Random string in language C

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Hi,
I need to make a program that generates a random strings in C, but i don't know how to do it.
Could anyone help me?
Sorry my english bad.
Tanks.

Posted 20-Aug-13 4:26am

Salatiel Bairros

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[no name] 20-Aug-13 10:32am

Sounds like a typical homework assignment. What have you tried and where are you stuck?

2 solutions

Solution 2

I think GUID and Regex could make this much easier and reliable...

Do try the following code which creates a random different string of 20 length each time.

Guid guid = Guid.NewGuid();

           string id = guid.ToString().Substring(0, 20);
           Regex R1 = new Regex(id);
           id = Regex.Replace(id, @"\s|\-|'", "");

           Response.Write(id);

Hope that will help to.... :)

Posted 20-Aug-13 19:13pm

VICK

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Yesudasan Moses · Accepted Answer · 2013-08-20T04:34:00

Solution 1

This may help you....

C#

void gen_random(char *s, const int len) {
    static const char alphanum[] =     "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";

    for (int i = 0; i < len; ++i) {
        s[i] = alphanum[rand() % (sizeof(alphanum) - 1)];
    }

    s[len] = 0;
}

Posted 20-Aug-13 4:34am

Yesudasan Moses

Updated 20-Aug-13 4:36am

v2

Comments

Salatiel Bairros 20-Aug-13 10:41am

Tanks!

Sergey Alexandrovich Kryukov 20-Aug-13 11:51am

It's not quite clear why do you think a "random string" could be the string composed of letters only, and static string is redundant (you should just get a random number and cast it to char), but it still shows some technique. I voted 4.
—SA

Argonia 21-Aug-13 4:01am

Your code generates only letters. What about numbers and symbols ?

Yesudasan Moses 21-Aug-13 4:39am

add this "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789~!@#$%^&*()_"