Range of a number according to a range list

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Hi friends,
I have a list of numbers 0.25,0.50,0.75,1,1.25,2,2.5,3.5, ... and then I need to find out the range minimum and maximum of a number. For example my number is 0.30 then the min range is 0.25 and maximum is 0.50.
I know there are so many ways to find out this but I want to know that if there is any pre-defined functions like Icompare.(The reason is I want to shorten my code length.)
Thanks in Advance.

Posted 6-Nov-14 23:04pm

Manu Prasad

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DamithSL 7-Nov-14 5:27am

What is the datatype of the list?

Manu Prasad 7-Nov-14 5:49am

Arraylist of double values

DamithSL 7-Nov-14 5:54am

double givenNumber =0.30 ;
List<double> numbers = new List<double>{0.25,0.50,0.75,1,1.25,2,2.5,3.5};
var min = numbers.Where(n=>n<=givenNumber).Min();
var max = numbers.Where(n=>n>=givenNumber).Min();

Manu Prasad 7-Nov-14 6:29am

Thank you Damith.. Now my code is this much only
private double GetLength(double myvalue)
{
return lengths.Where(n => n >= myvalue).Min();

}

Tomas Takac 7-Nov-14 5:40am

If you would use array instead of list you can do binary search on sorted array that finds you the range. I can post the code if you are interested.

Manu Prasad 7-Nov-14 5:47am

yes..Please.

BillWoodruff 7-Nov-14 12:03pm

Do you want to see another approach to this using Linq and a form similar to .NET constructs like 'TryParse, 'TryGetValue ?

If so, just ask.

[no name] 7-Nov-14 16:53pm

a.) "... and then I need to find out the range minimum and maximum of a number"

Please what is the Minimum and the max of a number? My number is e.g. 100 now what is min/max......?

b.) "The reason is I want to shorten my code length"
In worst case write a method and look to it as a black box...your "main"- code is then shorten. Even I'm asking me what entitles something like this.

BillWoodruff 7-Nov-14 18:10pm

Curious: suppose your test value is equal to one of the list values: if the test value is #1 is the desired result:

1. min 1, max 1

or

2. min 0.75, max 1.25

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Maciej Los · Answer 1 · 2014-11-07T09:31:00

Solution 4

You can achieve it using Linq[^]:

C#

double find = .80;
double[] darr = new double[]{0.25,0.50,0.75,1,1.25,2,2.5,3.5};
double up = (from maxv in darr
		where maxv > find
		select maxv).First();
double down = (from minv in darr
		where minv < find
		select minv).Last();
Console.WriteLine("Range for {0} is: {1}-{2}", find, down, up);

Result:

Range for 0,8 is: 0,75-1

Posted 7-Nov-14 9:31am

Maciej Los

Comments

Manas Bhardwaj 8-Nov-14 5:27am

Yes +5!

Maciej Los 8-Nov-14 8:27am

Thank you, Manas ;)

Tomas Takac · Answer 2 · 2014-11-07T00:58:00

As I mentioned in my comment, you can do this easily with an array. Please note that the array must be sorted in ascending order.

C#

double[] numbers = new[] {0.25,0.50,0.75,1,1.25,2,2.5,3.5};
int index = Array.BinarySearch(numbers, 0.3);

if(index >= 0)
{
    Console.WriteLine("is exact match");
}
else
{
    int lowerBound = -index-2;
    int upperBound = -index-1;
	
    if(lowerBound < 0)
        Console.WriteLine("is minimum");
    else if(upperBound >= numbers.Length)
        Console.WriteLine("is maximum");
    else
        Console.WriteLine("is between {0} and {1}", numbers[lowerBound], numbers[upperBound]);
}

Please see MSDN for more details on Array.BinarySearch[^] method.

OriginalGriff · Answer 3 · 2014-11-06T23:28:00

AFAIK, there is no "find in range" method: You will have to "do it yourself".
But it's not massive code: depending on the number of numbers in your set (and I notice it's sorted already) it shouldn't take long to find the "first number above" your value and then that and the previous index are the range.

For a small number of ranges I'd just scan up: for a larger number then maybe a binary chop would be more efficient? Depends on the count, and what your code is doing at the moment.

Range of a number according to a range list

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