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Re: Any **FAST** way to convert IEnumerable to IEnumerable<T>?

SledgeHammer019-Sep-14 20:07

9-Sep-14 20:07

I don't know T until runtime, so I would have to do the same thing of making a generic method and calling it through a delegate / invoke / expression tree.

However, the above code you suggested will actually be "much" slower then Cast / CastIterator since you are new'ing up the T array every time. CastIterator is simply:

// System.Linq.Enumerable
private static IEnumerable<TResult> CastIterator<TResult>(IEnumerable source)
{
	foreach (object current in source)
	{
		yield return (TResult)((object)current);
	}
	yield break;
}

Unless of course, the yield keyword is expensive... but from my understanding of how it works internally, it should be MUCH, MUCH faster then the method above since its lazy (and it doesn't new up anything).

I know I'm nitpicking lol, but really trying to squeeze everything out of this block of code.

Re: Any **FAST** way to convert IEnumerable to IEnumerable<T>?

Pete O'Hanlon9-Sep-14 20:46

Pete O'Hanlon

9-Sep-14 20:46

If you don't know the type until runtime, why not make it IEnumerable<dynamic>. When you run this, it will appear that you have an IEnumerable of objects (as you have now), but with the proviso that because it's dynamic, it will honour any method calls you care to make on that object. I haven't tested the performance of this, but that might be worth a try for you.

Re: Any **FAST** way to convert IEnumerable to IEnumerable<T>?

SledgeHammer0110-Sep-14 6:46

SledgeHammer01

10-Sep-14 6:46

Hmm... I need to return a strongly typed IEnumerable. If I return an IEnumerable<dynamic> off of the object[], it compiles, but I get a runtime cast error. I don't have control over the calling code. I'm just the library that serves it up.

Re: Any **FAST** way to convert IEnumerable to IEnumerable<T>?

PIEBALDconsult10-Sep-14 3:14

PIEBALDconsult

10-Sep-14 3:14

SledgeHammer01 wrote:
will actually be "much" slower

That may be, but unless you try it (and/or the Enumerator you show) you'll never know for sure -- you're only acting on hearsay or prejudice. Get a baseline reading, then try something else and get another reading, etc. You're assuming that what you have is "much" faster, but it may not be, you need metrics.

What are you trying to do?
Why are you accepting an object[] of them; can you correct this upstream?
And what actual types are involved? Value types? Structs? Small simple classes? Large complex classes?

SledgeHammer01 wrote:
its lazy

Laziness may not help much unless the consumer doesn't need all the members.

And that cast to object looks redundant.

Re: Any **FAST** way to convert IEnumerable to IEnumerable<T>?

SledgeHammer0110-Sep-14 6:42

SledgeHammer01

10-Sep-14 6:42

PIEBALDconsult wrote:
That may be, but unless you try it (and/or the Enumerator you show) you'll never
know for sure -- you're only acting on hearsay or prejudice. Get a baseline
reading, then try something else and get another reading, etc. You're assuming
that what you have is "much" faster, but it may not be, you need metrics.

What are you trying to do?
Why are you accepting an object[] of
them; can you correct this upstream?
And what actual types are involved?
Value types? Structs? Small simple classes? Large complex classes?

... well, for the sake of the thread, I did... its not "much, much slower" as I thought it would be... but it is quite a bit slower (about 15%). 3900ms vs 4500ms Frown | :(

What I'm trying to do is given an array of some unknown (at compile time) object (which is why I store them as object[]), I need to convert said object[] into an IEnumerable T where T is known at compile time by the caller of my class.

I could potentially store a T[], but unfortunately, my class has non-T overloads. So its kind of like I need to support:

T GetTheObjects<T>();
IEnumerable<SomeClass> enum = GetTheObjects<SomeClass>();

object GetTheObjects(Type type);
IEnumerable<SomeClass> enum = (IEnumerable<SomeClass>)GetTheObjects(typeof(SomeClass));

If I only had to support the T overloads, I could avoid boxing / unboxing...

PIEBALDconsult wrote:
And that cast to object looks redundant.

Agreed. That's how Reflector shows it. I tried c&p'ing that static method into my dll and removing the extra cast, but it didn't affect performance.

add row to datagridview by checking child node check box of treeview

Member 110597999-Sep-14 15:39

Member 11059799

9-Sep-14 15:39

I'm new to C# and am working on first project.

I have a WINFORM that displays a treenode and a datagridview. I want selected items from the treenode to go to the datagridview. If I select the parent node of treenode all children go to datagridview but if I just expand the parent and select one of the children, nothing goes to datagrid. (selection of a treenode fires a method to get attributes of the item from sql table and it is the attributes that go to the grid + node value)

When parent is selected 'if (e.Node.Nodes.Count > 0)' is true. When parent isn't selected but child is 'if (e.Node.Nodes.Count > 0)' is false.

So my question is what code do I need to find child nodes that are checked/unchecked?

Once I get correct code to find child node check, what code moves it to datagrid or delete from datagrid if child is unchecked?

private void getChildNodesToGrid()
 {
     // get all child nodes add to dataGridView
     DataTable dt = getFieldsTable();
     dgvColumns.DataSource = dt;
     getAttributeSIDs();
 }

private void tvFileMan_AfterCheck(object sender, TreeViewEventArgs e)
    {
        getFileAndColumns();
        if (e.Node.Nodes.Count > 0)
        {
           this.CheckAllChildNodes(e.Node, e.Node.Checked);
            // Checked a file so get fields and check all fields except subfiles.
            // Use this event handler to process actions from check box click
            e.Node.Expand();
            foreach (TreeNode tn in e.Node.Nodes)
            {
                if (tn.Nodes.Count.Equals(0))
                    tn.Checked = e.Node.Checked;
            }
            getChildNodesToGrid();
 }

Re: add row to datagridview by checking child node check box of treeview

Member 1105979911-Sep-14 7:55

Member 11059799

11-Sep-14 7:55

RESOLVED:

Added an 'else' to the AfterCheck so it simply calls getChildNodesToGrid()

I then updated private DataTable getFieldsTable() to add a counter and condition 'if (fileNode.Nodes[cnt].Checked)'.
Don't know if this is proper programming but seems to work.

private void tvFileMan_AfterCheck(object sender, TreeViewEventArgs e)
 {
     getFileAndColumns();
     if (e.Node.Nodes.Count > 0)
     {
        //this.CheckAllChildNodes(e.Node, e.Node.Checked);
         // Checked a file so get fields and check all fields except subfiles.
         e.Node.Expand();
         foreach (TreeNode tn in e.Node.Nodes)
         {
             if (tn.Nodes.Count.Equals(0))
                 tn.Checked = e.Node.Checked;
         }
         getChildNodesToGrid();
     }
     else
     {
         e.Node.Expand();

             //if (tn.Nodes.Count.Equals(0))
             if (e.Node.Checked)
             {
                 //tn.Checked = e.Node.Checked;
                 getChildNodesToGrid();
             }

     }

private DataTable getFieldsTable()
 {
     //original
     DataTable dt = new DataTable();
     dt.Columns.Add("ColumnName");
     dt.Columns.Add("FMFieldName");
     dt.Columns.Add("FMFieldNumber");
     dt.Columns.Add("FMFileNumber");
     dt.Columns.Add("FMFieldType");
     dt.Columns.Add("ResolvedValue");
     dt.Columns.Add("PointsToFileNumber");
     TreeNode fileNode = tvFileMan.SelectedNode;
     int cnt = 0;
     foreach (TreeNode tn in fileNode.Nodes)
     {
         if (tn.Nodes.Count == 0)
         {
             if (fileNode.Nodes[cnt].Checked)
             {
              DataRow dr = dt.NewRow();

             dr["FMFieldName"] = tn.Text.Substring(tn.Text.IndexOf("  - ") + 4);
             dr["FMFieldNumber"] = tn.Tag.ToString();
             dr["FMFileNumber"] = tn.Parent.Tag.ToString();
             dr["ColumnName"] = suggestName(tn.Text.Substring(tn.Text.IndexOf("  - ") + 4));
             //added by TEA 9/3/14 to get PointsToFileNumber in DataGrid
             if (dr["PointsToFileNumber"].ToString().Length > 0)
             {
                 dr["ColumnName"] = suggestName(tn.Text.Substring(tn.Text.IndexOf("  - ") + 4) + "txt");
             }
             dt.Rows.Add(dr);
             }
             cnt++;
         }
     }
     return dt;

 }
private void getFileAndColumns()
 {
     label4.Visible = false;
     label5.Visible = false;
     btAllFields.Visible = false;
     cbComputed.Checked = false;
     TreeNode node = tvFileMan.SelectedNode;
     if (node == null) return;
     // Is it a File or Field?
     if (node.Index == 0) return;

     if (node.Nodes.Count > 0)
     {
         // FileManFile selected.
         // Check AttributeMap for this file. If found, fill in textboxes with that info.

         // Otherwise, suggest a name for the table.
         tbFileNumber.Text = node.Tag.ToString();
         tbFileName.Text = node.Text.Substring(node.Text.IndexOf("  - ") + 4);
         tbTableName.Text = "xxxx." + (suggestName(tbFileName.Text) + "F" + tbFileNumber.Text.Replace('.', 'x'));
         label4.Text = "To select all fields push button to the right. \nOtherwise double-click fields to add them one at a time.";
         label4.Visible = true;
         btAllFields.Visible = true;
         dgvColumns.DataSource = null;
         dgvPKIENS.DataSource = getPKIENSTable();
         getPKIENSIDs();
     }
     else
     {
         // FileMan Field selected.
     }


 }

Chat Application

Kevin Marois9-Sep-14 11:23

Kevin Marois

9-Sep-14 11:23

I want to create a simple chat app. I would like to host it on my server and allow one-to-many people to chat.

I'd like to do it myself as a learning experience. Can anyone point me in the right direction?

Thank you

If it's not broken, fix it until it is