XML / XSL Discussion Boards

Steven Campbell13-Apr-04 8:47

13-Apr-04 8:47

You could wait for the next version of Visual Studio .NET - apparently XML support is vastly improved. (I cannot recall where I heard that exactly).

searching for xmlNode

Anonymous15-Mar-04 8:48

Anonymous

15-Mar-04 8:48

Hi!

I have a xmlDocument and would like to read and load only just the node I´m searching for
, that is looking for the right node on the xmlFile (since the xmlDocument is large it seems
unnecesary to read the whole xmlDocument to memory and then look for
the right node) is it possible?

Thomas Andersson

Re: searching for xmlNode

Philip Fitzsimons16-Mar-04 3:45

Philip Fitzsimons

16-Mar-04 3:45

you need to look into SAX - in c# you would use XmlTextReader
http://www.xml.com/pub/a/2003/07/09/xmlapis.html[^]

"When the only tool you have is a hammer, a sore thumb you will have."

Re: searching for xmlNode

sinnen16-Mar-04 11:02

sinnen

16-Mar-04 11:02

Thx!

Just what I was looking for!

Thomas Andersson

Re: How do I get the XmlNode?

sinnen18-Mar-04 6:15

sinnen

18-Mar-04 6:15

Hmm...

Mayby I was a bit to fast.....sure I do find the XmlNode I´m looking for, but
since the XmlTextReader is a read-only class it doesn´t seem to be a way to
get the actual XmlNode? Any sugestions?

Thomas Andersson

Re: searching for xmlNode

Jiten_Soni29-Mar-04 2:04

Jiten_Soni

29-Mar-04 2:04

U can use Document Object Model for This .Create an Object of Xml DOM and take the reference and then use the Method GetNodeByName .

It's Jeet

Re: searching for xmlNode

Philip Fitzsimons29-Mar-04 2:34

Philip Fitzsimons

29-Mar-04 2:34

This is exactly what he does not want to do.
using dom would require loading the whole document first.

"When the only tool you have is a hammer, a sore thumb you will have."

Re: searching for xmlNode

JakubSK31-Mar-04 11:25

JakubSK

31-Mar-04 11:25

Well, since XML is tree-based, you have to somehow traverse the document, starting at the root, even if youre talking about an XPath location. If you don't read in the entire document, there would technically be no way to get to that node you require. Also, if your xml file is really that huge, use a stream reader. Although, you won't have capability to access the document randomly, it would be forward-only, but you would be saving a bunch on memory. Therefore, if you know where the node is exactly and it wouldn't change position, you can hard-code a solution.

Re: searching for xmlNode

Steven Campbell13-Apr-04 9:01

Steven Campbell

13-Apr-04 9:01

XPathDocument is the simple solution. It is a lightweight version of XmlDocument designed for searching for specific nodes.

It is not a 100% fit, because it *does* load the whole document into memory, but it is much better than XmlDocument, because it does not have the same processing overhead.

If you absolutely do not want the whole document in memory, then you can use an XmlReader. If you are already familiar with SAX, there is a comparison of SAX and XmlReader in the framework documentation. They take different, but (InMyOpinion) equal approaches in terms of efficiency.

transform dynamically generated xml doc

vancouver7778-Mar-04 21:00

vancouver777

8-Mar-04 21:00

I am trying to transform xml doc to reformat, but only i got is the title i've specified in xsl file and no match element dispalyed in result.
Is there something i missing here?
set xml = Server.CreateObject( "Microsoft.XMLDOM" )
xml.async = FALSE
xml.load( Server.MapPath("orders.asp") )

set xsl = Server.CreateObject( "Microsoft.XMLDOM" )
xsl.async = FALSE
xsl.load( Server.MapPath("orders.xsl") )

Response.Write(xml.transformNode(xsl))

thanks

Re: transform dynamically generated xml doc

Philip Fitzsimons9-Mar-04 6:18

Philip Fitzsimons

9-Mar-04 6:18

we need to see the xsl and xml...

"When the only tool you have is a hammer, a sore thumb you will have."

Re: transform dynamically generated xml doc

Michael Flanakin22-Mar-04 5:16

Michael Flanakin

22-Mar-04 5:16

One thing that always helps me when working with XML transformations is to load the XML and XSL pages in IE. If there are formatting issues IE will point them out. When working with them a lot, you can sometimes forget a few small things.

Another thing you could do, is use a client-side tester. JavaScript points out errors better than ASP, in my experience. Then again, I haven't done a lot of ASP XML. Here's some JavaScript to do that:

<script type="text/javascript">
// Load XML 
var xml = new ActiveXObject('Microsoft.XMLDOM');
xml.async = false;
xml.load('CSDHD-IS Architecture.mof.xml');
 
// Load XSL
var xsl = new ActiveXObject('Microsoft.XMLDOM');
xsl.async = false;
xsl.load('MofToCSharp.xsl');
 
// Transform 
document.write(xml.transformNode(xsl));
</script>

Michael Flanakin
Web Log

SAX in C#

Noodnik8-Mar-04 12:40

Noodnik

8-Mar-04 12:40

I've got a big and deep XML file I want to extract values from. My webservice is currently entirely in C#.

I thought to use SAX because I just want to build up a two-column dataset from my XML file: the PATH and the TEXT VALUE.

E.g.:

/root=
/root/node=2
/root/node/sub=SomeText
/root/node2=3
/root/node2/sub=Some More Text

Since I've used SAX before to easily build up the "path" part, I searched for a SAX parser in .NET and on the net and am VERY surprised that I can't find one!!

Anyways, I'm new to XSLT et. al. and suspect there's a quick way for me to do what I want there (e.g. to build up this two column file WITHOUT knowing the names of the nodes). Can anyone suggest how, or even a small stylesheet to do this??

Thanks for any [good] advice!

Re: SAX in C#

Philip Fitzsimons9-Mar-04 6:13

Philip Fitzsimons

9-Mar-04 6:13

in xslt use the name() function, and to get paths just use the parent axis..

"When the only tool you have is a hammer, a sore thumb you will have."

Re: SAX in C#

Jeremy Kimball17-Mar-04 8:09

Jeremy Kimball

17-Mar-04 8:09

I'd have to think about it a bit, but my guy tells me what you're looking for is to subclass XmlReader, which is basically a SAX parser that doesn't toss events; it's all manual.

If I think of anything better, I'll add to this...

Jeremy Kimball

User Controls & XSLT

Andrew Porter8-Mar-04 4:01

Andrew Porter

8-Mar-04 4:01

Has anyone embedded an ASP .Net user control into an XSLT file successfully? I have had a go and also seen some examples on the internet but nothin seems to work. Any working examples will be greatly appreciated. D'Oh! | :doh:

XML Save Hanging

Shenthil8-Mar-04 3:02

Shenthil

8-Mar-04 3:02

I am parsing an XML document in a VB Activex Dll and then saving the xml document by calling DOMDocument.save. After this, if I try to edit the .xml file from the source folder, my explorer is hanging. What is the problem?

Shenthil

how to use xsl file in vc++ resources

mahesh.mundra7-Mar-04 22:29

mahesh.mundra

7-Mar-04 22:29

I want to use xsl file as resource . so there is no need to supply it externaly .how can i send a xml file path to xsl file at runtime?

Re: how to use xsl file in vc++ resources

Lee Fuller8-Mar-04 4:30

Lee Fuller

8-Mar-04 4:30

You can specifiy an XSLT file within your XML document using <xsl:stylesheet>, which can be handy for debugging your XML document outside of your normal code-base.

If you are talking about parameters, then you can use <xsl:param> within your XSLT, which you then setup when creating your XML parser object (such as MSXML or the System.Xml) by passing in variables from your code.

Hope this helps,

Lee.

Lee H Fuller
lee@fullerdata.com

transformation problem in win2000

mahesh.mundra7-Mar-04 22:24

mahesh.mundra

7-Mar-04 22:24

I am using Xml file as database. I am using xsl to trasform it. I am calling these files from vc++. it works fine on winxp . but it doesnt work on win2000. it will simply show the tables,text etc.but doesnt show any value from xml. when i tried to trasform using javascript its working fine. but i have to do it from my vc++ code.. please help.. is there any problem in win2000? b'coz sometimes it works fine.

XSLT for XML attributes

act_x7-Mar-04 8:39

act_x

7-Mar-04 8:39

I need to use XSLT to display meanigful information from my XML file .
My XML file is such that i just have elements <A> and with the condition that is always below <A>

<A Name="Main" >

<A Section="A" >


</A>
<A Section="B" >


</A>
</A>

you will find that I have no Data but all information is stored in attributes .
How do i use the "template match" and the
"value-of select" with attributes

I need output like this

My Project
Name : Main
Project : 1101

Section :A
Size: 1
Data:Data1

Section :B
Size: 1
Data:Data2

Re: XSLT for XML attributes

boogs7-Mar-04 20:33

boogs

7-Mar-04 20:33

I have found that a lot of XSLT beginners have this same question. You need the "@" symbol (get it? "at"-symbol for "attributes"??).

eg:

<br />
<xsl:template match="A"><br />
  Section: <xsl:value-of select="@Section" /><br />
  Size: <xsl:value-of select="B/@Size" /><br />
  Data: <xsl:value-of select="B/@Data" /><br />
</xsl:template><br />

youngpup.net

Re: XSLT for XML attributes

Jiten_Soni29-Mar-04 2:07

Jiten_Soni

29-Mar-04 2:07

U can use xsl for Loop

Jeet

Xslt debugger tools recognize <msxsl:script>

Firas Rashid7-Mar-04 0:25

Firas Rashid

7-Mar-04 0:25

Does anyone know Xslt debugger tool that can recognize and debugge the
<msxsl:script> element and the embedded script inside it?

I used some debuggers like XMLSPY, but it consider a call to function
defined in embedded script like "<xsl:value-of
select='udf:somefunction();'>", it consider it as a not valid XPath
or variable.

I already know that <msxsl:script> element is Microsoft extension to
Xslt standards so its not expected to find alot -if not at all- of
debuggers dealing with such element, but maybe someone can guide me
here.

Thanx in advance.

getting start and end text in a node?

Roger Alsing6-Mar-04 9:58

Roger Alsing

6-Mar-04 9:58

Hi,

i have a html'ish xml that i want to transform into real html . like this:

"some plain text <bold>somebold <italic>some bold-italic text</italic> more bold </bold> more plain text"

i want to output that to html like this:
"some plain text somebold some bold-italic text more bold more plain text"
how do i do this?

ive created an xslt file that contains a match tag for each of my custom tags.
like this:

<xsl:template match="italic"><br />
	<i>***<br />
	<xsl:value-of select="*"/>		<br />
	<xsl:apply-templates select="*"/><br />
	***</i><br />
</xsl:template>

the problem is that i dont know how to output the text inside the tags in a good way..

take the following sample

"<bold>hello<italic>this</italic>is a <italic>test</italic>blabla</bold>"

how can i do to make "hello","is a","blabla" to be outputted as bold text?
if i do as above with the value-of , it just outputs the whole innertext as a single string and then applies the templates..

//Roger

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