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Stop dividing by zero (x-y=0)...
(yes|no|maybe)*
"Fortunately, we don't need details - because we can't solve it for you." - OriginalGriff
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Why are you dividing by (x-y) when you started with x=y?
You have just been Sharapova'd.
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Dominic Burford wrote: x2 - y2 = xy - y2.
Dividing by (x-y), obtain
x + y = y.
Wrong... aint it?
x2 -y2 / (x-y) => x+y
xy -y2 / (x-y) => y+y
xy / x-y => 1*1/1-1 => (actually how could you divide this when there is a minus...)
y2 / x-y => y/x-1 => (actually how could you devide this when there is a minus...)
But i guess thats bullshit 2 because it "should"? be x2/x-y - y2/x-y which ruins everything
Okay screw everything... you are wrong, thats all i can say
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HobbyProggy wrote: xy -y2 / (x-y) => y+y Nope.
xy-y2 = y(x-y)
You have just been Sharapova'd.
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Ah yeah i started to correct it because i know its not correct you have to divide every part of that equation that leads to funny result
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if(!string.IsNullOrEmpty(this.signature))
ftfy
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Thank god signature is not an object you first have to convert .ToString() right?
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A high school teacher showed this to me some 10+ years back (feeling old now).
All I can say is no.
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The only thing i can agree with is that 1 != 3/3 (at least not exactly) because 1/3 is 0,333... and multiplied with 3 it is just 0,99999.... which is technically 1 but not 100%
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Quote: 0,99999.... which is technically 1 but not 100% Uh?
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Whats the matter ?
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By definition, not by maths
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By maths. There's no difference.
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Allright, tell that the next flightcomputer that breakes down because he multiplied 0,333 and didn't get to 1
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You know, float are not real numbers.
(likewise Computer Science is not Mathematics)
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CPallini wrote: (likewise Computer Science is not Mathematics)
But its both logic And 0,999 is not 1 it's even written different
But i guess we could debate ages about that
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Right: we could follow all the nines until we find a difference.
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Take your pick: How Can 0.999... = 1? | Purplemath[^]
For example:
x = 0.999...
10x = 9.999...
10x - x = 9.000...
9x = 9
x = 1
EDIT: As Nagy said[^], 2+ hours ago.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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1/6 = 0,166666
->*6
0,9996
x = 0,9996
10x = 9,996
10x -x = 8,9964
9x = 8,9964
x = 0,9996
?
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HobbyProggy wrote: 1/6 = 0,166666
->*6
0,9996
Nope - 6 × 0.1666... = 0.9999...
It's simple multiplication:
1 x 6 = 6 (0.6)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.96)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.9996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.99996)
etc.
Because you're repeating the operation an infinite number of times, there's no point where you stop and leave the last digit as 6 . There's always another digit to the right which needs to be multiplied by 6 , carrying the 3 into the current column.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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So this works only for 0.999999 ?
Because the 6 at the end is in this case important to show that it wont be a 1 in the end
But nevermind, this is all just playing with numbers
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HobbyProggy wrote: Because the 6 at the end is ...
But there isn't a 6 at the "end", because there isn't an "end"!
Think of it like this:
using System;
static class Program
{
static void Main()
{
while (true)
{
Console.WriteLine("9");
}
Console.WriteLine("Squirrel!");
}
}
If you run that program, how long will you have to wait before it prints "Squirrel"?
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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STACK OVERFLOW
nvm
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