C# Discussion Boards - CodeProject

Re: Comunication between form an appl. and a service.

8-Dec-08 9:16

daavena wrote:
Is it possible?

Yes.

daavena wrote:
If yes, could you give me a hint?

It can be done via Inter-Process communication. Possible solutions are:

Pipes and .Net Remoting/WCF

Giorgi Dalakishvili

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daavena8-Dec-08 9:28

daavena

8-Dec-08 9:28

Thank you. I will check it.

Re: Comunication between form an appl. and a service.

Giorgi Dalakishvili8-Dec-08 19:19

Re: Comunication between form an appl. and a service.

8-Dec-08 19:19

Glad to help you Smile | :)

Giorgi Dalakishvili

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PIEBALDconsult8-Dec-08 12:45

PIEBALDconsult

8-Dec-08 12:45

I have the Service write an XML file, then many users of the application can read the file.

You could also use a database.

Embedding Excel in Windows Forms

San248-Dec-08 8:11

San24

8-Dec-08 8:11

I`m trying to embed Excel in Windows forms. I`m following the example in
http://www.codeproject.com/KB/office/Embedding_Excel.aspx

Everything seems to work fine, but I want the Tool Bar for Excel [Very Important] . I can`t seem to enable the Toolbar in windows forms. Can anyone please go through the code in demo and see what needs to be done. I`m completely lost and frustrated. Also, I want to save the excel file, what is the way to go about that, since its already open.

Giorgi Dalakishvili8-Dec-08 8:27

8-Dec-08 8:27

Try this approach: Window Tabifier[^]

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San248-Dec-08 9:10

San24

8-Dec-08 9:10

Cool App! Not what I`m looking for. I need to use windows forms and excel embedded in it.

Giorgi Dalakishvili8-Dec-08 9:15

8-Dec-08 9:15

sharat567 wrote:
I need to use windows forms and excel embedded in it.

Why not just host it?

San2410-Dec-08 5:21

San24

10-Dec-08 5:21

Can you please elaborate. What exactly do you mean by hosting? Like in a web browser? I already do that.

Giorgi Dalakishvili10-Dec-08 6:23

The "Create GUID" tool is disable in my Visual Studio 2005 IDE.

10-Dec-08 6:23

No, like it is done by Window Tabifier. Start Excel and set parent of excel form to your form.

Giorgi Dalakishvili

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hdv2128-Dec-08 7:35

hdv212

8-Dec-08 7:35

Hi i don't know why the "Create GUID" tool is disable in my Visual Studio 2005 IDE.
also i could not found guidgen.exe in this path :
D:\Program Files\Microsoft Visual Studio 8\Common7\Tools

Can anybody help me about this issue ?
i'm using Microsoft Vidual Studio 2005 Professional Edition

Thanks

Re: The "Create GUID" tool is disable in my Visual Studio 2005 IDE.

Colin Angus Mackay8-Dec-08 8:03

Colin Angus Mackay

8-Dec-08 8:03

Guid.NewGuid()[^]

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Re: The "Create GUID" tool is disable in my Visual Studio 2005 IDE.

Mark Salsbery8-Dec-08 8:52

Mark Salsbery

8-Dec-08 8:52

hdv212 wrote:
also i could not found guidgen.exe in this path :
D:\Program Files\Microsoft Visual Studio 8\Common7\Tools

I think guidgen.exe is installed as part of the SDK.

Is there a copy here? D:\Program Files\Microsoft SDKs\Windows\...<version>...\bin

Mark Salsbery
Microsoft MVP - Visual C++
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Re: The "Create GUID" tool is disable in my Visual Studio 2005 IDE.

Nissim Salomon8-Dec-08 9:00

Nissim Salomon

8-Dec-08 9:00

Hi
Download it form the following link
http://www.microsoft.com/downloads/details.aspx?familyid=94551f58-484f-4a8c-bb39-adb270833afc&displaylang=en[^]

Re: The "Create GUID" tool is disable in my Visual Studio 2005 IDE.

hdv2128-Dec-08 9:08

hdv212

8-Dec-08 9:08

Thanks nissims

method inheretance

Deresen8-Dec-08 6:29

8-Dec-08 6:29

Hello everyone,

I'm building my own library. But I'm kind of stuck and it is really tough to explain, but I will try:

I have a class, let's call this X. X has an interface and a base class. X also inherets another class (called Y).

Now I call some base functions and give X as a parameter.
But I would like to know if it is possible in another baseclass?

To sketch it up in code, it looks like this now:

class X : Y, InterfaceX
{
   public X()
   {
   }

   bool function1(String txt)
   {
      return base.function1(this, txt);
   }
}

class Y
{
   bool function1(InterfaceX x, String txt)
   {
      //do something
      return true/false;
   }
}

And what I would like to have is something like this:

class X : Y (& Z), InterfaceX
{
   public X()
   {
   }
}

class Y
{
   bool function1(InterfaceX x, String txt)
   {
      //do something
      return true/false;
   }
}

class Z
{

   bool function1(String txt)
   {
      return base.function1(this.getParent(), txt);
   }
}

Is this possible, and if it is, how can I implement this?

Thank you very much.

Alan Balkany8-Dec-08 8:11

Alan Balkany

8-Dec-08 8:11

Class X can't inherit from Y and Z because C# only supports single inheritance (unfortunately). You could have X inherit from Y, and Y inherit from Z. Or you could have X implement multiple interfaces.

Also you need the keyword "virtual" on the virtual methods in your base classes, and the keyword "override" on your overridden methods in the derived classes.

Another possibility is the Decorator design pattern, which lets you define inheritance (single or multiple) at runtime.

Deresen8-Dec-08 8:25

8-Dec-08 8:25

Thank you.

But the problem I have is that if I want to add a function to my Interface class and it is as simple as calling the base function with as parameter itself, shouldn't it be possible to do that in some kind of global class. Something like this:

class Main
{
   public Main()
   {
      X x = new X();
      x.function1("myText"); -> false
      X2 x2 = new X2();
      x2.function1("myText"); -> true
   }
}

interface InterfaceX
{
    int number { get; };
    bool function1(String txt);
}

class X :  Z, InterfaceX
{
    public int number
    {
       get { return 5;}
    }
   public X(){}
}
class X2 : Z, InterfaceX
{
    public int number
    {
       get { return 2;}
    }
    public X2() {}
}

class Z : Y, 
{
   public bool function1(String txt)
   {
      return base.function2(this.getParent(), txt);
   }
}

class Y
{
   public bool function2(InterfaceX x, String txt)
   {
      if(x.number < 3)
         return true;
      else
         return false;
   }
}

It's all about the this.getParent(), this doesn't work, but how can I get this working?

Alan Balkany8-Dec-08 8:32

Alan Balkany

8-Dec-08 8:32

I'm not sure what you're trying to do, but this.getParent () will only work if:

1. Class Z (or an ancestor of Z) defines a getParent () method, and
2. This getParent () method returns InterfaceX (or a descendant of InterfaceX).

Deresen8-Dec-08 9:14

8-Dec-08 9:14

With the this.getParent() I would like to get the 'parent' of Z.

So if I make an X : Z I would like to get X.
And if I make an BlahBlah : Z I would like to get BlahBlah.

I'm trying to get some work of my back.
In stead of implementing all the functions (of the interface) inside of every class, I would like to make a base class which implements these functions.

Alan Balkany8-Dec-08 9:40

Alan Balkany

8-Dec-08 9:40

If you put all the interface functions in a base class, they will automatically be available to all the derived classes.

If this doesn't work for you, you can define a class that implements all the interface functions, and define an instance of this in any class that that implements the interface. Then for each interface function, forward the call to this instance. This avoids having to re-implement the whole functions in each class that implements the interface.

For example:

interface InterfaceX
{
// Lots of interface function definitions...
}

class ImplementationOfInterfaceX : InterfaceX
{
// Implementation of each function...
}

class X : InterfaceX
{
ImplementationOfInterfaceX implX;

public int func1 (int par)
{
return implX.func1 (par); // I.e., a forwarded call instead of a 100-line function.
}

public float func2 (float par)
{
return implX.func2 (par);
}

...
}

Of course this would be much easier if C# allowed multiple inheritance. I'm hoping they will in a future version. It makes some things very easy. It seems to me they left it out because it allows complexity and confusion for some extreme contrived cases that no one in their right mind would do. Not a good justification for leaving it out (in my biased opinion).

Ben Fair8-Dec-08 10:34

Ben Fair

8-Dec-08 10:34

The crux of the problem is that you want class Z to pass an item into a function that accepts an InterfaceX item, but class Z is not necessarily an InterfaceX. So, the only way to do it as-is is to do this messy kind of check. Ideally, you'd have the call to function2 be in a class that is an InterfaceX. Passing a Z that is not an InterfaceX won't work, so you'll have figure out how you want to handle that situation. Here's a class Z that should work:

class Z : Y
{
    public bool function1(String txt)
    {
        if(this is InterfaceX)
            return base.function2((InterfaceX)this, txt);
        else
            return false; // maybe throw exception?
    }
}

Keep It Simple Stupid! (KISS)

Deresen8-Dec-08 10:51