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I thought it was "English-speaking North America versus the World"?
It is often shortened to maths or, in English-speaking North America, math.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Richard Deeming wrote: I thought it was "Not-Quite-English-speaking North America versus the World"?
ftfy
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Obscurum per obscurius.
Ad astra per alas porci.
Quidquid latine dictum sit, altum videtur .
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Congratulations, you win.
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Ok, but why? (Please  )
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Each position has 4 options 0,0 0,1 1,0 or 1,1 3 of which will give 0 and there are 32 positions.
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Thanks, as usual, it makes sense when looked at from the right angle
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That's hard! The number is huge, and thinking about it has lead to delirium. Please help. For example, I can see the answer for all pairs where the first of the numbers is of the form 10000000000000000000000000000000, 01000000000000000000000000000000, etc. (i.e. a single bit is flipped. - each has 1^31 paired values.) But my head swims when I try to extend this. Usually, there's some other clever way of simplifying the problem, but I sure don't see it.
Is there a simple way to think about this, or is it a lot of calculation?
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There is a simple way of course, I wouldn't ask you guys to try 264 combinations Ok I might, but I didn't.
Here's a start: consider the 1-bit case. 3 out of 4 inputs give 0.
There are several different ways to go from there.
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You could also "cheat" and use algorithms and data structures instead of just math, for example: made an ROBDD representing the function "x & y == 0" (that BDD is pretty small) and count its solutions (in time depending mainly on the size of the BDD, not the magnitude of the answer). (that's what my site[^] does)
That way you might not see that it's 332 though, just the raw number, and it's a little hard to take 1853020188851841 and figure out where it came from, so to speak.
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Time yourself.
I reckon under 30 seconds for most people here:
Solve for x:
(x+1)(x+2)(x+6) = x^3+9x^2+4(7x-1)
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Obscurum per obscurius.
Ad astra per alas porci.
Quidquid latine dictum sit, altum videtur .
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x=4
speramus in juniperus
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x=42
There are only 10 types of people in the world, those who understand binary and those who don't.
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x = beer
Microsoft ... the only place where VARIANT_TRUE != true
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You are only half right:
x = beer + bacon
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(x+1)(x+2)(x+6) =
x^3+9x^2+20x+12 = x^3+9x^2+4(7x-1)
20x+12=4(7x-1)
5x+3=7x-1
4=2x
x = 2
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Congratulations! I'm sure you get an A in GSCE maths for that, or possibly even an A at A-level these days.
Not that they've dumbed down or anything...
Regards,
Rob Philpott.
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I lost an x somewhere doing it in my befuddled brain.
speramus in juniperus
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x=2
(3)(4)(8) = 8 + 36 + 52
96 = 96
Will Rogers never met me.
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(x+1)(x+2)(x+6) = x^3+9x^2+4(7x-1)
x³ + 9x² + 20x + 12 = x³ + 9x² + 28x - 4 |-x³
9x² + 20x + 12 = 9x² + 28x -4 |-9x²
20x + 12 = 28x -4 |-20x |+4
16 = 8x
x = 2
if not i would say 42 too 
"WAKE UP, NEO."
"THE MATRIX HAS YOU..."
"FOLLOW THE WHITE RABBIT".
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What's the point?
"If you think it's expensive to hire a professional to do the job, wait until you hire an amateur." Red Adair.
Those who seek perfection will only find imperfection
nils illegitimus carborundum
me, me, me
me, in pictures
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I like this answer 
I still don't understand how they got it though
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Ok now my head does hurt.
What kind of math is this ?
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