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sit your kid down and talk with them, or just supervise them online, well atleast thats what parenting involved back in my day.
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Sean Mulkerrin wrote: sit your kid down and talk with them, or just supervise them online, well atleast thats what parenting involved back in my day.
Been there, done that, about 10 years ago.
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Then just go out and buy $@#()*@$% BigBrotherWare and be done with it. Just saying "I;m on the side of angels isn't going to cut it for actually being told how to do anything like this"
Today's lesson is brought to you by the word "niggardly". Remember kids, don't attribute to racism what can be explained by Scandinavian language roots.
-- Robert Royall
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elie aintabi wrote: about to get trolled but
Unless you are a newsgroup, you can't get trolled. You probably mean flamed.
What possible use would you have of a key logger? You will pr0b4bly n07 und3r574nd w4t ur |<1dz r 74|_|<1n b0u7 4nyw4y...
Despite everything, the person most likely to be fooling you next is yourself.
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I have three sons, two of whom are in High School, so I feel your pain: the Internet is not only an attractive nuisance, but probably the world's biggest dirty book. After several incidents of "inappropriate usage", I finally found IPCop and installed it on an old PC. It was easy to install and configure, and allows me to review all Internet traffic or block sites as needed; with a little more work, I figured out how to have IPCop send me e-mail notifications when certain "dirty words" were detected. I would recommend it as a possible solution to your dilemma.
Cheers!
Humble Programmer
,,,^..^,,,
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Amazing I'm going to take a peek into that right now. It's not so much the sites he visits as much as the conversations he has. But the second you said e-mail notification that is a feature I would have definitely liked.
Thanks very much.
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I have an xml file which I would like to read and pull out it's contents as follows:
xml sample:
<persons>
<person></person>
<person>
<value>x</value>
<value>y</value>
<value>z</value>
</person>
<person>
<value>w</value>
<value>u</value>
</person>
...
...
...
</persons>
So as I read through the above xml, I would like to go through them one record at a time so I would like to see:
record No xml
1 <person></person>
2 <person>
<value>x</value>
<value>y</value>
<value>z</value>
</person>
3 <person>
<value>w</value>
<value>u</value>
</person>
How can I code this please?
Thanks
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Try the code below:
string xmlFilePath = @"C:\Persons.xml";
System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
doc.Load(xmlFilePath);
System.Xml.XmlNode pNode = doc.SelectSingleNode("persons");
for (int i = 0; i < pNode.ChildNodes.Count; i++)
{
System.Xml.XmlNode personNode = pNode.ChildNodes[i];
for (int x = 0; x < personNode.ChildNodes.Count; x++)
{
string value = personNode.ChildNodes[x].InnerText;
}
}
Hope this helps.
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Thank you
modified on Tuesday, October 14, 2008 10:20 AM
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Look at the member methods of XmlDocument, read the documentation.
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Hi ,
I am developing an application in C# to control remote systems in local network.I need to capture the screen of a remote machine,is that possible??
Please help...
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Yes, you can , arround 4 years ago i have done a same application on VB.Net. What we have done, just trap the Printscreen button using interupt and save the image on disk and read the image as networkstream and display it you applicaiton picture box by saving the receiving stream as image.
Hope this will helps you to startup 
cheers,
Abhijit
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http://www.codeproject.com/KB/IP/ScreenCast_With_Control.aspx
Probably seen it already or even solved it by now.
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I am developing software in C#. I generate reports in datagridview and also generate report directly in printdocument control.
My problem is, when I want to print only some pages, i.e. page from 2 to 3, i am not able to print the same, i give code as under
In print click event
printDialog1.AllowSomePages = true;
printDialog1.ShowDialog();
printDocument1.PrinterSettings.PrintRange = printDialog1.PrinterSettings.PrintRange;
printDocument1.PrinterSettings.FromPage = printDialog1.PrinterSettings.FromPage;
printDocument1.PrinterSettings.ToPage = printDialog1.PrinterSettings.ToPage;
printDocument1.Print();
If there are 6 pages in the report all the 6 pages are printed not page from 2 to 3. Why? Can anyone face this problem. Is there any solutions?
Suleh.
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Hi All,
I'm still new to development, I'm trying to link a text box to an ID in a table. This text box will be an identfier and it will insert the text to the table when it has linked to the id.
Is this possible or should i look into something else.
Regards,
Ndeza
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Hi Ndeza,
sure, this is possible (You could write a whole rocket steering application in C# if you like, am I right?) .
But please be sure to post more information about the issue. What kind of table, what kind of Id? What do you want to achieve exactly.
Regards
Sebastian
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Hi Sebastian,
I've got a Foreign Exchange app that I'm trying to create, and the table is stored in the database. This table has an ID where it links to the different currencies. Now what I want to do is I want to link the text boxes of all the different currencies to the currencies in the table. I haven't done much with this but I've created a stored proc that updates, and inserts.
cmd.Parameters.Add("@PlayerTypeID", SqlDbType.Int, 20);
cmd.Parameters["@PlayerTypeID"].Value = txt0.Text; -- this is what I’ve been trying and it’s not working out.
cmd.Parameters.Add("@DateYear", SqlDbType.Int, 40);
cmd.Parameters["@DateYear"].Value = cbmYear.SelectedItem;
cmd.Parameters.Add("@DateMonth", SqlDbType.Int, 4);
cmd.Parameters["@DateMonth"].Value = cmbMonth.SelectedItem;
cmd.Parameters.Add("@FXR", SqlDbType.Float);
cmd.Parameters["@FXR"].Value = txt0.Text;
cmd.Parameters["@FXR"].Value = txt3.Text;
cmd.Parameters["@FXR"].Value = txt5.Text;
cmd.Parameters["@FXR"].Value = txt6.Text;
cmd.Parameters["@FXR"].Value = txt9.Text;
cmd.Parameters["@FXR"].Value = txt55.Text;
cmd.Parameters["@FXR"].Value = txt61.Text;
cmd.Parameters["@FXR"].Value = txt76.Text;
cmd.Parameters["@FXR"].Value = txt77.Text;
cmd.Parameters["@FXR"].Value = txt81.Text;
But now my problem is that I just cant get the PlayerTypeID being the ID link to the text box. Please can you assist with an example of some kind.
Thank you,
Ndeza
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Hmm...
still not sure if I understand everything. All you do here is to put the text of the txt0-Textbox into the PlayerTypeID (same for the @FXR values). So you write all the values stored in your textboxes into the database... If you change sth. within the database it will not automatically change in your app...
Could you please explain in more detail what you mean by "link the textboxes ... in the table". What means "link"?
Regards,
Sebastian
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Ok,
For each currency there is an ID, what I'm trying to do is make the Text box that I will also enter the new exchange rate into, the text box will correspond with the ID(PlayerTypeID). Basically, I’m trying to make the text box be an Id identifier and also an input text that will update the @FXR.
What I mean by link; I want the text box to identify the id in which it will enter the new exchange rate.
Thank you,
Ndeza
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Alright,
now i'm getting close to the point. I thin k you have two options here:
-------------
First one:
Use a dictionary to store the textbox and the playerid. Looks somethind like this:
Dictionary<textbox,> dictBoxes = new Dictionary<textbox,>();
dictBoxes.Add(txt0, );
In your storing method you can then access the value:
cmd.Parameters["@PlayerTypeID"].Value = dictBoxes[txt0];
---------------
Second option is to inherit the textbox and add another property:
public class MyPlayerIDTextbox:Textbox {
private string m_sPlayerID;
public string PlayerID {
get { return this.m_sPlayerID;}
set { this.m_sPlayerID = value;}
}
}
Than you have to set the playerid of your textbox once:
MyPlayerIDTextbox txt0 = new MyPlayerIDTextbox();
txt0.PlayerID =
And the storing method will look like this:
cmd.Parameters["@PlayerTypeID"].Value = txt0.PlayerID;
Hope this helps you a bit.
Regards
Sebastian
P.S: I would prefer the dictionary method, it is simplier I think. Or any other suggestions?
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Heya Sebastian,
Wow you were right the Dictionary works perfect, but the only thing is that I have allot of exchange rates to update and insert and it only inserts for one where as I'm trying to insert in one go. Please can you assist if you can?
Oh the second option is quite complicated as you will need to convert a string to an INT32.
But I prefer the First Option much easier and more understandable.
Regards,
Ndeza
/// create the dictionary
Dictionary<TextBox, int> dictBoxes = new Dictionary<TextBox, int>();
/// than put the id in it
dictBoxes.Add(txt0, 0);
dictBoxes.Add(txt3, 3);
dictBoxes.Add(txt5, 5);
dictBoxes.Add(txt55, 55);
dictBoxes.Add(txt6, 6);
dictBoxes.Add(txt61, 61);
dictBoxes.Add(txt76, 76);
dictBoxes.Add(txt77, 77);
dictBoxes.Add(txt81, 81);
dictBoxes.Add(txt9, 9);
//All the parameters that will be added to the database
//also all the from the app
cmd.Parameters.Add("@PlayerTypeID", SqlDbType.Int, 20);
cmd.Parameters.Add("@DateYear", SqlDbType.Int, 40);
cmd.Parameters.Add("@DateMonth", SqlDbType.Int, 4);
cmd.Parameters.Add("@FXR", SqlDbType.Float);
//Assigning the Values to the parameters
cmd.Parameters["@PlayerTypeID"].Value = txt0.Text;
cmd.Parameters["@PlayerTypeID"].Value = txt3.Text;
cmd.Parameters["@PlayerTypeID"].Value = txt5.Text;
cmd.Parameters["@DateYear"].Value = cbmYear.SelectedItem;
cmd.Parameters["@DateMonth"].Value = cmbMonth.SelectedItem;
cmd.Parameters["@FXR"].Value = txt0.Text;
cmd.Parameters["@FXR"].Value = txt3.Text;
cmd.Parameters["@FXR"].Value = txt5.Text;
cmd.Parameters["@FXR"].Value = txt6.Text;
cmd.Parameters["@FXR"].Value = txt9.Text;
cmd.Parameters["@FXR"].Value = txt55.Text;
cmd.Parameters["@FXR"].Value = txt61.Text;
cmd.Parameters["@FXR"].Value = txt76.Text;
cmd.Parameters["@FXR"].Value = txt77.Text;
cmd.Parameters["@FXR"].Value = txt81.Text;
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 I have a Asp.net C# site(A) in which there is 3 Iframes Header ,body and footer.........
In header there is a droupdown which is filled by database ,which contain links to another sites(B).now when user click and sellect droupdown the site(B) is open in the body Iframe of site(A).
Now when i open this site(B) by typing the address in the browser,then it will work fine and all the ajax control work.But when this site(B) open in the body frame of my site(A) then AJAX control stop working and evertime whole frame get refreshed......WHAT TO DO as i have to open different sites in my one site as per the selection,Ajax is not working.
modified on Wednesday, October 15, 2008 1:44 AM
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Post the question on ASP.NET Fourm
cheers,
Abhijit
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