Database

Luc Pattyn20-Feb-11 11:13

Luc Pattyn

20-Feb-11 11:13

in SQL string literals need quotes, so I would suggest you try:

...VALUES('"+ text +"')"...
          ^          ^

Warning: make sure not to insert anything between the single and double quotes there!

Smile | :)

Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

Mike Certini20-Feb-11 11:39

Mike Certini

20-Feb-11 11:39

Luc,

Thank you for your reply.

Luc Pattyn20-Feb-11 11:43

Luc Pattyn

20-Feb-11 11:43

You're welcome.

Smile | :)

Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

Mike Certini20-Feb-11 11:44

Mike Certini

20-Feb-11 11:44

Luc,

I am getting the error message: "error C2110: '+' : cannot add two pointers"

Luc Pattyn20-Feb-11 12:03

Luc Pattyn

20-Feb-11 12:03

one cannot add pointers together, it doesn't make sense; adding house numbers wouldn't make sense either.

What is your code, and what is the exact line where the error occurs? and what language and IDE are you using?

Smile | :)

Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

Mike Certini20-Feb-11 13:28

Mike Certini

20-Feb-11 13:28

Luc,

The error is occuring at VALUES('"+ text + "'). My VS2008 is giving me this error. I am trying to send a record to MS Access.

Mycroft Holmes20-Feb-11 11:13

Mycroft Holmes

20-Feb-11 11:13

You need to enclose your varchar value in single quotes.

hr = rec2->Open("INSERT INTO mytable(id)VALUES('"+ text +"')",con2.GetInterfacePtr(), ADODB::adOpenForwardOnly, ADODB::adLockReadOnly, ADODB::adCmdText);

I find string.Format() to be VERY useful!

Never underestimate the power of human stupidity
RAH

Wendelius20-Feb-11 19:27

Automatic update table based on time

20-Feb-11 19:27

You cannot directly use local variables inside your SQL statements. You can use a Parameter object to pass a value from a variable to the statement. For example see, http://msdn.microsoft.com/en-us/library/ms677589(VS.85).aspx[^]

The need to optimize rises from a bad design.My articles[^]

AhmedMasum20-Feb-11 2:52

AhmedMasum

20-Feb-11 2:52

Suppose some one purchased a ticket online. [Here the value of a column is pending]
If the person does not pay the cash money within 24 hours than the ticket will be automatically cancelled. [The value of the status column will be cancelled after 24 hours]
So,
How can I do automatic update of a table after 24 hours???

R. Giskard Reventlov20-Feb-11 3:14

R. Giskard Reventlov

20-Feb-11 3:14

Easiest way would be to run a job[^] at a specified interval that checks the table and does whatever it needs to do.

"If you think it's expensive to hire a professional to do the job, wait until you hire an amateur." Red Adair.
nils illegitimus carborundum

me, me, me

AhmedMasum22-Feb-11 1:41

AhmedMasum

22-Feb-11 1:41

You have done this using sql server. But How can I do this for oracle??

Eddy Vluggen20-Feb-11 5:03

Eddy Vluggen

20-Feb-11 5:03

AhmedMasum wrote:
Suppose some one purchased a ticket online. [Here the value of a column is pending]
If the person does not pay the cash money within 24 hours than the ticket will be automatically cancelled. [The value of the status column will be cancelled after 24 hours]

It's not pending, it's reserved from that moment forward. Otherwise you could run into the problem that there's more pending than there's actually available.

AhmedMasum wrote:
How can I do automatic update of a table after 24 hours???

I'd run through it once an hour, processing the valid payments (sending out a ticket to an address) and the invalid ones.

I are Troll Suspicious | :suss:

PIEBALDconsult21-Feb-11 8:21

PIEBALDconsult

21-Feb-11 8:21

I wouldn't; I'd design the system so that that isn't required. The Pending column should be a date column that is set to the time when it will expire if not Purchased. Then, when seeking available tickets, look for any where the Pending field is null or less than the current time and Purchased (another date field) is also null.

Or name them Ordered and Purchased or something, but I wouldn't put them in a single Status column, Status could be calculated from a number of fields, including Shipped.

AhmedMasum22-Feb-11 1:28

AhmedMasum

22-Feb-11 1:28

Thanks for your nice suggestion!!!.
My above case is just an example.
Actually I need something that will do insert/update/delete on a table every week or after a specific period of time.
Is there any type of trigger can do this type of operation??

Cannot use mysql in linux fedora14. Do we have to install it or the bydefault coming is fine.

PIEBALDconsult22-Feb-11 10:37

PIEBALDconsult

22-Feb-11 10:37

Use a Windows Service (for very frequent actions) or a Windows Scheduled Task (for less-frequent actions).

cmaheshwari1619-Feb-11 2:30

cmaheshwari16

19-Feb-11 2:30

Hi

I have not installed mysql on my own, its the default one that is coming with fedora14 at /usr/local/mysql

I am giving you some screenshots, please check if you can find out something.
*********************************************************************************************************************************************************

The first issue is while I login using command
mysql -u root -p
it asks for password I enter, root123
then gives the error
ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: YES)

let me give you the full flow:

I am using fedora 14
_________________________________________________________________________________________________________
in root I fire the below commands:
[starting the mysql]

[root@chandan init.d]# /etc/init.d/mysqld start
Starting mysqld: [ OK ]

now from my local account I try to login to sql,

[chadan@chandan ~]$ mysql -u root -p
Enter password:

[i give password as root123

ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: YES)

But when I login using command

[chadan@chandan ~]$ mysql

Welcome to the MySQL monitor. Commands end with ; or \g.
Your MySQL connection id is 3
Server version: 5.1.51 Source distribution

Copyright (c) 2000, 2010, Oracle and/or its affiliates. All rights reserved.
This software comes with ABSOLUTELY NO WARRANTY. This is free software,
and you are welcome to modify and redistribute it under the GPL v2 license

Type 'help;' or '\h' for help. Type '\c' to clear the current input statement.

mysql>

[here I am able to login to server but when I try to create database then it gives error]

mysql> create database dummy;
ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'dummy'

mysql> show databases;
+--------------------+
| Database |
+--------------------+
| information_schema |
| test |
+--------------------+

**********************************************************************************************************************************

NOW THE SECOND ISSUE WHEN I START THE SERVER IN DIFFERENT WAY.

[root@chandan init.d]# mysqld_safe --skip-grant-tables &

[1] 29006
[root@chandan init.d]# 110219 18:33:25 mysqld_safe Logging to '/var/log/mysqld.log'.
110219 18:33:25 mysqld_safe Starting mysqld daemon with databases from /var/lib/mysql

Now from my account I try to login

[chadan@chandan ~]$ mysql -u root -p

Enter password: fsklfjfljf
here whatever password I give I am able to login

Welcome to the MySQL monitor. Commands end with ; or \g.
Your MySQL connection id is 2
Server version: 5.1.51 Source distribution

Copyright (c) 2000, 2010, Oracle and/or its affiliates. All rights reserved.
This software comes with ABSOLUTELY NO WARRANTY. This is free software,
and you are welcome to modify and redistribute it under the GPL v2 license

Type 'help;' or '\h' for help. Type '\c' to clear the current input statement.

mysql> show databases;
+--------------------+
| Database |
+--------------------+
| information_schema |
| mysql |
| test |
+--------------------+
3 rows in set (0.00 sec)

now when I check mysql database
mysql> use mysql
Reading table information for completion of table and column names
You can turn off this feature to get a quicker startup with -A

Database changed

mysql> show tables;
+---------------------------+
| Tables_in_mysql |
+---------------------------+
| columns_priv |
| db |
| event |
| func |
| general_log |
| help_category |
| help_keyword |
| help_relation |
| help_topic |
| host |
| ndb_binlog_index |
| plugin |
| proc |
| procs_priv |
| servers |
| slow_log |
| tables_priv |
| time_zone |
| time_zone_leap_second |
| time_zone_name |
| time_zone_transition |
| time_zone_transition_type |
| user |
+---------------------------+
23 rows in set (0.01 sec)

mysql> select host,user,password,Insert_priv,update_priv from user;
+---------------------- +------+---------- +-------------+-------------+
| host | user | password | Insert_priv | update_priv |
+---------------------- +------+---------- +-------------+-------------+
| localhost | root | root123 | Y | Y |
| username.corp.org.in | root | root123 | Y | Y |
| 127.0.0.1 | root | root123 | Y | Y |
| localhost | | | N | N |
| username.corp.org.in | | N | N |
+----------------------+------+----------+-------------+-------------+
5 rows in set (0.00 sec)

[here you can see that the password for root user is root123,
now here if i try to create database i am able to do that

mysql> create database dummy;

mysql> show databases;
+--------------------+
| Database |
+--------------------+
| information_schema |
| dummy |
| mysql |
| test |
+--------------------+
4 rows in set (0.00 sec)

I dont know how to solve this also I tried to create another user but it denied

mysql> CREATE USER 'seen' IDENTIFIED BY 'seen123';
ERROR 1290 (HY000): The MySQL server is running with the --skip-grant-tables option so it cannot execute this statement

Re: Cannot use mysql in linux fedora14. Do we have to install it or the bydefault coming is fine.

ScottM121-Feb-11 18:57

ScottM1

21-Feb-11 18:57

Check this[^], looks like it could be that the root password could be incorrect. The MySQL root password could be different to your OS root password.
It could also be that there is a port conflict which is why it works when you start it in a different way.

how to change a color of particular word in the row in ssrs reports

vinu.111119-Feb-11 0:51

vinu.1111

19-Feb-11 0:51

hi..

i've created an report in which i want to change the color of
the particular word i've four words which i want to change the
color
john,steve,mike,and danial..
for these name where ever they appear in the row the color should change
is it possible..

??

Re: how to change a color of particular word in the row in ssrs reports

Wendelius19-Feb-11 1:17

SQL Express Redistribution

19-Feb-11 1:17

Hi,

You can use BackgroundColor-property to change the color and define an expression how the color is set. What comes to the color itself, you can for example resolve the color in the formula or add an extra field to your query which defines the color, like:

SELECT ...
       CASE
          WHEN LOWER(table.NameField) LIKE '%john%' THEN 'Red'
          WHEN LOWER(table.NameField) LIKE '%steve%' THEN 'Blue'
          ...
          ELSE 'White'
       END AS BackgroundColor,
       ...
FROM ...

Now each row should have a color field which you can use in the expression for the BackgroundColor-property. If you want to do this in more elegant way you can create a table for the name/color pairs and use that table for lookups and possibly create a small T-SQL function for the logic.

The need to optimize rises from a bad design.My articles[^]

εїзεїзεїз18-Feb-11 22:00

εїзεїзεїз

18-Feb-11 22:00

I have a Software which is having SQL Server Database, Most of the users don't want to buy SQL Server, So as Microsoft has SQL Express, Can i bundled SQL Express in my Setup CD,
means can i redistribute it ?

SOFTDEV

Luck in life always exists in the form of an abstract class that cannot be instantiated directly and needs to be inherited by hard work and dedication.

Wendelius18-Feb-11 22:15

18-Feb-11 22:15

Yes you can but you have to register for redistrubution rights. See: Register for SQL Server 2008 Express Redistribution Rights[^]

The need to optimize rises from a bad design.My articles[^]

εїзεїзεїз19-Feb-11 18:29

εїзεїзεїз

19-Feb-11 18:29

Thanks

SOFTDEV

Luck in life always exists in the form of an abstract class that cannot be instantiated directly and needs to be inherited by hard work and dedication.

Wendelius20-Feb-11 7:05

20-Feb-11 7:05

No problem Smile | :)

The need to optimize rises from a bad design.My articles[^]

PIEBALDconsult19-Feb-11 5:24

PIEBALDconsult

19-Feb-11 5:24

Just put instructions in the documentation.

Wendelius19-Feb-11 6:58