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I guess I failed to explain better.
I have one HGLOBAL. This is used to create an image of type System::Drawing::Bitmap.
HGLOBAL hdl = GloabalAlloc(BitmapImageSize);
PBITMMAPINFOHEADER bmih = (PBITMAPINFOHEADER)GlobalLock(hdl);
LPDWORD ImgBits = (LPDWORD)(bmih + sizeof(BITMAPINFOHEADER));
....
....
....
StretchDIBits()......
That gives me an image from an HGLOBAL
If I had an image already in memory, from some other means (loaded from file maybe), I want to then point that image to the HGLOBAL.
Hope that was clearer
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OK thanks for that.
How then do you copy that to HGLOBAL?
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alleyes wrote: The Bitmap images in memory use the System::Drawing::Bitmap classes not the GDI+ version.
System.Drawing IS the managed version of GDI+.
It's using GDI+ in its implementation. So your
images ARE GDI+ images.
Why do you need to use an HGLOBAL in a managed application?
If you need old school GDI BITMAPINFOHEADER stuff you
can certainly construct that info yourself from info
in your GDI+ System.Drawing.Bitmap objects.
For example, to extract 24bpp image data from a
System.Drawing.Bitmap:
using namespace System::Drawing;
using namespace System::Drawing::Imaging;
Bitmap ^bmp = ...;
Rectangle rect = Rectangle(0, 0, bmp->Width, bmp->Height);
BitmapData ^bmpData = bmp->LockBits(rect, ImageLockMode::Read, PixelFormat::Format24bppRgb);
BITMAPINFOHEADER bmiHeader;
bmiHeader.biSize = sizeof(BITMAPINFOHEADER);
bmiHeader.biWidth = bmp->Width;
bmiHeader.biHeight = bmp->Height;
bmiHeader.biPlanes = 1;
bmiHeader.biBitCount = 24;
bmiHeader.biCompression = BI_RGB;
bmiHeader.biSizeImage = abs(bmpData->Stride) * bmpData->Height;
bmiHeader.biXPelsPerMeter = 0;
bmiHeader.biYPelsPerMeter = 0;
bmiHeader.biClrUsed = 0;
bmiHeader.biClrImportant = 0;
bmp->UnlockBits(bmpData);
Mark Salsbery
Microsoft MVP - Visual C++
![Java | [Coffee]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/coffee.gif)
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Let me clarify what I said and thanks for correcting that
Yes you are correct. I was just pointing out that the Images were using the managed version classes. What I hope to accomplish is:
I have one HGLOBAL. This is used to create an image of type System::Drawing::Bitmap.
HGLOBAL hdl = GloabalAlloc(BitmapImageSize);
PBITMMAPINFOHEADER bmih = (PBITMAPINFOHEADER)GlobalLock(hdl);
LPDWORD ImgBits = (LPDWORD)(bmih + sizeof(BITMAPINFOHEADER));
....
....
....
StretchDIBits()......
That gives me an image from an HGLOBAL
If I had an image already in memory, from some other means (loaded from file maybe), I want to then point that image to the HGLOBAL.
The reason for using those deprecated function is the type that is returned from functions in ActiveX controls that handle image acquisition is of HGLOBAL. It is then convenient to use those Global functions and since I am doing a mixed mode app thanks in large part to using C++/CLI I can do this.
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alleyes wrote: I want to then point that image to the HGLOBAL.
What does that mean?
You don't point something to an HGLOBAL.
You can allocate memory as an HGLOBAL and
copy data into that memory, just like you
did using an array in the thread below.
Mark Salsbery
Microsoft MVP - Visual C++
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I have ONE store of heap memory with a handle to it - HGLOBAL. What I am not articulating adequately is that instead of creating a new memory block, I would like to use a common one if that's at all possible with what I described. Is that possible using the LockBits method? Like I said previously, I have one block of heap space and assign that to one image from a picture box. I have actually two picturebox objects on my form and want to the ability to copy the image from the second picturebox to the main heap store that was allocated. This is what I feel is the disconnect.
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The HGLOBAL is just a handle to an allocated block
of memory (a BYTE array). You get a pointer to that
block of memory with GlobalLock().
You can copy whatever you want to it.
It's up to you to make sure that block is large enough to
hold what you write to it.
Mark Salsbery
Microsoft MVP - Visual C++
![Java | [Coffee]](https://www.codeproject.com/script/Forums/Images/coffee.gif)
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Mark Salsbery wrote: You get a pointer to that
block of memory with GlobalLock().
That's what I meant by pointer but mis-construed it a bit.
To summarize then. I can copy the bitmap data to this HGLOBAL using managed Bitmap classes? I do have the advantage of BITMAPINFOHEADER being available from the image that is to be copied from so I have most of that information which happens to be common to both the images in question
If copying to the memory block is the lock still in place or do you call an GlobalUnLock first.
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alleyes wrote: I can copy the bitmap data to this HGLOBAL using managed Bitmap classes?
You can't directly copy from managed to unmanaged memory.
You can use Marshal::Copy though. You can also wrap
the pointer in an UnmanagedMemoryStream object so you
can use any managed functionality that uses a Stream object.
For example, you could write a BMP file from a Bitmap to
memory in one line of code instead of building the headers
manually.
alleyes wrote: If copying to the memory block is the lock still in place or do you call an GlobalUnLock first.
You use the pointer while it's locked.
Mark Salsbery
Microsoft MVP - Visual C++
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Mark Salsbery wrote: You can't directly copy from managed to unmanaged memory.
You can use Marshal::Copy though
I fully intended using the Marshal class for copying.
Mark Salsbery wrote: You can also wrap
the pointer in an UnmanagedMemoryStream object so you
can use any managed functionality that uses a Stream object.
Now you threw me a bit. One of the things I was considering was saving the image to a managed memory stream object. Why consider unmanaged? By calling the Save method and then specifying BMP as the image type, I do get the BITMAPHEADERINFO.
This is what I'm building upon without doing the Save to Stream technique:
System::Drawing::Rectangle imgRect =
System::Drawing::Rectangle(0, 0,
MyImage->Width, MyImage->Height);
System::Drawing::Imaging::BitmapData^ bmpData =
MyImage->LockBits(imgRect,
System::Drawing::Imaging::ImageLockMode::ReadOnly,
System::Drawing::Imaging::PixelFormat::Format32bppRgb);
int byteCount = bmpData->Stride * MyImage->Height;
array<Byte>^ bmpBytes = gcnew array<Byte>(byteCount);
Marshal::Copy(bmpData->Scan0, bmpBytes, 0, byteCount);
MyImage->UnlockBits(bmpData);
Once I have the image in an array shouldn't I be copying it to the HGLOBAL? Or should the destination be the HGLOBAL and forget about the array?
modified on Wednesday, January 20, 2010 2:42 PM
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I think I have the solution:
MemoryStream^ ms = gcnew MemoryStream();
MyImage->Save(ms, System::Drawing::Imaging::ImageFormat::Bmp);
array<Byte>^ bits = gcnew array<Byte>(MyHeader->biSizeImage);
bits = ms->GetBuffer();
ms->Close();
Marshal::Copy(bits, 0, static_cast<IntPtr>(MyHGlobal), bits->Length);
Where:
MyHeader->biSizeImage is the member from the BITMAPINFOHEADER
MyHGlobal is the handle to the locked memory block.
I then throw an AccessViolationException at the copy call. I think that perhaps the array size may be bigger than the memory block.
I appreciate your help so far - I'm close!
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I said UnmanagedMemoryStream, not MemoryStream.
And you don't cast an HGLOBAL to a pointer - GlobalLock
returns the pointer.
And Bitmap::Save() saves everything - BITMAPFILEHEADER,
BITMAPINFO, and the pixel bits.
You're trying to make it harder than it is 
void *pMyGlobalMemory = GlobalLock(MyHGlobal);
UnmanagedMemoryStream^ ms = gcnew UnmanagedMemoryStream(IntPtr(pMyGlobalMemory), GlobalSize(MyHGlobal));
MyImage->Save(ms, System::Drawing::Imaging::ImageFormat::Bmp);
GlobalUnlock(MyHGlobal);
Mark Salsbery
Microsoft MVP - Visual C++
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I get an error when trying that:
Error C2664: 'System::IO::UnmanagedMemoryStream::UnmanagedMemoryStream(unsigned char *,__int64)' : cannot convert parameter 1 from 'System::IntPtr' to 'unsigned char *'
I didn't consider the UnmanagedMemoryStream
Mark Salsbery wrote: You're trying to make it harder than it is Smile
Yeah it seems that way 
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Oops wrong constructor
unsigned char *pMyGlobalMemory = (unsigned char *)GlobalLock(MyHGlobal);
UnmanagedMemoryStream^ ms = gcnew UnmanagedMemoryStream(pMyGlobalMemory, GlobalSize(MyHGlobal));
Note you're still resonsible for making sure the
allocated global memory is large enough to write to.
GlobalSize() will give you the allocated size, but if you
don't know how many bytes will be written, you'll need to
write to a growable memory stream first, check how many bytes
were written, compare it to the globally allocated size, and
reallocate if you need more room.
Mark Salsbery
Microsoft MVP - Visual C++
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I made a small change:
void* pMyGlobal = GlobalLock(MyHGlobal);
UnmanagedMemoryStream^ ms = gcnew UnmanagedMemoryStream((unsigned char*)(pMyGlobal), GlobalSize(gPtrImage));
MyImage->Save(ms, System::Drawing::Imaging::ImageFormat::Bmp);
It builds but then I get ExternalException was unhandled in GDI+
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alleyes wrote: It builds but then I get ExternalException was unhandled in GDI+
I can't debug that for you from here, but I suspect
not enough allocated on the HGLOBAL.
So maybe something like this:
MemoryStream^ ms = gcnew MemoryStream();
MyImage->Save(ms, System::Drawing::Imaging::ImageFormat::Bmp);
if (GlobalSize(MyHGlobal) < ms->Length)
{
GlobalRealloc(MyHGlobal, ms->Length, 0);
}
void *pMyGlobalMemory = GlobalLock(MyHGlobal);
UnmanagedMemoryStream^ ums = gcnew UnmanagedMemoryStream((unsigned char *)pMyGlobalMemory, GlobalSize(MyHGlobal));
ms->WriteTo(ums);
GlobalUnlock(MyHGlobal);
Mark Salsbery
Microsoft MVP - Visual C++
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Mark Salsbery wrote: I can't debug that for you from here
No of course not.
I was suspecting perhaps an image already in memory was the issue and maybe that needed a dispose method called, not sure.
Thanks for the re-size tip 
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NotSupportedException unhandled.
Stream does not support writing?
Since when? 
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Sorry try another constructor:
...gcnew UnmanagedMemoryStream((unsigned char *)pMyGlobalMemory, GlobalSize(MyHGlobal), GlobalSize(MyHGlobal), FileAccess.ReadWrite);
Mark Salsbery
Microsoft MVP - Visual C++
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Ugh!
Still getting an AccessViolation Exception.
That can either mean not enough memory available or is that this memory can't be written to.
I see the CanWrite, CanSeek flags are TRUE. Capacity and Length are both the same - 1658934
modified on Thursday, January 21, 2010 9:22 AM
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Did you use FileAccess.ReadWrite?
I'm only guessing here since I don't know
what line the exception occurs on...
Mark Salsbery
Microsoft MVP - Visual C++
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Hi,
This is what I have so far:
MemoryStream^ ms = gcnew MemoryStream();
MyImage->Save(ms, System::Drawing::Imaging::ImageFormat::Bmp);
ms->Seek(0, SeekOrigin::Begin);
if (GlobalSize(MyGlobal) < ms->Length)
{
GlobalReAlloc(MyGlobal, (LONG)ms->Length, 0);
}
void* pMyGlobal = (UCHAR*)MyGlobal;
UnmanagedMemoryStream^ ums = gcnew UnmanagedMemoryStream((UCHAR*)pMyGlobal, GlobalSize(MyGlobal), GlobalSize(MyGlobal), FileAccess::ReadWrite);
ums->Position = 0;
ms->WriteTo(ums);
It occurs on the line:
ms->WriteTo(ums);
This is even without setting the Position of the streams. I did this because just before the Call to WriteTo, the position was set to Length.
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Where did this come from?
void* pMyGlobal = (UCHAR*)MyGlobal;
Casting a handle to a pointer is bad.
For an HGLOBAL it's bad unless you know for sure
GMEM_FIXED was used to allocate the memory.
Much safer to use GlobalLock to get the pointer.
Mark Salsbery
Microsoft MVP - Visual C++
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Sorry I threw you there.
The lock is already done earlier during the creating of the original images. Didn't make sense to call another GlobalLock on it again. The call to GlobalAlloc is GlobalAlloc(GMEM_MOVEABLE, Size)
You have to call GlobalLock on the existing memory again?
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alleyes wrote: The lock is already done earlier during the creating of the original images. Didn't make sense to call another GlobalLock on it again. The call to GlobalAlloc is GlobalAlloc(GMEM_MOVEABLE, Size)
Then you need to use the pointer returned by
the GlobalLock() call.
Mark Salsbery
Microsoft MVP - Visual C++
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