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Re: 1 = 0

HobbyProggy1-Dec-15 22:00

HobbyProggy

1-Dec-15 22:00

Dominic Burford wrote:
x2 - y2 = xy - y2.
Dividing by (x-y), obtain
x + y = y.

Wrong... aint it?
x2 -y2 / (x-y) => x+y
~~xy -y2 / (x-y) => y+y~~
xy / x-y => 1*1/1-1 => (actually how could you divide this when there is a minus...)
y2 / x-y => y/x-1 => (actually how could you devide this when there is a minus...)

But i guess thats bullshit 2 because it "should"? be x2/x-y - y2/x-y which ruins everything Smile | :)

Okay screw everything... you are wrong, thats all i can say Smile | :)

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Re: 1 = 0

Agent__0071-Dec-15 22:02

Agent__007

1-Dec-15 22:02

HobbyProggy wrote:
xy -y2 / (x-y) => y+y

Nope.
xy-y2 = y(x-y)

You have just been Sharapova'd.

Re: 1 = 0

HobbyProggy1-Dec-15 22:04

HobbyProggy

1-Dec-15 22:04

Ah yeah i started to correct it because i know its not correct Smile | :)

you have to divide every part of that equation that leads to funny result Smile | :)

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Re: 1 = 0

kiLLe_5123-Dec-15 0:15

kiLLe_512

3-Dec-15 0:15

if(!string.IsNullOrEmpty(this.signature))

ftfy

Re: 1 = 0

HobbyProggy3-Dec-15 1:18

HobbyProggy

3-Dec-15 1:18

Thank god signature is not an object you first have to convert .ToString() right?

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Re: 1 = 0

Slacker0071-Dec-15 22:05

Slacker007

1-Dec-15 22:05

http://www.wolframalpha.com/input/?i=x2%3Dxy[^]

you can use this site to experiment with your theories?

Re: 1 = 0

Sander Rossel1-Dec-15 23:01

Sander Rossel

1-Dec-15 23:01

A high school teacher showed this to me some 10+ years back (feeling old now).
All I can say is no.

Visit my blog at Sander's bits - Writing the code you need.
Or read my articles at my CodeProject profile.

Simplicity is prerequisite for reliability.
— Edsger W. Dijkstra

Regards,
Sander

Re: 1 = 0

HobbyProggy1-Dec-15 23:06

HobbyProggy

1-Dec-15 23:06

The only thing i can agree with is that 1 != 3/3 (at least not exactly) because 1/3 is 0,333... and multiplied with 3 it is just 0,99999.... which is technically 1 but not 100%

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Re: 1 = 0

CPallini1-Dec-15 23:10

CPallini

1-Dec-15 23:10

Quote:
0,99999.... which is technically 1 but not 100%

Uh?

Re: 1 = 0

HobbyProggy1-Dec-15 23:14

HobbyProggy

1-Dec-15 23:14

Whats the matter ?

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Re: 1 = 0

CPallini1-Dec-15 23:59

CPallini

1-Dec-15 23:59

0.9999... is 1.

Re: 1 = 0

HobbyProggy2-Dec-15 1:03

HobbyProggy

2-Dec-15 1:03

By definition, not by maths Smile | :)

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Re: 1 = 0

CPallini2-Dec-15 1:32

CPallini

2-Dec-15 1:32

By maths. There's no difference.

Re: 1 = 0

HobbyProggy2-Dec-15 1:34

HobbyProggy

2-Dec-15 1:34

Allright, tell that the next flightcomputer that breakes down because he multiplied 0,333 and didn't get to 1 Wink | ;)

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Re: 1 = 0

CPallini2-Dec-15 1:49

CPallini

2-Dec-15 1:49

You know, float are not real numbers.
(likewise Computer Science is not Mathematics) Big Grin | :-D

Re: 1 = 0

HobbyProggy2-Dec-15 1:53

HobbyProggy

2-Dec-15 1:53

CPallini wrote:
(likewise Computer Science is not Mathematics)

But its both logic Smile | :)

And 0,999 is not 1 it's even written different Sigh | :sigh:

But i guess we could debate ages about that

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Re: 1 = 0

CPallini2-Dec-15 1:59

CPallini

2-Dec-15 1:59

Right: we could follow all the nines until we find a difference. Laugh | :laugh:

Re: 1 = 0

Richard Deeming2-Dec-15 2:06

Richard Deeming

2-Dec-15 2:06

Take your pick: How Can 0.999... = 1? | Purplemath[^]

For example:

      x = 0.999...
10x     = 9.999...
10x - x = 9.000...
     9x = 9
      x = 1

EDIT: As Nagy said[^], 2+ hours ago.

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: 1 = 0

HobbyProggy2-Dec-15 2:22

HobbyProggy

2-Dec-15 2:22

1/6 = 0,166666
->*6
0,9996

x = 0,9996
10x = 9,996
10x -x = 8,9964
9x = 8,9964
x = 0,9996

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Re: 1 = 0

Richard Deeming2-Dec-15 2:34

Richard Deeming

2-Dec-15 2:34

HobbyProggy wrote:
1/6 = 0,166666
->*6
0,9996

Nope - 6 × 0.1666... = 0.9999...

It's simple multiplication:

1 x 6 = 6 (0.6)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.96)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.9996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.99996)
etc.

Because you're repeating the operation an infinite number of times, there's no point where you stop and leave the last digit as 6. There's always another digit to the right which needs to be multiplied by 6, carrying the 3 into the current column.

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: 1 = 0

HobbyProggy2-Dec-15 2:39

HobbyProggy

2-Dec-15 2:39

So this works only for 0.999999 ?
Because the 6 at the end is in this case important to show that it wont be a 1 in the end Smile | :)

But nevermind, this is all just playing with numbers Smile | :)

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Re: 1 = 0

Richard Deeming2-Dec-15 2:48

Richard Deeming

2-Dec-15 2:48

HobbyProggy wrote:
Because the 6 at the end is ...

But there isn't a 6 at the "end", because there isn't an "end"! Laugh | :laugh:

Think of it like this:

using System;

static class Program
{
    static void Main()
    {
        while (true)
        {
            Console.WriteLine("9");
        }
        
        Console.WriteLine("Squirrel!");
    }
}

If you run that program, how long will you have to wait before it prints "Squirrel"?

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: 1 = 0

HobbyProggy2-Dec-15 2:51

HobbyProggy

2-Dec-15 2:51

STACK OVERFLOW Blush | :O

nvm

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Re: 1 = 0

Nelek2-Dec-15 3:40

Nelek

2-Dec-15 3:40

mmm

working by 9, not working by 6

what about 69? does it works?

Oh, wait... I think I stop now since I am about to break the KSS rule Laugh | :laugh:

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Re: 1 = 0

kiLLe_5123-Dec-15 0:17

kiLLe_512

3-Dec-15 0:17

That's bloody brilliant!

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