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For Windows NT to XP, you'd have to replace the GINA.DLL. You can read more about it here[^].
For Vista and 7, the security system is now extensible. You have to create a new Credential Provider. Read more on this here[^]
You cannot replace GINA with a .NET application or form. I'm not too sure you can use C# for a Credential Provider either.
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Dave Kreskowiak wrote: You cannot replace GINA with a .NET application or form. I'm not too sure you can use C# for a Credential Provider either
Read this and am a little confused. I thought Vista was build in .Net and I assume Windows 7 as well, so why would you not be able to use .Net for this? (In addition "Credential Provider" sounds very .Net like  )
Just curious.
V.
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V. wrote: I thought Vista was build in .Net and I assume Windows 7 as well
So far as I am aware there are no parts of any M$ operating system that are written in .Net. Both Vista and Wevenjs install the .net libraries but they are not written using it.
Visual Studio 2010 uses WPF for its Editor, maybe that is what you are thinking of?
Henry Minute
Do not read medical books! You could die of a misprint. - Mark Twain
Girl: (staring) "Why do you need an icy cucumber?"
“I want to report a fraud. The government is lying to us all.”
Why do programmers often confuse Halloween and Christmas?
Because 31 Oct = 25 Dec.
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Not really, but I'm probably dreaming in that case, thx.
V.
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V. wrote: I thought Vista was build in .Net and I assume Windows 7 as well
No, they're not. I would have cost Microsoft BILLIONS of dollars to rewrite the entire Windows kernel in .NET.
V. wrote: (In addition "Credential Provider" sounds very .Net like )
It sounds very modular and better designed, not .NET'ish.
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If you're only letting them choose between images in your resources, yeah, you can save the name of the selected resource in the app.config file.
.45 ACP - because shooting twice is just silly
-----
"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997
-----
"The staggering layers of obscenity in your statement make it a work of art on so many levels." - J. Jystad, 2001
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Well, when you create a shortcut, and then select an icon on for the shortcut. I've never seen an application itself that let you do it.
.45 ACP - because shooting twice is just silly
-----
"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997
-----
"The staggering layers of obscenity in your statement make it a work of art on so many levels." - J. Jystad, 2001
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Why not use a small local DB to store your icons? Like SQLLite, sql compact, or *.mdb(s).
Or even a custom binary file(Serializable)?
Just an irritated, ranting son of ... an IT guy.
At your trolling services
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Hello,
Anyone know some class that give you the range between two ip?
example:
start 216.1.1.2
end 216.1.1.5
the class print on the screen:
216.1.1.2
216.1.1.3
216.1.1.4
216.1.1.5
OR
start 216.1.1.254
end 216.1.2.2
216.1.1.254
216.1.1.255
216.1.2.1
216.1.2.2
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What I posted wouldn't work. Look at Luc's answer. that's the one.
.45 ACP - because shooting twice is just silly----- "Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997----- "The staggering layers of obscenity in your statement make it a work of art on so many levels." - J. Jystad, 2001
modified on Thursday, June 3, 2010 2:08 PM
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I personally don't know of such a class.
But it's not that hard to create one. Logic is quite simple.
First check the given values(IPs) then if OK
odrer them then split by "." check and do the math.
Just an irritated, ranting son of ... an IT guy.
At your trolling services
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you can do it with simple arithmetic and a couple of loops.
or you can rely on some classes, maybe you'll like this approach:
IPAddress from=IPAddress.Parse("216.1.1.254");
IPAddress to=IPAddress.Parse("216.1.3.25");
byte[] bFrom=from.GetAddressBytes();
Array.Reverse(bFrom);
int iFrom=BitConverter.ToInt32(bFrom, 0);
byte[] bTo=to.GetAddressBytes();
Array.Reverse(bTo);
int iTo=BitConverter.ToInt32(bTo, 0);
for (int ip=iFrom; ip<=iTo; ip++) {
byte[] bIP=BitConverter.GetBytes(ip);
if (bIP[0]!=0 && bIP[1]!=0 && bIP[2]!=0 && bIP[3]!=0) {
Array.Reverse(bIP);
IPAddress ipa=new IPAddress(bIP);
log("IPA="+ipa.ToString());
}
}
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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You should post this as a tip/trick.
.45 ACP - because shooting twice is just silly
-----
"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997
-----
"The staggering layers of obscenity in your statement make it a work of art on so many levels." - J. Jystad, 2001
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I'll consider that.
My problem then is I could publish hundreds of these, not sure I should.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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I'm doing it. When I create some cool code that doesn't call for an article, I publish a tip/trick.
.45 ACP - because shooting twice is just silly
-----
"Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997
-----
"The staggering layers of obscenity in your statement make it a work of art on so many levels." - J. Jystad, 2001
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Does anybody knows a way to get integer values from the slider control, instead of double-precision values?
My slider control is from 0 to 255 and I want use it as way of getting an integer value, to be able to send it throw the serial port to the arduino duemilanove.
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Can't you just cast the double to an int?
Or better yet, Round it to the nearest whole number then cast it to an int?
double someVal = 0.5782;
int intVal = (int)Math.Round(someVal);
My current favourite quote is: Punch them in the face, see what happens!
-SK Genius
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In my books TrackBar.Value[^] is an integer.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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I'm using C# but in WPF Application (XAML)
the snippet using Math.Round works perfectly
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you should have said so.
it is the (int) cast that solves it, rounding/ceiling/flooring is up to you.
Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]
I only read formatted code with indentation, so please use PRE tags for code snippets.
I'm not participating in frackin' Q&A, so if you want my opinion, ask away in a real forum (or on my profile page).
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It doesn't matter to make a (int) cast, since the value of slider is to be stored in a label.
In XAML, label.Content is of type 'object'
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I'm fine for now. I have no more questions.
Thanks for everyone!
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