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My thought exactly, there must be dozens of possible answers, and without further information we can just regard all of them as correct.
"If you don't fail at least 90 percent of the time, you're not aiming high enough."
Alan Kay.
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2
(1 + 0 + 1 + 0 ) * 1 = 2
Marc
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Those who fail to learn history are doomed to repeat it. --- George Santayana (December 16, 1863 – September 26, 1952)
Those who fail to clear history are doomed to explain it. --- OriginalGriff (February 24, 1959 – ∞)
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Damn it, you beat me to it 
Microsoft ... the only place where VARIANT_TRUE != true
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Overflow Exception
Microsoft ... the only place where VARIANT_TRUE != true
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11*11 = 121 -> sum of digits = 4
22*22 = 484 -> sum of digits = 16
10*10 = 100 -> sum of digits = 1
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Smart thinking!
I saw it differently, but I don't know if it would have applied for all cases:
11*11 -> (1+1)*(1+1) -> 2*2 = 4
22*22 -> (2+2)*(2+2) -> 4*4 = 16
10*10 -> (1+0)*(1+0) -> 1*1 = 1
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Which proves the problem is underspecified.
One day I aspire to having a signature.
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Right. There are several paths to a solution. We can only speculate about the intended solution.
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Nonsense. It is only underspecified if there isn't sufficient informatino to reach a solution. The existence of multiple paths to a correct solution does not imply a lack of specification, else the entire concept of OOP would fail.
Will Rogers never met me.
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I disagree, a puzzle should have just one correct solution, and sufficient clues to infer the correct solution.
The problem presented has too many correct solutions, and not enough rules specified to determine the answer.
Imagine a jigsaw puzzle with multiple solutions, or a crossword, or Sudoku, or a chess problem, or ...
(Unless the problem is to find all correct solutions - but in this case I suspect that could be pretty close to infinite).
"If you don't fail at least 90 percent of the time, you're not aiming high enough."
Alan Kay.
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1
Reason is like that?
11*11=4 means (1+1)*(1+1)=4
22*22=16 means (2+2)*(2+2)=16
so
10*10=(1+0)*(1+0)=1. 
modified 16-Jul-14 3:30am.
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Quote: 10*10=(1+0)*(1+1)=1.
should that be (1+0)*(1+0) = 1, as I'm pretty sure (1+0)*(1+1) gives 1*2 = 2 or am I missing something?
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Sorry, I've written wrong. I've just modified my answer.
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You've got the first two wrong and you want me to solve the third one for you?
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There are only 10 types of people in the world, those who understand binary and those who don't.
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I'm sorry, my responses are limited. You must ask the right questions.
Peter Wasser
"The whole problem with the world is that fools and fanatics are always so certain of themselves, and wiser people so full of doubts." - Bertrand Russell
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ok, where did you hide MH370?
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Is it home time yet?
Every day, thousands of innocent plants are killed by vegetarians.
Help end the violence EAT BACON
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No, looking busy while dealing with nothing very much aside from applying for other jobs, isn't really time occupying 
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No solution.
Programmatically, the computer should detect that the second character in 10 is not the same as the first and thereby fails the pattern that you had previously established. Ergo, aa*aa is the only established pattern here.
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Have you seen this Microsoft video game, Escape From XP?
https://escapefromxp.azurewebsites.net/[^]
It's interesting that they put that much work into this. When the game comes up if you just die you'll get "rescued from XP" and then you'll see Giant Clippy get blown up. Kind of funny.
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Haha funny, Oh these red evil eyes on IE 
Thank you for sharing the link with us.
Microsoft ... the only place where VARIANT_TRUE != true
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That was a weird experience: XP loading and a BSOD on my tablet!
Those who fail to learn history are doomed to repeat it. --- George Santayana (December 16, 1863 – September 26, 1952)
Those who fail to clear history are doomed to explain it. --- OriginalGriff (February 24, 1959 – ∞)
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