3 Oct 2010 by Baji Jabbar
Hi I am assuming the programming language as C#You can use Math.Pow() Function to accomplish this in C#. You can refer [this.]You can convert the equation to result with Math.Pow((x - a), 2) + Math.Pow((mx + c - b), 2) = Math.Pow(r,2); :) But your equation seems like it...