Accessing a variable from another class

Question

1.00/5 (2 votes)

See more:

Hi all,
There are two classes class1 and class2

C++

class1()
{
public: 
CV3 Value1;
}

class2()
{
//how to access the variable Value1 here?
}

C++

class1* temp;
temp->variable.x; 
//this gives initialisation error;

Posted 18-Jul-12 2:03am

Sumal.V

Add a Solution

4 solutions

Solution 4

Also u can make class2 as a friend class of class1 to access members of it.

Posted 18-Jul-12 19:14pm

joyjhonson

Comments

Albert Holguin 19-Jul-12 10:51am

This is only applicable to accessing private members. You also need to already have the object instantiated somehow.

Solution 3

Why doing all? just inherit class A as parent to class B. so you can access class A public variable using class B object

Posted 18-Jul-12 17:42pm

Aburik

Updated 18-Jul-12 17:44pm

v2

Solution 2

A possible variant :) :

C++

class A
{
  int m_iVar;
public:
  A(int iVar) : m_iVar(iVar) {}
  int GetVar() const { return m_iVar; }
};

class B
{
  A* m_pcA;
public:
  B(A* pcA) : m_pcA(pcA) { ASSERT(m_pcA); }
  int Test() const { return m_pcA ? m_pcA->GetVar() : 0; }
}

void Tast()
{
  enum { testVar = 3 };
  A a(testVar);
  B b(&a);
  int iResult(b.Test());
  ASSERT(testVar == iResult);
}

Posted 18-Jul-12 2:18am

Eugen Podsypalnikov

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

C^hris L^osinger · Accepted Answer · 2012-07-18T02:10:00

Solution 1

//this gives initialisation error;

of course it does. you haven't actually created an instance of an object of type class1. you created a pointer to an object, and they you didn't point it to anything.

try this:

class1 temp;
temp.variable.x;

or this:

class1 *temp = new class1;
temp->variable.x;

Posted 18-Jul-12 2:10am

C^hris L^osinger154.1K

Comments

Sumal.V 18-Jul-12 8:36am

Thanks, was being a lil silly :P