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hi all,
how can i detect if a (any) window is being dragged? Obviously with PInvoke, but I cannot find any C# examples. If anyone has any or could explain, could you please do so?
Thanks,
Maurice
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Thanks for the reply,
I need to determine out of process windows being dragged and I need to know which window it is. i.e., get a handle to it.
Thanks,
Maurice
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I am doing a project, which had a requirement of sending an sms message to a mobile from the c#.net.How can i do this.If i need to add any .dll files how can i add those file.
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Can you use COM port and AT command
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The client who install my software connects a bluetooth device. When some event occurs then this software should send an sms to the adjacent mobile through the bluetooth.For doing this, what should i do.
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i want to print a windows form by using a printpreview control in vs 2005.I used but i am not able to get it. please lemme know the possible solution. I had to print the full windows form as it was designed.
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Can you see this note[^]
or this note[^]
modified on Friday, December 5, 2008 9:56 AM
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Hello Guys,
I have to connect to Oracle and SQL Server in my database projects. So I have to write the code to connect and query these tables...
I am looking for a class/assembly that provides connectivity/query facility for 2 databases (oracle and SQL Server).
I should be able to pass connection parameters from my application.
Then use the methods to query the database through the class/dll.
I have seen one @ DB Connectivity Provider[^]
If any one known of one please let know.
Thanks in advance
o O º(`'·.,(`'·., ☆,.·''),.·'')º O o°
»·'"`»* *☆ t4ure4n ☆* *«·'"`«
°o O º(,.·''(,.·'' ☆`'·.,)`'·.,)º O o°
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You can use Data Access Application Block from Enterprise Library: Link[^]
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A little bit different approach: You can connect to Oracle from SQL Server and vice versa. After that you can for example define a view that actually hides where the data is coming from, so basically your application can connect to a single database and still get data from multiple databases but the application does not see it. In some cases this is easier to implement.
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Hi,
I am developing a client/server socket program. From server number of time the Socket.send() is calling. I want to identify each message for different functions in the client side.
Eg:
Chat application:
When first connect a send message is send with welcome message. In client side it is displayed in a label. Next time the another message is send, that message should displayed a list box, Next time in text box…. There is no specific order for sending.
How can i identify the type of message
Regards,
Ypki
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design your messaging spec such that each message has a type identifier in it. XML is good for this kind of stuff.
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Better: use SOAP[^].
Instead of writing from scratch at the socket level, take into account using WCF[^]: it takes care of all the type resolution and serialization for you.
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Wrap the message you are sending e.g.
when sending a connection message: "Connection|YourMessage"
for message to be added to listbox: "ListBox|YourMessage"
for message to be added to textbox: "TextBox|YourMessage", etc.
You can wrap your message with multiple key words to distinguish
e.g. "KeyWord1|KeyWord2|KeyWord3|.....|YourMessage"
Hope this helps,
Prateek
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i've to find some records that matches with a given date once the search button is clicked. by default the datetime picker shows the current date. but i want to show all records when the date is not set by the user specifically,(and when Passportno and name fields are blank(defaut all fields are balnk))
1.how can i set the datetime picker value to balnk
2.is there better solution for this
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Dear Team,
I have a requirement that
i am displaying the records in the datagrid which will are fetched from the database , which has 3 columns
1. id
2. the blob data
3. the file name ( this can be of any format ) like .txt,.pdf etc.
so when i click on the perticular file name ( which is just an name ) the file should get opened in its corresponding format by reading the data from its perticular blob column.
i am developing this in windows application.
expecting an responce from your side
Thanx and regards
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OK, that describes your app . Now, may I ask you *what exactly* you need help with?
It is a crappy thing, but it's life -^ Carlo Pallini
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actually i want to open the file which is stored in the database in blob format.
i was able to save that perticular file into any of folders in the system
sample code is here.
string ATTACHEMENTID1 = "";
private void DgToolsList_CellContentClick(object sender, DataGridViewCellEventArgs e)
{
ATTACHEMENTID1 = DgToolsList.Rows[e.RowIndex].Cells[0].Value.ToString();
string FileName = DgToolsList.Rows[e.RowIndex].Cells[1].Value.ToString();
if (e.ColumnIndex == 1)
{
saveFileDialog1.Title = "Open File";
saveFileDialog1.Filter = "All Files|*.*|JPEG Images|*.jpg|GIF Images|*.gif|BITMAPS|*.bmp";
saveFileDialog1.FileName = FileName.ToString();
saveFileDialog1.ShowDialog();
//txtAttachment.Text = openFileDialog1.FileName;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
byte[] buffer = GetFileFromDB(ATTACHEMENTID1);
int ArraySize = new int();
ArraySize = buffer.GetUpperBound(0);
FileStream fs1 = new FileStream(saveFileDialog1.FileName, FileMode.OpenOrCreate, FileAccess.Write);
fs1.Write(buffer, 0, ArraySize);
fs1.Close();
MessageBox.Show("File Save to " + saveFileDialog1.FileName);
}
}
}
GetFileFromDB(string atachmenet) is the method to read the blog data from the database
but i want to open the file directly istead of saving it and open it again.
please provide me with some solution for it .
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And what have you tried? Post some code with specific problems if you want help.
shaik abdul gani wrote: expecting an responce from your side
And do not demand things, its rude.
Bob
Ashfield Consultants Ltd
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sorry for that.
actually i want to open the file which is stored in the database in blob format.
i was able to save that perticular file into any of folders in the system
sample code is here.
string ATTACHEMENTID1 = "";
private void DgToolsList_CellContentClick(object sender, DataGridViewCellEventArgs e)
{
ATTACHEMENTID1 = DgToolsList.Rows[e.RowIndex].Cells[0].Value.ToString();
string FileName = DgToolsList.Rows[e.RowIndex].Cells[1].Value.ToString();
if (e.ColumnIndex == 1)
{
saveFileDialog1.Title = "Open File";
saveFileDialog1.Filter = "All Files|*.*|JPEG Images|*.jpg|GIF Images|*.gif|BITMAPS|*.bmp";
saveFileDialog1.FileName = FileName.ToString();
saveFileDialog1.ShowDialog();
//txtAttachment.Text = openFileDialog1.FileName;
if (saveFileDialog1.ShowDialog() == DialogResult.OK)
{
byte[] buffer = GetFileFromDB(ATTACHEMENTID1);
int ArraySize = new int();
ArraySize = buffer.GetUpperBound(0);
FileStream fs1 = new FileStream(saveFileDialog1.FileName, FileMode.OpenOrCreate, FileAccess.Write);
fs1.Write(buffer, 0, ArraySize);
fs1.Close();
MessageBox.Show("File Save to " + saveFileDialog1.FileName);
}
}
}
GetFileFromDB(string atachmenet) is the method to read the blog data from the database
but i want to open the file directly istead of saving it and open it again.
please provide me with some solution for it .
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Sorry, you are not making sense. Looking at your code, you read the data from the database and save it to a file. Simple enough. What doesn't make sense is
shaik abdul gani wrote: but i want to open the file directly istead of saving it and open it again.
So use the byte[] buffer that you populated from the database. Whats the problem?
Bob
Ashfield Consultants Ltd
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