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Mathematicians at CERN Discover End of Prime Numbers
[-- Dalgen Schizfeld, Chief Numerical Scientist at CERN has discovered the end of the Prime Numbers.
"The last and largest prime has 12,389,238,993,382 digits in it. We've recently discovered that everything after that number is divisible by 2 evenly. It's a strange phenomenon but we figured it would happen one day." --]
Where'd that link go?
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That goes no where, but just shows how weak we humans are that even the genius of us are bound to believe in a metaphysical truth.
The sh*t I complain about
It's like there ain't a cloud in the sky and it's raining out - Eminem
~! Firewall !~
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... for at least one value for 2.
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This is completely true news. Just need to find that link.
"They" don't want you to know about it because of the implications on modern cryptography.
Prime numbers are busted! Prime numbers are over.
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No doubt they are past their prime.
There are only 10 types of people in the world, those who understand binary and those who don't.
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RyanDev wrote: No doubt they are past their prime.
Absolutely terrible pun!
Love it! 
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newton.saber wrote: "The last and largest prime has 12,389,238,993,382 digits in it.
There is no number after that. You fall into a mathematical abyss where imaginary dragons will eat you. This also proves that the universe if flat.
Marc
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Marc Clifton wrote: This also proves that the universe if flat.
Your universe threw a compile-error, saying "flat" is not a valid boolean.
Bastard Programmer from Hell 
If you can't read my code, try converting it here[^]
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That's OLD news. Sheesh, mathematics has come a long way since then with all our newfangled technology. We now stuff that Euclid couldn't even dream about, like the end of primes.
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Euclid was obviously pressured by the clerics, yet on his death-bed he muttered "they still end".
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newton.saber wrote: "The last and largest prime has 12,389,238,993,382 digits in it. We've recently discovered that everything after that number is divisible by 2 evenly"
Er yeah.
What if the 12,389,238,993,382nd digit is 3?
I wanna be a eunuchs developer! Pass me a bread knife!
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Mark_Wallace wrote: What if the 12,389,238,993,382nd digit is 3?
THat's old math.
It is sad to see the uneducated try to understand how this advanced math system works.
Very sad indeed.
The primes are over so get over it.
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It's true for values of 2 close to 1.5 .
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May the prime be with you!
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I've gotta tell ya: as wannabe-jokes go, this one isn't even as funny as: "Hey, scientists say that gravity doesn't attract, any more, so buy lots of duct tape to keep your sht1 from flyin' off!"
To hit the funnybone you're aiming at, your point has to be something that's believable enough to make people stop and think about it.
The "all numbers above n are divisible by two" thing is just not going to cut it in a developers' forum.
I wanna be a eunuchs developer! Pass me a bread knife!
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Mark_Wallace wrote: The "all numbers above n are divisible by two" thing is just not going to cut it in a developers' forum.
It might for large values of 2.
I'm retired. There's a nap for that...
- Harvey
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H.Brydon wrote: It might for large values of 2.
Ah, you mean the "2" part, rather than the "1" part. I see what you mean.
With Boolean values in a non-zero-based system, the "1" would be the zero, and the "2" would be the 1, and, as such, becomes a factor of any integer, without a remainder!
Now I get it!
(Now that's absurd!)
I wanna be a eunuchs developer! Pass me a bread knife!
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Some of us find absurdity amusing. 'Tis unfortunate that you do not.
Software Zen: delete this;
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I would if it were but it ain't so I can't.
I wanna be a eunuchs developer! Pass me a bread knife!
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Mark_Wallace wrote: The "all numbers above n are divisible by two" thing is just
not going to cut it in a developers' forum.
You just need to choose the correct numbering system.
In any binary floating-point system, there will be a largest representable odd integer. All representable numbers larger than that will be integers, and divisible by two.
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack.
--Winston Churchill
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Ah, but then some evil genius (probably Doctor Doom or the Master) will come along and stick a "1" on the end, break all our computer systems, and take over the world in the ensuing chaos.
Better not to go there, I think.
I wanna be a eunuchs developer! Pass me a bread knife!
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Mark_Wallace wrote: Ah, but then some evil genius (probably Doctor Doom or the Master) will come along and stick a "1" on the end
Converting IEEE binary64 to binary65, and simultaneously modifying the hardware on every IEEE floating point-compatible machine in the world?
Not even Chuck Norris could do that! 
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack.
--Winston Churchill
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