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Re: One from an interview

OriginalGriff3-Dec-13 5:24

3-Dec-13 5:24

That was my answer as well!

Re: One from an interview

fixthebugg3-Dec-13 5:27

3-Dec-13 5:27

316

Re: One from an interview

Rob Philpott3-Dec-13 5:28

3-Dec-13 5:28

Splendid!

Regards,
Rob Philpott.

Re: One from an interview

fixthebugg3-Dec-13 5:30

3-Dec-13 5:30

I had seen it before.. Poke tongue | ;-P

Poke tongue | ;-P

Re: One from an interview

Rob Philpott3-Dec-13 5:33

3-Dec-13 5:33

Kudos destroyed. Too honest!

Regards,
Rob Philpott.

Re: One from an interview

Simon_Whale3-Dec-13 5:28

3-Dec-13 5:28

317 or there abouts I would guess

Do'h just realised that I has also added the last game D'Oh! | :doh:

D'Oh! | :doh:

so it would be 316

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Help end the violence EAT BACON

Re: One from an interview

Rob Philpott3-Dec-13 5:29

3-Dec-13 5:29

Yes, don't think winners going through, think losers dropping out. 317 = 1 winner and 316 losers. Each loser loses only one game...

Regards,
Rob Philpott.

Re: One from an interview

Jörgen Andersson3-Dec-13 5:45

Jörgen Andersson

3-Dec-13 5:45

What about the Bronze match?

Politicians are always realistically manoeuvering for the next election. They are obsolete as fundamental problem-solvers.
Buckminster Fuller

Re: One from an interview

MehGerbil3-Dec-13 5:48

3-Dec-13 5:48

I don't know much about tennis so I couldn't even guess at an answer.

Re: One from an interview

Dalek Dave3-Dec-13 5:58

3-Dec-13 5:58

It is a sub-topic of Set Theory I believe.

---------------------------------
Obscurum per obscurius.
Ad astra per alas porci.
Quidquid latine dictum sit, altum videtur.

Re: One from an interview

Nagy Vilmos3-Dec-13 6:17

3-Dec-13 6:17

It's covered by matches in game theory.

speramus in juniperus

Re: One from an interview

MehGerbil3-Dec-13 7:06

3-Dec-13 7:06

I'm sure I could put together a solution in .Net.

Re: One from an interview

pkfox4-Dec-13 11:44

4-Dec-13 11:44

If you don't know how could you code it ? Wink | ;-)

Wink | ;-)

We can’t stop here, this is bat country - Hunter S Thompson RIP

Re: One from an interview

MehGerbil4-Dec-13 16:42

4-Dec-13 16:42

That is what QA is for...

Re: One from an interview

Marc Clifton3-Dec-13 7:12

3-Dec-13 7:12

Rob Philpott wrote:
How many matches need to be played to determine the winner?

[edit] Ignore me. My brain is addled. I hate word problems.[/edit]

Marc

Day 1: Spider Database Navigator
Unit Testing Succinctly

Corporal Agarn3-Dec-13 4:25

3-Dec-13 4:25

All these mathematics problems make my brain hurt. Smile | :)

Smile | :)

I come to the lounge to lounge not remember my quadratic equation lessons. Poke tongue | ;-P

Poke tongue | ;-P

Re: Brain hurts

Nagy Vilmos3-Dec-13 4:33

3-Dec-13 4:33

I get the same trying to solve the Gin problem.

speramus in juniperus

Re: Brain hurts

vonb3-Dec-13 4:35

3-Dec-13 4:35

For me will be the wine problem / solution in less then an hour.. Big Grin | :-D

Big Grin | :-D

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Re: Brain hurts

Nagy Vilmos3-Dec-13 4:38

3-Dec-13 4:38

The good news is that alcohol is a solution...

speramus in juniperus

Re: Brain hurts

vonb3-Dec-13 4:39

3-Dec-13 4:39

Nagy Vilmos wrote:
alcohol is a solution

At this time of the day, yes..

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Re: Brain hurts

Richard Deeming3-Dec-13 4:56

Richard Deeming

3-Dec-13 4:56

vonb wrote:
in less then an hour..

http://www.youtube.com/watch?v=VFEEa-jibhs[^]

"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer

Re: Brain hurts

vonb3-Dec-13 7:29

3-Dec-13 7:29

Of course less than an hour.. The wine was good so..

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Re: Brain hurts

vonb3-Dec-13 4:34

3-Dec-13 4:34

You can do math for fun sometimes.. Smile | :)

Smile | :)

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Re: Brain hurts

R. Giskard Reventlov3-Dec-13 5:39

R. Giskard Reventlov

3-Dec-13 5:39

oxymoron

"If you think it's expensive to hire a professional to do the job, wait until you hire an amateur." Red Adair.
Those who seek perfection will only find imperfection
nils illegitimus carborundum

me, me, me
me, in pictures

A more computer-related math problem

harold aptroot3-Dec-13 3:52

3-Dec-13 3:52

Now that we're in the mood..

Determine ~~how often (x & y) == 0 for x and y both 32bit integers.~~
for how many pairs (x, y) where x and y are both 32bit integers, (x & y) == 0.

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