]{2,2}$");If a caret (^) is at the beginning...
if it is Windows Applicationset property of Textbox CharacterCasing = Lowerit will automatically convert uppercase letters to lowercase.string pattern="^([0-9a-zA-Z]([-.\w]*[0-9a-zA-Z])*@([0-9a-zA-Z][-\w]*[0-9a-zA-Z]\.)+[a-zA-Z]{2,3})$";and verify it when textbox's Leave event...
I tried this in C# and it worked fine.Regex regex = new Regex("\'");string[] lines = File.ReadAllLines("d:\\milind.txt");foreach (string line in lines){ string str = regex.Replace(line, ""); Console.WriteLine(str);}Hope that helps. If it does, mark it as...
What you are searching for is not a case for using Regular Expressions. RE's allow you to quantify how many characters of a set may occur in a row, but not how many in total. Writing a regular expression for what you are trying to do is not possible.You're better of doing this with a...
Manfred R. Bihy's answer is mainly correct. But regexp is capable of counting total character counts using lookaheads (please look at this article: http://www.zorched.net/2009/05/08/password-strength-validation-with-regular-expressions/[^]). But strong password validation usually goes beyond...
Hello Paw,Here's a pattern to find the LON and then insert it into a group called "lon":string patternToFindLON = @"lon(\s|:)*(?[0-9]*(.[0-9]*))";And the same idea to find the LATCheers, Edo
Try this:string regexSearch = new string(Path.GetInvalidFileNameChars()) + new string(Path.GetInvalidPathChars());Regex r = new Regex(string.Format("[{0}]", Regex.Escape(regexSearch)));Cheers, Edo
An attempt of applying Regular Expressions to extract data from HTML is a very usual in the beginners, and, in most cases, is a methodological mistake. First of all, it's most usual case when HTML is a well-formed XML. In this case, .NET XML parsers should be used, and they are always available....
You haven't used groups in your Regex! So all you will get is the whole string matched.I'm just guessing that you want to break out the title and the human readable segment separately?Try this:\w+)">(?.+?)This breaks out two groups:...
I found a similar question on Stack Overflow[^] and used its answer on your problem.The idea is to split only on comma's that have an even number of or no single quotes after it.Using this expression I got the result without the additional blank line you are looking for....
This is not a "good" regex problem: what you really want to do is use a regex to find if a string contains any "special" characters, then count the number of non-special characters. But your description basically comes down to: you can use any characters you like, but you must have at least one...
Have a look here: http://regexlib.com/Search.aspx?k=ISBN&AspxAutoDetectCookieSupport=1[^]. There you'll find a solution ;)In my opinion this regex:ISBN(-1(?:(0)|3))?:?\x20+(?(1)(?(2)(?:(?=.{13}$)\d{1,5}([ -])\d{1,7}\3\d{1,6}\3(?:\d|x)$)|(?:(?=.{17}$)97(?:8|9)([...
Hai,I have some HTML Text. When i display that i want to highlight some keywords. I dont want to match if that is a part of html tag or any special characters like for eg :My HTML Text : Hello Welcome to my Spa No. 160my keywords : spa 160for highlighting i use...
The hyphen is the key part, the regex is saying match any character in the range "+" to "x" or *For example ")" and "z" would not matchNot sure why it isn't just [\*-x] to be honest.
Is it possible to use std::tr1::regex_iterator to search and replace in a string ?I know I can use std::tr1::regex_replace to replace all occurrences (or only one), but I need to replace each "pattern" that I find with something different, so I need to iterate my input string and replace on...
I would split the whole thing into scanning and parsing.According to your spec, the overall pattern looks as follows:begin, 1-to-2-digits, 1-char, 2-chars, 2-evenly-split-digit-groups-of-up-to-4-digits-each, endWhere between all tokens, there may be zero or more spaces.Lets define...
Although you have solved your problem I am posting this to help those wanting to better use RegEx. A very helpful site is regexlib[^]; they have a large library of Regular Expressions. They also have a RegEx tester[^]. Also a very useful RegEx tool is available here.
Hi allI wrote this expression for validating % in textbox^100(\.0{0,2})? *%?$|^\d{1,2}(\.\d{1,2})? *%?$Its working fine with input like 20.88%but when i give 20.88 i.e. without %, that also it's taking..this i don't wantPlease tell me what i am doing wrong..??
If you aren't sure, then the best thing to do is to get a copy of Expresso: http://www.ultrapico.com/expresso.htm[^]It's free, and it explains, helps you create and tests Regexes - I use it all the time and really wish I'd written it. (And I wish it came in an Android version, too)."\*"in...
Hi Bala,Here is the regex for dollar symbol^([0-9]{1,3}\$?)$ (dollar optional here)If dollar mandatory at last with single appearance then use this ^([0-9]{1,3}\$)$ or ^([0-9]{1,3}\${1})$ (dollar mandatory here)will allow 100$, 111$, 001$, 123$.For indian currency you can...
Here is a way to do it without RegEx: class Program { static void Main(string[] args) { string fileName = "CheckFileList.txt"; Dictionary> sections = GenerateList(fileName); foreach (string sectionName...
To be honest, a regex is a poor way to do this: regular expressions are very good at pattern matching, but they are very poor are syntactic analysis, which is what this task requires.It is possible to match brackets and so forth - though it is quite complex - but it can't easily spot things...
Please see my comment to the question.You just need to learn System.DateTime and methods of parsing of string into date data. Please see all the methods named Parse, ParseExact, TryParse and TryParseExact (and avoid using Convert, in most cases; after all, this is parsing, not...
Either[0-9a-zA-Z]+:for "one or more", or[0-9a-zA-Z]*:for "zero or more"But you may find this better:\w+:for "one or more", or\w*:for "zero or more""\w" is the equivalent of "[0-9a-zA-Z_]"
It has got nothing to do with regex, just use javascript to validate before submissioncheck-box-validation-for-atleast-one-check-box-should-cheked-in-asp-net[^]
Maybe:const string EIDPattern = @"^(?[A-Za-z0-9]{4})(?:[/\s])(?[A-Za-z0-9]{5})(?:[/\s])(?[A-Za-z0-9]{2})$"TheInput string can have space or other symbols also.is not directly translatable to a valid regular expression statement, though.You should...
Hi,Change your expression to this:string pattern = "(?=.*\bgoods\b|\bitems\b|\bthings?\b)(?=.*\bbought\b)(?=.*\bid\b)(?=.*\btest\b).*";Putting a ? after the 's' in 'things?' will catch both thing and things.You need to have word boundaries around each word in the optional...
Something like that should do the work: List exp = new List(); exp.Add("#:t.Brand"); exp.Add("#:iF(12 > 10,t.price,t.description)"); exp.Add("#:t.Brand + 'and ' + t.SubBrand"); System.Text.RegularExpressions.Regex searchTerm = new...
Why not just have the Regex do the replacement?private string ReplaceProductDescription(string description){ string pattern = @"/en/products/(?\d{4})/(?\d{4})\.aspx"; Regex regEx = new Regex(pattern); return regEx.Replace(description, "newString pn1 here:${pn1} pn2...
This is one way to do it.string input = "ABC_V3_Weekly_Abcdef_from_NOV_05_to_NOV_12";Regex regex = new Regex(@"from_(?[A-Z]{3})_(?[0-9]{2})_to_(?[A-Z]{3})_(?[0-9]{2})", RegexOptions.IgnoreCase | RegexOptions.CultureInvariant | RegexOptions.Multiline...
How about this - not RegEx, but produces also the desired result:var names = new string[]{ "Anitha", "Nandu", "anushka", "jayasree"};string[] anu = names.Where(n=>n.IndexOfAny("aA")>=0) .Where(n=>n.IndexOfAny("nN")>=0) ...
Hi,You can try this:var regex = new Regex( "(\\)|(\\)", RegexOptions.Singleline | RegexOptions.IgnoreCase);string ouput = regex.Replace(yourString, "");This worked for me. Hope this helps !! :) :)
Right, well obviously that method can't handle C/C++/C# syntax; it's actually pretty limited in what it can do.Fortunately, .net allows you to compile code at run-time. There are several articles here on CP, including mine: Compiling Source Code from a String[^]
You have to somehow parse the JavaScript source code, in order to extract such a info.You may have a look at existing parsers (Google is your friend[^]).
You have a syntax error in your expression. You are using ( instead of [.So change the expression from^(a-z)+\(+(a-z)+\,+(a-z)+\) $to^[a-z]+\(+[a-z]+\,+[a-z]+\);$I also replaced the white space with a ;
The year is the problem - the rest of it is trivial.I would do the year validation as a separate operation: extract it as part of the regex, then check it as a valid year in code rather than try to do it as a regular expression operation.The reasons are twofold1) Year validity changes...
Regular expressions are not the best tool for this, because you will have nested parts of your input text.In this case it with be more robust to use a parser, but that has a bit of a learning threshold. ANTLR4 is a free parser originally for Java, but it has a version for C# as well. See...
The problem is that "?" means just that: "0 or 1 repetition of the preceding item"Which means it's optional.Take the "integer number" regex:^[+-]?\d+$What that says is "the whole string consists of at least one digit, which may be preceded by a single plus or minus"So it...
Well, the regex should work. But ... your code doesn't care what happens if it does or doesn't work in that all you do is put up a message box if it fails and continue.Probably, you need to add an Else clause to the click handler to do something specific when the pattern does match. But we...
Hello I believe that there is a better way to use RegEx in C# than I have done below: public override object ProvideValue(IServiceProvider serviceProvider) { Regex r = new Regex("{.+}"); var matches = r.Matches(String); var replacer = new...
Something like this should work: private static readonly Regex Pattern = new Regex("{(.+?)}", RegexOptions.Compiled); public override object ProvideValue(IServiceProvider serviceProvider) { return Pattern.Replace(String, match => { string newMatch = match.Groups[1].Value; ...
Here is a nice extension class that will make regex searches a lot simpler: I don't like Regex...[^] You can search using a wildcard like * and the result will contain the found string. I modified it a little so * also includes spaces in the result and users don't need to use %: static...
If you mean HearingDocExtract, DocumentCopy, and DocumentID Then this will do it: (['])(?:(?=(\\?))\2.)*?\1 using System.Text.RegularExpressions; /// /// Regular expression built for C# on: Wed, May 9, 2018, 05:43:42 PM /// Using Expresso Version: 3.0.4750, http://www.ultrapico.com...
A digit is \d. A repetition can be implemented using {N} (meaning that a char or group must be repeated N times). With that, your regex becomes: ^\d{3}/[A-Z]{2}\d{2}/\d{9}/\d{2}$ Test it here: Online regex tester and debugger: PHP, PCRE, Python, Golang and JavaScript[^] string regex =...
I'm guessing somewhat here, but I suspect you're using the Validating[^] event to validate your textbox, and that's preventing you from clicking on your "exit" button unless you've entered a valid value. If that's the case, you need to set the...
Quote: Can someone help? The principle of regex is to match variable strings, to explain what you want, you need to give examples inputs and matched strings to let us know what you want, a few input that will be rejected may help too....
To be honest, Regex is not a good tool for this: it's a text processor, and that means it's great at processing well formed text, but not so great at processing syntax. If you are going to play with Regexes, then get a copy of Expresso[^] - it's...
If you're using Linux of MacOS, then regex.h should be installed as part of the libc development packages. Don't forget to #include before you #include . But I'm guessing you're using Windows and Visual Studio. In which...
It works for me in Expresso: I get the whole string matched correctly, together with an anonymous group containing "zoo-coin" only. The way I'd do it is to switch to a non-capturing prefix and suffix: (?
This is one of my regular expressions:(?[-+]?[0-9]*\.?[0-9]+([eE][-+]?[0-9]+)?),(?[-+]?[0-9]*\.?[0-9]+([eE][-+]?[0-9]+)?)The input would be 2 floats separated by a comma2.34,-23It creates 2 main groups "RollP" and "RollI" and i want to be able to take the...
I have a text file that I want to split with RegEx, but the problem is that its syntax is something like this:["string", "string", [("string", int),("string", int)], int, int, string(int, "string")],I want to split it using the comma (,) as a delimiter, but as you can see, there are a lot of...
Regular expression isn't there to help you in such a situation.Whatever your HTML tag is will give you finally out put in a browser in a pattern of what you wanted actually, What you want to achieve using Regex.Dot is a HTML display for unordered li tags.and number is a HTML display...
Sorry, but I have to vote this way down. Your regular expression (or @Chris's) is not robust enough for what I would consider "real world" data. Especially if this is used on any kind of public web site, I would be afraid of JavaScript injection attacks and other things (depending on its usage)....
Well, this is a repost[^] of your earlier question with changed content a little. Please avoid posting the same stuff multiple times. Follow at one place. Asking for code is not going to help. Try and then post the issue you face.
You don't need a Regex to do that: you can just use the string.Replace method:string inp = "hello there\n/* Call SUT */goodbye";inp = inp.Replace("/* Call SUT */", "/* Lower LOG level to improve performance and decrease output file size. */\n" + ...
Well,Based on this; http://regexlib.com/REDetails.aspx?regexp_id=564[^]I substiuted ABCD for TBRL and got this;(?i:([TBRL])(?!\1)([TBRL])(?!\1|\2)([TBRL])(?!\1|\2|\3)([TBRL])) Didn't work length had to be 4Try...
The first part of your question is not difficult, something like "[RBLT]{4}" would do it.The 'no duplicates' is difficult and in my opinion not suitable for a regular expression. This[^] article agrees.Although there are some regex wizards on CP that might give different advice.
It should be three steps: first, compare string with string.Empty (or first with null, or use string.IsNullOrEmpty). As a second step, use [RBLT]{4}, as Henry correctly put it. Third: with Regex, find all matches and then compare them in a loop to find duplicates and select only one match in...
In addition to what Kim and Manfred proposed, I'll add:You need to create an XML schema and validate XML against the schema, please read this: http://msdn.microsoft.com/en-us/library/system.xml.schema.xmlschemavalidator.aspx[^].General conclusion: application of Regex to XML is totally...
Try this regexp^at\s+(?.+?),.+?\(.+?longitude\s+(?.+?),latitude\s+(?.+?)\)\s+in\s+(?.+?),the depth.+?\s+(?\d+)/// A description of the regular expression:/// /// ^at\s+/// Beginning of line or string/// at/// ...
Try this bade boy of a regex string: \b(?=[-/\\\\A-Za-z]*[0-9])(?=[-/\\\\0-9]*[A-Za-z])[A-Za-z0-9]+(?:[-/\\\\][A-Za-z0-9]+)*\bIt will find only strings that contains numbers.string like this "Dam It12 is not45 that g00d".Will give...
string abc = "deepthi12 " char[] SpecialChars = "0123456789";.ToCharArray(); int indexOf = abc.IndexOfAny(SpecialChars); if (indexOf != -1) { //there should a number in the string } else ...
Hello All, I want to validate my textbox and email fields not to contain >> ( ) { } [ ] ? & * ~ ` ! # $ % ^ = + | \ : ' " , ; these special characters and can contain - _ @ / . these sepcial characters.How can i do it?Thanks in advance,Regards.
The simple regex is easy: @"[^\...]" where the elipsis is the list of individual characters you want to prohibit.However, I would suggest that a better email address validation would be a good idea, especially since '@' is not a legal character in an email address (it is the separator...
I suggest you download the program expresso. It helps you build regular expressions and test them. Also, 9 out of 10 real programmers know how to do something like this[^].
Hi all.Is it possible to split input text into list of words. Words should contain only symbols.for ex. "This is Peter's 5th program." I want to get words: "This", "is", "Peter", "program".Can I do it using only regular expressions? Or it is better to use myString.Split(' '), analyse...
Google! A very simple search using "validate alphanumeric in javascript" copied from your question subject gave 1.3 million hits, most of then explaining exactly how to do it.Please, try to do at least basic research your self in future...
Why use regex? // I would personally make this an extension methodpublic static string ReplaceOccurrence(this string str, string target, string replacement, int count){ int pos = -1; int counted = 0; string result = ""; do { pos = (pos >= 0) ?...
There is no sensible regex which will do that - it is a job for a sort routine.The easiest way is to convert the string to a character array, sort it, and convert back to a string again.string s = "bcade";char[] chars = s.ToCharArray();Array.Sort(chars);s = new...
Hi, I have an IE7 spesific REGEX problem.I'm validating Email Address with the following regex:^\s*[a-zA-Z0-9_\+-]{1,63}(\.[a-zA-Z0-9_\+-]{1,63})*@(?=[a-zA-Z0-9-\.]{0,255}\.?\s*$)[a-zA-Z0-9-]{1,63}(\.[a-zA-Z0-9-]{1,63}){0,126}\.([a-zA-Z]{2,63})\.?\s*$This works every modern browser but...
I recently downloaded some source files that seem to be exactly what I need for a project of mine. The only problem is that it is written for ANSI builds only, it has no UNICODE support.I now want to change all string literals from "text text" to _T("text text") by wrapping them in the _T...
this is one type of Regular expression.You can get the different type of regular expression from the site:http://regexlib.com/UserPatterns.aspx?authorid=0ebe8f93-b71b-4d1c-bfc2-0b583c464641[^]
I tried and its works: List list = new List(); list.Add("ASD"); list.Add("ASFsdsd"); list.Add("adsASFsdsd"); string pattern = @"[A-Z]{3}"; Regex regex = new Regex(pattern); List result = new List(); foreach (string val in...
Hi,I spent long time to figure out making the search with regular expressions in C# as it is done in SQL. I cannot find the equivalent of '%' sign of SQL in C#. I have tried to use "(|)" but it gives the 'or' condition.I am wondering if I can use the grouping with "and" condition on...
here is the ReGex i use for password fields... all the letters and symbols are allowed, and range is from 0 to maximum... * represents= 0 or more than 0 can exists^[a-zA-Z0-9]*[!,@,#,$,%,^,&,*,?,_,~,-,£,(,)]*$but this will not allow a letter once a symbol is entered...so you can modify it...
I have solved this by changing the expression as follows...Regex rx = new Regex(@"password='([a-zA-Z0-9\\%^&_*]+)\'");--------------again i have another question... Here is my updated expression...string x = "user = 'sa' password='e X65dere!@#$%^&*()' server = 'localhost'";Regex...
Hi, In our application we have many fields that are validated by using a regex. When the user enter an invalid data we show an error message. What I'm looking for is a way to create an example of a valid entry based on the regex we used to validate the field.I know that there's already...
The reason is that , is not to be escaped. So \, is interpreted as \ and , characters separately hence the required match is not found. Further .* in start is not necessary and \s* is also not necessary as . matches white space too. So the following pattern can be used\(.*,.*,.*\) but...
Hi,I want to verify the characters entered in excel sheet' cell using vba. I'm trying this with the pattern "^[a-zA-Z0-9]{21,21}$". I want this to match exactly 21 characters (can be alphanumeric) and no more or less than that. Its working fine when the characters are less than 21 characters...
Hi all. I have small problem I have some input text. I want to match that text but only then, when it not contains some words. I know how to do similar thing with characters ([^ChArAcTeRsWhItChIdOnTwAnT]). So my question is: is there any way how to get text starting with some words and ending...
I wouldn't use a regex directly - I would de-regionalize my data first. This is the way I do it:/// /// Remove Diacritics from a string/// This converts accented characters to nonaccented, which means it is/// easier to search for matching data with or without such accents.///...
Not in Google, huh?Then explain how I found this[^], this[^], and this download site[^] for the documentation.EDIT:And I forgot to post this guide[^] on understanding EDIFACT.I found that stuff in all of 10 seconds on Google. You really need to upgrade your Google-Fu skills.
your confusion are for sure. let me try to remove your confusion.[..] :- it means it has explicit set of character to match.^ :- it means start of string.$ :- it means end of string.there are more like--\ :- preceding one of the above or down.. :- any character except new...
Regexes are clever beasts, one opf the overloads for Rexex.Replace uses a match evaluator delegate: http://msdn.microsoft.com/en-us/library/cft8645c.aspx#Y0[^] which allows you to do further processing on the text matched by the Regex.If you write your routine to compare the match text as...
Guys,I've got a little lost with regular expressions in .NET 4.0. Can't understand why RegEx ignores maximum length in the pattern. See the code below...using System;using System.Text.RegularExpressions;namespace RegExTests{ class Program { static void Main() { bool...
Hello everyone,I need to write a regular expression which will allow numbers like1.23 and 1in to the text-box. Decimal point is not the compulsion.Any suggestion or links are welcome..!!
Regular Expression is : ^[0-9]\d{0,9}(\.\d{1,3})?%?$ [0-9] : for integers which allows integers from 0 to 9 d{0,9}: this will take up to 10 digits \. : for decimal d{1,3} : for decimal up to three digits
It's complex - but possible:^.*(?=.{8,10})(?=.*[!"£$%^&*()_])(?=.*[a-zA-Z]).*$The characters between the '[' and ']' are the permitted special characters. To be honest, I wouldn't use a regex for this - I'd do it in code, it's a lot more maintainable.
You only need a single RegEx.Use the conditional quantifiers in the Regex:Case eValidateInput.IsPhoneNumberWithPlus Dim objRegEx As New System.Text.RegularExpressions.Regex("^\+?\s?\d{3}\s?\d{3}\s?\d{4}$") If Not objRegEx.IsMatch(InputValue) Then sValidationMsg = "'" &...
You should make an effort to learn more about Regular Expressions. A good place to get started is here. Another very helpful site is regexlib[^]; they have a large library of Regular Expressions. They also have a RegEx tester[^]. Also a very useful RegEx tool is available here.
You can done this in following ways:1.AjaxFilteredTextBoxExtenderhere you first add reference of ajax toolkit and this extender.you can set ValidChars to "." for decimal which allo user to enter numeric value with decimal point.
In C# If you want to replace the (') with blankstring name=name.Replace("'","");If you don't want to replace the (')string name=name.Replace("'","''");In SQL If you want to replace the (') with blankprint replace('isola d''istria','''','')
Regex is probably the wrong tool, unless you are trying to match that string as a pattern:"A slash, followed by two uppercase Alpha, and three digits, then a other slash, followed by ..."If you want to find an exact string, then use string comparison instead - it's a lot easier and a lot...
How about:...string input = ...;Match match = Regex.Match(input, @"\w+\s*=\s*(\d+(?:\.\d+)?\s*[A-Z]+)");string size = match.Success ? match.Groups[1].Value : string.Empty;...Depends very much on the input string if the @ and { are relevant to properly match the text.Note: If you...
Hi Aarti,there are actually two issues with your example.There is no need for quotes around your pattern literal. Regular Expressions are first class citizens in JavaScript. Look here Regular Expression Cheat Sheet[^] or here W3 Schools RegExp Object[^]Certain characters in Regular...
Thank you for clarification. It finally looks like Regex is not helpful at all.Before entering data, perform filtering, to filter out everything except decimal digits, '.' and backspace (code point 8). Unfortunately, masked edit won't help much. For example, if this is...
This is the one I use:Expresso - A Tool for Building and Testing Regular Expressions[^]OThers are also availiable:http://www.codeproject.com/search.aspx?q=regex+tool&x=0&y=0&sbo=kw[^]
That's because '\d' is rexeg-speak for a digit: '0' to '9', Since your string contains "abcdefgh" and no digits at all, it will never match.Try@"DATE=.{7}"for seven of any character, or:@"DATE=\w{7}"for seven alphnumerics, or:@"DATE=[a-zA-Z]{7}"for seven upper or lower case...
Solution 1 provides right idea. Besides, you may want to do a different thing: instead of validation, you could filter out unwanted character while they are entered. In a Web application, this is done in JavaScript. Just one detail, often forgotten, don't forget to allow "character" #8,...
I am trying to remove all the instances of a number except for a number that I supply. This is currently what I have:var ar = '10,13,9,8,13,10,5,3,1,9,5,8,10,2,6';var removed = ar.replace(new RegExp('[^(' + 10 + ')]', 'g'), '')The result of this is "101110110", but I need it to...
Foreworda) Take a long tour here?: http://www.regular-expressions.info/tutorial.html[^]b) Install this little tool, and play with it: http://www.weitz.de/regex-coach/[^]Now the explanation\w stands for "word character", usually [A-Za-z0-9_]. Notice the inclusion of the underscore and...
Simple: you have told it not to!If I compact this a bit it may be a bit more obvious:^x+y+(z+)?$Where x, y, and z are the "phrases" in your regex.That requires "one or more x", then "one or more y", then "one or more z" - a minimum of three characters.I don't know exactly what you...
Check these, you could build yourself new expressions.Expresso - A Tool for Building and Testing Regular Expressions[^]Expresso - The 30 Minute Regex Tutorial[^]
The question almost contains the answer. Get Match.Value, which is a string, and use it in another Regex's pattern string. Please see:http://msdn.microsoft.com/en-us/library/system.text.regularexpressions.capture.value.aspx[^].—SA
I'm not sure that a regex is exactly what you are looking for here: it isn't a text matching process, it's a pattern matching process. It can't tell the difference between:mid nightandmidnight tonightThey are both "a word" followed by "a space", followed by "a word".But if you want to...
Can someone please provide a thorough explanation of what's going on with the Regex below?I was checking some of the features introduced in .NET Framework 4.5 and one of the mentioned benefits was Regex Timeout.In the example the following Regex is used: ^(\d+)+$ on the following text:...
After struggling with google search and reading about balanced group I finally got things working, though I had to alter the pattern slightly to make it work, at least for me :)Regex: ...
First of all, your regex is overly complicated and doesn't quite fit standards for domain names. - You have | pipes inside of bracketed character classes, which are unnecessary since everything inside brackets is already an alternation. Furthermore, it means that you have inadvertently...
You can't do arithmetic with a regex. You can extract the current value with a regex (@"\((\d+)\)$"), do arithmetic on it in code and then replace the value:str = str.Substring(0, str.LastIndexOf('(')) + newValue + ")";
If you want regex pattern for the following sample outputs:text.45example.90value.46then try:\b[a-zA-Z]*[.][\d][\d]\bElse if you only want those alphabets:textexamplevaluethen try:\b[a-zA-Z]*(?=[.][\d][\d]\b)+++++++++++++++++++++++++++++++++++++++++[amended upon...
This regex will do it:(\$\d+(,\d{3})*|\d+(,\d{3})*\$)Explanation: - You need to escape the dollar sign, since it's a special character in regex - The main part of the regex is any number of digits possibly followed by combinations of comma and three digit sections - There's an...
Your regex look like this - http://www.regexper.com/#(.*%3F)%3A%5C%5C%7B(.*%3F)%5C%5C%7D%3B[^]I believe this will do better - http://www.regexper.com/#(.%2B%3A)(%5C%7B.%2B%5C%7D)%3B[^]Also - when you have to check a string for repeating pattern use split to find all the parts...
Try this:string textWithEmails = "Christian has christian@email.com. Olof has the email olof@gmail.com. Lars has the emai britt123@oxford.co.uk.";string filteredStr = Regex.Replace(textWithEmails,...
The error says that you have to have an instance for the object you are referencing. You are trying to reference without first having created an instance of it which you can't do because it is not static.
Submit an article or tip
1 alternative