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If you divide by zero you get sucked into the mathematical black hole where all logic is lost. But if it were true that 1=0, would that simplify chip design?
"A little knowledge is a dangerous thing, drink deeply or taste not."
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MKJCP wrote: But if it were true that 1=0, would that simplify chip design?
I wonder, I've heard that qubits can be in the "0" and "1" state at the same time, so does that qualify for "1=0" at any level?
Φευ! Εδόμεθα υπό ρηννοσχήμων λύκων!
(Alas! We're devoured by lamb-guised wolves!)
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I suppose it's arguable but dual state does not imply equality. It sounds like they should have named them confusedbits.
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The second statement is false.
if x = y, then x2 does not equal xy; x to the second power equals xy.
For example: if 1=1 then 1(2) does not equal 1(1)
Bullshit from the start, not to mention the division by zero
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Sorry guys but second line is false its only true when x=1 or 2
x = y.
Then x2 = xy is wrong if x=3 , xy=9 x2=6 6 !=9
you can't divide this way if its proper algebra left side is
x2 - y2 2(x-y)
------- = ------ = 2 <- left side of the equation
(x-y) (x-y)
and obviously you cant separate (x-y) from the right side (xy - y2)/(x-y) != y
sorry guys example is flawed and 1 != 0
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Unfortunately, this "proof" falls apart at the 2nd line. x2 = xy only holds true for 0, 2, and -2. The correct equation is x^2 = xy.
Still, a pretty interesting use of mathematics in an attempt to destroy all of our beliefs in what is thought to be true. 
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This appears to work, but only because you are dividing by zero since (x-y) is, by definition of the first line, equal to zero.
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huh? I don't think x = y implies x2 = xy. How did you get that?
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"x2" is supposed to mean x squared.
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As has been pointed out here, at some point you're dividing erroneously. But, you can prove that 0 = any number you want, using the derivation of differential calculus, as described here[^]: if you plug numbers into the equation at stage 3, you can "prove" pretty much whatever you want to prove. But of course, math is a language, not reality - and you can speak nonsense in any language.
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If 1 = 0, then 1 - 1 = 0 - 1, which means -1 = 0. Contradiction, so 1 = 0 can't be true.
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This is a code site so I wanted to prove this with C# and it fell apart for me.
[TestMethod]
public void TestMethod1()
{
var y = 5;
var x = y;
Assert.AreEqual(x * 2, x * y);
}
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Sorry, that doesn't work.
x2 is NOT equal to xy. That's like saying 2x = x*y which is ONLY true if x and y are both 2.
Cute, but does not float.
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Why do so many people here fail to grasp the obvious, that "x2" is meant to represent x squared? It's almost as if the CP community isn't very high quality.
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Well, the first problem with this is
x = y
then x2 = xy IFF x = y = 2
This was stated just above, but I didn't get that far when I was reading the comments...
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Seeing you're playing with polynomials there, aren't you?
following the logics..
x = y
x^2 = xy
x^2-y^2 = xy-y^2
(x-y)(x+y) = (x-y)y
x+y = y
2y = y
however you draw the wrong conclusion here, go on like this:
2y-y = y-y
y = 0
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You can't divide any number with 0. (x-y=0)
Divide by 0 is infinity, and infinity can't be equated.
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x-y=0. You are dividing by 0. Therefore your theorem falls apart at that point.
Nice try.
"Courtesy is the product of a mature, disciplined mind ... ridicule is lack of the same - DPM"
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"x2 = xy"
This is VERY wrong, I guess?
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Movie Quote Of The Day
Now, we've lost those computers with all of the 13th century in them. Not much in the century, just Dante and a few corrupt Popes, but it's so distracting and annoying!
Which movie?
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IT-Support
Rules for the FOSW ![ ^]
if(this.signature != "")
{
MessageBox.Show("This is my signature: " + Environment.NewLine + signature);
}
else
{
MessageBox.Show("404-Signature not found");
}
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Roy picks up phone: Hello IT, did you try turning it off and on again?
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Exactly
Rules for the FOSW ![ ^]
if(this.signature != "")
{
MessageBox.Show("This is my signature: " + Environment.NewLine + signature);
}
else
{
MessageBox.Show("404-Signature not found");
}
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The Da Vinci files?
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack.
--Winston Churchill
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