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var x=prompt("enter age here", "10");
if(x>60)
{
document.write("older");
}
else if(x>40)
{
document.write('Medium age');
}
else if(x>18)
{
document.write('young');
}
else if (x>0)
{
document.write('child');
}
else {
alert("invalid input");
}

What I have tried:

if i am entering a number more than 60 even any number like 200,300,2000,2000000, getting answer is 'older'. Can anybody tell me how to validate it i mean age should not be more than 120 years.
Posted
Updated 21-Feb-18 0:53am
v2

It's because your code is written that way. You have asked your program to say older when x is greater than 60.

Try something like following-
JavaScript
var x=prompt("enter age here", "10");
if(x>60 && x<=120)
{
document.write("older");
}
//...rest of the code as it is.


Hope, it helps :)
 
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Comments
Maciej Los 21-Feb-18 7:21am    
5ed!
Member 13688822 21-Feb-18 7:33am    
thanks
Suvendu Shekhar Giri 21-Feb-18 7:41am    
Thanks :)
Just add another "if"

if (x>120)
{
document.write("too old");
}
else if(x>60)
{
document.write("older");
}
 
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Comments
CPallini 21-Feb-18 6:49am    
Sometimes is sooooooooooooooooo simple. :-D
5.
Maciej Los 21-Feb-18 7:20am    
5ed!

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